我不知道这样做的函数,有人知道吗?
当前回答
app.get('*',function(req,res){
res.redirect('/login');
});
其他回答
我认为你应该首先定义你所有的路线,然后作为最后的路线添加
//The 404 Route (ALWAYS Keep this as the last route)
app.get('*', function(req, res){
res.status(404).send('what???');
});
一个示例应用程序的工作:
app.js:
var express = require('express'),
app = express.createServer();
app.use(express.static(__dirname + '/public'));
app.get('/', function(req, res){
res.send('hello world');
});
//The 404 Route (ALWAYS Keep this as the last route)
app.get('*', function(req, res){
res.send('what???', 404);
});
app.listen(3000, '127.0.0.1');
alfred@alfred-laptop:~/node/stackoverflow/6528876$ mkdir public
alfred@alfred-laptop:~/node/stackoverflow/6528876$ find .
alfred@alfred-laptop:~/node/stackoverflow/6528876$ echo "I don't find a function for that... Anyone knows?" > public/README.txt
alfred@alfred-laptop:~/node/stackoverflow/6528876$ cat public/README.txt
.
./app.js
./public
./public/README.txt
alfred@alfred-laptop:~/node/stackoverflow/6528876$ curl http://localhost:3000/
hello world
alfred@alfred-laptop:~/node/stackoverflow/6528876$ curl http://localhost:3000/README.txt
I don't find a function for that... Anyone knows?
Express-error-handler允许您为错误指定自定义模板、静态页面或错误处理程序。它还做了其他有用的错误处理,每个应用程序都应该实现,比如防止4xx错误DOS攻击,以及在不可恢复错误时优雅地关闭。以下是你如何做到你所要求的:
var errorHandler = require('express-error-handler'),
handler = errorHandler({
static: {
'404': 'path/to/static/404.html'
}
});
// After all your routes...
// Pass a 404 into next(err)
app.use( errorHandler.httpError(404) );
// Handle all unhandled errors:
app.use( handler );
或者对于自定义处理程序:
handler = errorHandler({
handlers: {
'404': function err404() {
// do some custom thing here...
}
}
});
或者对于自定义视图:
handler = errorHandler({
views: {
'404': '404.jade'
}
});
发送到自定义页面:
app.get('*', function(req, res){
if (req.accepts('html')) {
res.send('404', '<script>location.href = "/the-404-page.html";</script>');
return;
}
});
如果你想从你的函数(路由)重定向到错误页面,那么做以下事情-
Add general error messages code in your app.js - app.use(function(err, req, res, next) { // set locals, only providing error in development res.locals.message = err.message res.locals.error = req.app.get('env') === 'development' ? err : {} // render the error page // you can also serve different error pages // for example sake, I am just responding with simple error messages res.status(err.status || 500) if(err.status === 403){ return res.send('Action forbidden!'); } if(err.status === 404){ return res.send('Page not found!'); } // when status is 500, error handler if(err.status === 500) { return res.send('Server error occured!'); } res.render('error') }) In your function, instead of using a error-page redirect you can use set the error status first and then use next() for the code flow to go through above code - if(FOUND){ ... }else{ // redirecting to general error page // any error code can be used (provided you have handled its error response) res.status(404) // calling next() will make the control to go call the step 1. error code // it will return the error response according to the error code given (provided you have handled its error response) next() }
app.get('*',function(req,res){
res.redirect('/login');
});
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