我怎么能在多行分割字符串,如下面?

var text:String = "This is some text
                   over multiple lines"

当前回答

下面是一个简单的实现(Swift 5.4+),使用resultBuilder来清理语法!

@resultBuilder
public struct StringBuilder {
    public static func buildBlock(_ components: String...) -> String {
        return components.reduce("", +)
    }
}

public extension String {
    init(@StringBuilder _ builder: () -> String) {
        self.init(builder())
    }
}

用法:

String {
    "Hello "
    "world!"
} 
// "Hello world!"

其他回答

Swift 4通过提供多行字符串文字支持解决了这个问题。要开始字符串字面量,添加三个双引号(" " " ")并按回车键,按回车键后开始写带有任何变量的字符串,换行符和双引号,就像你在记事本或任何文本编辑器中写的那样。要结束多行字符串文字再次写入(" " ")在新行。

参见下面的例子

     let multiLineStringLiteral = """
    This is one of the best feature add in Swift 4
    It let’s you write “Double Quotes” without any escaping
    and new lines without need of “\n”
    """

print(multiLineStringLiteral)

下面的例子描述了一个多行连续,使用圆括号作为一个简单的解决方法,以解决Xcode 6.2 Beta版本的Swift错误,它抱怨表达式太复杂,无法在合理的时间内解析,并考虑将其分解为更小的片段:

    .
    .
    .
    return String(format:"\n" +
                    ("    part1:    %d\n"    +
                     "    part2:    %d\n"    +
                     "    part3:  \"%@\"\n"  +
                     "    part4:  \"%@\"\n"  +
                     "    part5:  \"%@\"\n"  +
                     "    part6:  \"%@\"\n") +
                    ("    part7:  \"%@\"\n"  +
                     "    part8:  \"%@\"\n"  +
                     "    part9:  \"%@\"\n"  +
                     "    part10: \"%@\"\n"  +
                     "    part12: \"%@\"\n") +
                     "    part13:  %f\n"     +
                     "    part14:  %f\n\n",
                    part1, part2, part3, part4, part5, part6, part7, part8, 
                    part9, part10, part11, part12, part13, part14)
    .
    .
    .

我在String上使用了一个扩展来实现多行字符串,同时避免编译器挂起的错误。它还允许您指定分隔符,以便您可以像使用Python的join函数一样使用它

extension String {
    init(sep:String, _ lines:String...){
        self = ""
        for (idx, item) in lines.enumerated() {
            self += "\(item)"
            if idx < lines.count-1 {
                self += sep
            }
        }
    }

    init(_ lines:String...){
        self = ""
        for (idx, item) in lines.enumerated() {
            self += "\(item)"
            if idx < lines.count-1 {
                self += "\n"
            }
        }
    }
}



print(
    String(
        "Hello",
        "World!"
    )
)
"Hello
World!"

print(
    String(sep:", ",
        "Hello",
        "World!"
    )
)
"Hello, World!"

样本

var yourString = "first line \n second line \n third line"

以防您发现+运算符不合适

正如litso所指出的,在一个表达式中重复使用+-操作符会导致Xcode Beta挂起(刚刚用Xcode 6 Beta 5检查过):Xcode 6 Beta无法编译

目前,多行字符串的另一种替代方法是使用一个字符串数组,并将其压缩为+:

var text = ["This is some text ",
            "over multiple lines"].reduce("", +)

或者,可以更简单地使用join:

var text = "".join(["This is some text ",
                    "over multiple lines"])