改编为随机类扩展:

public static class RandomExtensions
{   
    public static T NextEnum<T>(this Random random)
    {
        var values = Enum.GetValues(typeof(T));
        return (T)values.GetValue(random.Next(values.Length));
    }
}

用法示例:

var random = new Random();
var myEnumRandom = random.NextEnum<MyEnum>();

下面是一个使用LINQ的扩展方法的替代版本。

using System;
using System.Linq;

public static class EnumExtensions
{
    public static Enum GetRandomEnumValue(this Type t)
    {
        return Enum.GetValues(t)          // get values from Type provided
            .OfType<Enum>()               // casts to Enum
            .OrderBy(e => Guid.NewGuid()) // mess with order of results
            .FirstOrDefault();            // take first item in result
    }
}

public static class Program
{
    public enum SomeEnum
    {
        One = 1,
        Two = 2,
        Three = 3,
        Four = 4
    }

    public static void Main()
    {
        for(int i=0; i < 10; i++)
        {
            Console.WriteLine(typeof(SomeEnum).GetRandomEnumValue());
        }
    }           
}

两个 一个 四个 四个 四个 三个 两个 四个 一个 三个

你可以这样做:

var rnd = new Random();
return (MyEnum) rnd.Next(Enum.GetNames(typeof(MyEnum)).Length);

不需要存储数组

你也可以强制转换一个随机值:

using System;

enum Test {
  Value1,
  Value2,
  Value3
}

class Program {
  public static void Main (string[] args) {
    var max = Enum.GetValues(typeof(Test)).Length;
    var value = (Test)new Random().Next(0, max - 1);
    Console.WriteLine(value);
  }
}

但你应该用一个更好的随机器就像我这个库里的那个。

改编为随机类扩展:

public static class RandomExtensions
{   
    public static T NextEnum<T>(this Random random)
    {
        var values = Enum.GetValues(typeof(T));
        return (T)values.GetValue(random.Next(values.Length));
    }
}

用法示例:

var random = new Random();
var myEnumRandom = random.NextEnum<MyEnum>();

很多答案都很老了，而且——如果我说错了请纠正我——似乎只涉及一些粗略的概念，比如类型擦除和动态类型转换。然而，正如用户Yarek T指出的那样，Enum的通用重载不需要这样做。getvalue:

static Random random = new Random();

// Somewhat unintuitively, we need to constrain the type parameter to
// both struct *and* Enum - struct is required b/c the type can't be
// nullable, and Enum is required b/c GetValues expects an Enum type.
// You'd think that Enum itself would satisfy the non-nullable
// constraint, but alas, me compiler tells me otherwise - perhaps
// someone more knowledgeable can explain why this is in a comment?
static TEnum RandomEnumValue<TEnum>() where TEnum : struct, Enum
{
    TEnum[] vals = Enum.GetValues<TEnum>();
    return vals[random.Next(vals.Length)];
}

或者，像borja garcia的答案一样，我们甚至可以把它写成随机类的扩展

public static class RandomExtensions
{   
    public static TEnum NextEnumValue<TEnum>(this Random random)
        where TEnum : struct, Enum
    {
        TEnum[] vals = Enum.GetValues<TEnum>();
        return vals[random.Next(vals.Length)];
    }
}

我们可以从mafu的答案中进行相同的测试:

Random random = new Random();
for (int i = 0; i < 10; i++) {
    var day = random.NextEnumValue<System.DayOfWeek>();
    Console.WriteLine(day.ToString());
}

潜在产出:

Thursday
Saturday
Sunday
Sunday
Sunday
Saturday
Wednesday
Monday
Wednesday
Thursday