这意味着什么?我该如何解决?
zsh compinit: insecure directories, run compaudit for list.
Ignore insecure directories and continue [y] or abort compinit [n]?
运行compaudit将返回如下结果:
There are insecure directories:
/usr/local/share/zsh/site-functions
这意味着什么?我该如何解决?
zsh compinit: insecure directories, run compaudit for list.
Ignore insecure directories and continue [y] or abort compinit [n]?
运行compaudit将返回如下结果:
There are insecure directories:
/usr/local/share/zsh/site-functions
当前回答
这是我在https://github.com/zsh-users/zsh-completions/issues/433#issuecomment-600582607上唯一有用的东西。感谢https://github.com/malaquiasdev !
$ cd /usr/local/share/
$ sudo chmod -R 755 zsh
$ sudo chown -R root:staff zsh
其他回答
在macOS Sierra上,你需要运行: sudo chown -R $(whoami):staff /usr/local
MAC OS X解决方案:
$ sudo chmod -R 755 /usr/local/share/zsh
$ sudo chown -R root:staff /usr/local/share/zsh
还有“user:staff = OSX上的默认根用户”。
接受的答案在macOs Sierra(10.12.1)上不适用。必须从/usr/local递归吗
cd /usr/local
sudo chown -R <your-username>:<your-group-name> *
注意:你可以用whoami获取你的用户名,用id -g获取你的组
在莫哈韦沙漠,这招奏效了: Sudo chmod go-w /usr/local/share
(2022年更新)
如果使用ZSH补全,你应该使用chmod -R go-w "$(brew——prefix)/share"
这两条线路已经为我固定了。
sudo chown -R _user_:root /usr/local/share/zsh
sudo chown -R _user_:root /usr/local/share/zsh/*