我是这样做的:

    Uri queryUri = MediaStore.Files.getContentUri("external");
    String columnData = MediaStore.Files.FileColumns.DATA;
    String columnSize = MediaStore.Files.FileColumns.SIZE;

    String[] projectionData = {MediaStore.Files.FileColumns.DATA};


    String name = null;
    String size = null;

    Cursor cursor = getContentResolver().query(contentURI, null, null, null, null);
    if ((cursor != null)&&(cursor.getCount()>0)) {
        int nameIndex = cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME);
        int sizeIndex = cursor.getColumnIndex(OpenableColumns.SIZE);

        cursor.moveToFirst();

        name = cursor.getString(nameIndex);
        size = cursor.getString(sizeIndex);

        cursor.close();
    }

    if ((name!=null)&&(size!=null)){
        String selectionNS = columnData + " LIKE '%" + name + "' AND " +columnSize + "='" + size +"'";

        Cursor cursorLike = getContentResolver().query(queryUri, projectionData, selectionNS, null, null);

        if ((cursorLike != null)&&(cursorLike.getCount()>0)) {
            cursorLike.moveToFirst();
            int indexData = cursorLike.getColumnIndex(columnData);
            if (cursorLike.getString(indexData) != null) {
                result = cursorLike.getString(indexData);
            }
            cursorLike.close();
        }
    }

    return result;

在这里，我将向您展示如何创建一个BROWSE按钮，当您单击它时，它将打开SD卡，您将选择一个文件，结果您将获得所选文件的文件名和文件路径:

一个你要按的按钮

browse.setOnClickListener(new OnClickListener()
{
    public void onClick(View v)
    {
        Intent intent = new Intent();
        intent.setAction(Intent.ACTION_PICK);
        Uri startDir = Uri.fromFile(new File("/sdcard"));
        startActivityForResult(intent, PICK_REQUEST_CODE);
    }
});

获取结果文件名和文件路径的函数

protected void onActivityResult(int requestCode, int resultCode, Intent intent)
{
    if (requestCode == PICK_REQUEST_CODE)
    {
        if (resultCode == RESULT_OK)
        {
            Uri uri = intent.getData();

            if (uri.getScheme().toString().compareTo("content")==0)
            {
                Cursor cursor =getContentResolver().query(uri, null, null, null, null);
                if (cursor.moveToFirst())
                {
                    int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);//Instead of "MediaStore.Images.Media.DATA" can be used "_data"
                    Uri filePathUri = Uri.parse(cursor.getString(column_index));
                    String file_name = filePathUri.getLastPathSegment().toString();
                    String file_path=filePathUri.getPath();
                    Toast.makeText(this,"File Name & PATH are:"+file_name+"\n"+file_path, Toast.LENGTH_LONG).show();
                }
            }
        }
    }
}

这个解决方案适用于所有情况:

在某些情况下，从URL中获取路径太难了。那你为什么需要路径?把文件复制到其他地方?你不需要路径。

public void SavePhotoUri (Uri imageuri, String Filename){

    File FilePath = context.getDir(Environment.DIRECTORY_PICTURES,Context.MODE_PRIVATE);
    try {
        Bitmap selectedImage = MediaStore.Images.Media.getBitmap(context.getContentResolver(), imageuri);
        String destinationImagePath = FilePath + "/" + Filename;
        FileOutputStream destination = new FileOutputStream(destinationImagePath);
        selectedImage.compress(Bitmap.CompressFormat.JPEG, 100, destination);
        destination.close();
    }
    catch (Exception e) {
        Log.e("error", e.toString());
    }
}

这是我的例子获取文件名，从URI file://…内容://... .这是为我工作，不仅与Android MediaStore，而且与第三方应用程序，如EzExplorer。

public static String getFileNameByUri(Context context, Uri uri)
{
    String fileName="unknown";//default fileName
    Uri filePathUri = uri;
    if (uri.getScheme().toString().compareTo("content")==0)
    {      
        Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
        if (cursor.moveToFirst())
        {
            int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);//Instead of "MediaStore.Images.Media.DATA" can be used "_data"
            filePathUri = Uri.parse(cursor.getString(column_index));
            fileName = filePathUri.getLastPathSegment().toString();
        }
    }
    else if (uri.getScheme().compareTo("file")==0)
    {
        fileName = filePathUri.getLastPathSegment().toString();
    }
    else
    {
        fileName = fileName+"_"+filePathUri.getLastPathSegment();
    }
    return fileName;
}

对于那些搬到奇巧后有问题的人:

这将从MediaProvider, DownloadsProvider和ExternalStorageProvider获取文件路径，同时回落到非官方的ContentProvider方法https://stackoverflow.com/a/20559175/690777

我用一行代码做到这一点:

val bitmap = MediaStore.Images.Media。getBitmap (contentResolver uri)

在onActivityResult中看起来是这样的:

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    if (resultCode == Activity.RESULT_OK && requestCode == REQUEST_CODE_IMAGE_PICKER ) {
        data?.data?.let { imgUri: Uri ->
            val bitmap = MediaStore.Images.Media.getBitmap(contentResolver, imgUri)
        }
    }
}