我想写一个这样的查询:
SELECT o.OrderId, MAX(o.NegotiatedPrice, o.SuggestedPrice)
FROM Order o
但这不是MAX函数的工作原理,对吧?它是一个聚合函数,因此它需要一个参数,然后返回所有行的MAX。
有人知道我的方法吗?
我想写一个这样的查询:
SELECT o.OrderId, MAX(o.NegotiatedPrice, o.SuggestedPrice)
FROM Order o
但这不是MAX函数的工作原理,对吧?它是一个聚合函数,因此它需要一个参数,然后返回所有行的MAX。
有人知道我的方法吗?
当前回答
在MemSQL中执行以下操作:
-- DROP FUNCTION IF EXISTS InlineMax;
DELIMITER //
CREATE FUNCTION InlineMax(val1 INT, val2 INT) RETURNS INT AS
DECLARE
val3 INT = 0;
BEGIN
IF val1 > val2 THEN
RETURN val1;
ELSE
RETURN val2;
END IF;
END //
DELIMITER ;
SELECT InlineMax(1,2) as test;
其他回答
其实很简单:
CREATE FUNCTION InlineMax
(
@p1 sql_variant,
@p2 sql_variant
) RETURNS sql_variant
AS
BEGIN
RETURN CASE
WHEN @p1 IS NULL AND @p2 IS NOT NULL THEN @p2
WHEN @p2 IS NULL AND @p1 IS NOT NULL THEN @p1
WHEN @p1 > @p2 THEN @p1
ELSE @p2 END
END;
我可能不会这样做,因为它比前面提到的CASE结构效率更低——除非您为两个查询都有覆盖索引。不管怎样,对于类似的问题,这都是一个有用的技巧:
SELECT OrderId, MAX(Price) as Price FROM (
SELECT o.OrderId, o.NegotiatedPrice as Price FROM Order o
UNION ALL
SELECT o.OrderId, o.SuggestedPrice as Price FROM Order o
) as A
GROUP BY OrderId
以下是@Scott Langham用简单的NULL处理给出的答案:
SELECT
o.OrderId,
CASE WHEN (o.NegotiatedPrice > o.SuggestedPrice OR o.SuggestedPrice IS NULL)
THEN o.NegotiatedPrice
ELSE o.SuggestedPrice
END As MaxPrice
FROM Order o
CREATE FUNCTION [dbo].[fnMax] (@p1 INT, @p2 INT)
RETURNS INT
AS BEGIN
DECLARE @Result INT
SET @p2 = COALESCE(@p2, @p1)
SELECT
@Result = (
SELECT
CASE WHEN @p1 > @p2 THEN @p1
ELSE @p2
END
)
RETURN @Result
END
SELECT o.OrderID
CASE WHEN o.NegotiatedPrice > o.SuggestedPrice THEN
o.NegotiatedPrice
ELSE
o.SuggestedPrice
END AS Price