我有一个onActivityResult从一个mediastore图像选择返回,我可以获得一个图像使用以下URI:

Uri selectedImage = data.getData();

将this转换为字符串会得到:

content://media/external/images/media/47

或路径给出:

/external/images/media/47

然而,我似乎找不到一种方法将其转换为绝对路径,因为我想将图像加载到位图中,而不必复制到某个地方。我知道这可以使用URI和内容解析器来完成,但这似乎在重新启动手机时中断,我猜MediaStore在重新启动之间没有保持其编号相同。


当前回答

这是我的例子获取文件名,从URI file://…内容://... .这是为我工作,不仅与Android MediaStore,而且与第三方应用程序,如EzExplorer。

public static String getFileNameByUri(Context context, Uri uri)
{
    String fileName="unknown";//default fileName
    Uri filePathUri = uri;
    if (uri.getScheme().toString().compareTo("content")==0)
    {      
        Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
        if (cursor.moveToFirst())
        {
            int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);//Instead of "MediaStore.Images.Media.DATA" can be used "_data"
            filePathUri = Uri.parse(cursor.getString(column_index));
            fileName = filePathUri.getLastPathSegment().toString();
        }
    }
    else if (uri.getScheme().compareTo("file")==0)
    {
        fileName = filePathUri.getLastPathSegment().toString();
    }
    else
    {
        fileName = fileName+"_"+filePathUri.getLastPathSegment();
    }
    return fileName;
}

其他回答

这些答案在所有情况下都不适用。我必须直接去谷歌的文档https://developer.android.com/guide/topics/providers/document-provider.html关于这个主题,并发现这个有用的方法:

private Bitmap getBitmapFromUri(Uri uri) throws IOException {
    ParcelFileDescriptor parcelFileDescriptor =
    getContentResolver().openFileDescriptor(uri, "r");
    FileDescriptor fileDescriptor = parcelFileDescriptor.getFileDescriptor();
    Bitmap image = BitmapFactory.decodeFileDescriptor(fileDescriptor);
    parcelFileDescriptor.close();
    return image;
}

您可以使用此位图在图像视图中显示它。

对奥利奥

Uri uri = data.getData(); 
File file = new File(uri.getPath());//create path from uri
final String[] split = file.getPath().split(":");//split the path.
filePath = split[1];//assign it to a string(your choice).

对于Oreo以下的所有版本,我已经做了这个方法,从uri中获取真实路径

 @SuppressLint("NewApi")
    public static String getFilePath(Context context, Uri uri) throws URISyntaxException {
        String selection = null;
        String[] selectionArgs = null;
        // Uri is different in versions after KITKAT (Android 4.4), we need to
        if (Build.VERSION.SDK_INT >= 19 && DocumentsContract.isDocumentUri(context.getApplicationContext(), uri)) {
            if (isExternalStorageDocument(uri)) {
                final String docId = DocumentsContract.getDocumentId(uri);
                final String[] split = docId.split(":");
                return Environment.getExternalStorageDirectory() + "/" + split[1];
            } else if (isDownloadsDocument(uri)) {
                final String id = DocumentsContract.getDocumentId(uri);
                uri = ContentUris.withAppendedId(
                        Uri.parse("content://downloads/public_downloads"), Long.valueOf(id));
            } else if (isMediaDocument(uri)) {
                final String docId = DocumentsContract.getDocumentId(uri);
                final String[] split = docId.split(":");
                final String type = split[0];
                if ("image".equals(type)) {
                    uri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI;
                } else if ("video".equals(type)) {
                    uri = MediaStore.Video.Media.EXTERNAL_CONTENT_URI;
                } else if ("audio".equals(type)) {
                    uri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI;
                }
                selection = "_id=?";
                selectionArgs = new String[]{
                        split[1]
                };
            }
        }
        if ("content".equalsIgnoreCase(uri.getScheme())) {


          if (isGooglePhotosUri(uri)) {
              return uri.getLastPathSegment();
           }

            String[] projection = {
                    MediaStore.Images.Media.DATA
            };
            Cursor cursor = null;
            try {
                cursor = context.getContentResolver()
                        .query(uri, projection, selection, selectionArgs, null);
                int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
                if (cursor.moveToFirst()) {
                    return cursor.getString(column_index);
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
        } else if ("file".equalsIgnoreCase(uri.getScheme())) {
            return uri.getPath();
        }
        return null;
    }

    public static boolean isExternalStorageDocument(Uri uri) {
        return "com.android.externalstorage.documents".equals(uri.getAuthority());
    }

    public static boolean isDownloadsDocument(Uri uri) {
        return "com.android.providers.downloads.documents".equals(uri.getAuthority());
    }

    public static boolean isMediaDocument(Uri uri) {
        return "com.android.providers.media.documents".equals(uri.getAuthority());
    }

  public static boolean isGooglePhotosUri(Uri uri) {
    return "com.google.android.apps.photos.content".equals(uri.getAuthority());
}

这是我的例子获取文件名,从URI file://…内容://... .这是为我工作,不仅与Android MediaStore,而且与第三方应用程序,如EzExplorer。

public static String getFileNameByUri(Context context, Uri uri)
{
    String fileName="unknown";//default fileName
    Uri filePathUri = uri;
    if (uri.getScheme().toString().compareTo("content")==0)
    {      
        Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
        if (cursor.moveToFirst())
        {
            int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);//Instead of "MediaStore.Images.Media.DATA" can be used "_data"
            filePathUri = Uri.parse(cursor.getString(column_index));
            fileName = filePathUri.getLastPathSegment().toString();
        }
    }
    else if (uri.getScheme().compareTo("file")==0)
    {
        fileName = filePathUri.getLastPathSegment().toString();
    }
    else
    {
        fileName = fileName+"_"+filePathUri.getLastPathSegment();
    }
    return fileName;
}

只是对第一个答案进行了简单的更新:mActivity.managedQuery()现在已弃用。我已经用新方法更新了代码。

private String getRealPathFromURI(Uri contentUri) {
    String[] proj = { MediaStore.Images.Media.DATA };
    CursorLoader loader = new CursorLoader(mContext, contentUri, proj, null, null, null);
    Cursor cursor = loader.loadInBackground();
    int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
    cursor.moveToFirst();
    String result = cursor.getString(column_index);
    cursor.close();
    return result;
}

Android开发源码

我用一行代码做到这一点:

val bitmap = MediaStore.Images.Media。getBitmap (contentResolver uri)

在onActivityResult中看起来是这样的:

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    if (resultCode == Activity.RESULT_OK && requestCode == REQUEST_CODE_IMAGE_PICKER ) {
        data?.data?.let { imgUri: Uri ->
            val bitmap = MediaStore.Images.Media.getBitmap(contentResolver, imgUri)
        }
    }
}