这意味着什么?我该如何解决?

zsh compinit: insecure directories, run compaudit for list.
Ignore insecure directories and continue [y] or abort compinit [n]?

运行compaudit将返回如下结果:

There are insecure directories:
/usr/local/share/zsh/site-functions

当前回答

在莫哈韦沙漠,这招奏效了: Sudo chmod go-w /usr/local/share

(2022年更新)

如果使用ZSH补全,你应该使用chmod -R go-w "$(brew——prefix)/share"

其他回答

大多数答案都提供了解决方案,但没有提到为什么会出现这种警告。以下是ZSH公司的一段摘录:

For security reasons compinit also checks if the completion system would use files not owned by root or by the current user, or files in directories that are world- or group-writable or that are not owned by root or by the current user. If such files or directories are found, compinit will ask if the completion system should really be used. To avoid these tests and make all files found be used without asking, use the option -u, and to make compinit silently ignore all insecure files and directories use the option -i. This security check is skipped entirely when the -C option is given.

因此,解决方案意味着解决以下一个(或所有)问题:

将当前用户设置为所有目录/子目录/文件的所有者,原因如下: compaudit | xargs chown -R "$(whoami)" 删除组/others文件的写权限,原因如下: Compaudit | xargs chmod go-w

另一种方法是使用跳过这些检查

compinit -u

但我并不建议这样做,因为把问题藏在地毯下只能在短期内解决问题。

在M1上工作过

ProductName:    macOS
ProductVersion: 11.1
BuildVersion:   20C69

% compaudit
/opt/homebrew/share

将组权限从775更改为755

% sudo chmod 755 /opt/homebrew/share

drwxr-xr-x   33 xenea  admin   1056 Feb  2 01:28 share

在我的mac OS Catalina上运行这个命令是有效的:

Compaudit | xargs chmod g-w,o-w

我通过做来解决它

sudo chown -R root:staff /usr/local/share/zsh

在我的例子中,share/中的其他目录也分配了“staff”组

我得到这个问题在过去的5个月尝试了一些事情,但没有工作。最后帮助我的是这个。获取不安全目录的列表,然后按照下面的描述设置所有这些目录的chmod。

CLI# compaudit
There are insecure directories:
/usr/local/share/zsh
CLI# sudo chmod -R 755 /usr/local/share/zsh
Password: