另一种方法是，如果你想使用带有预定义文本的字符串变量，

var textFieldData:String = "John"
myTextField.text = NSString(format: "Hello User, \n %@",textFieldData) as String
myTextField.numberOfLines = 0

Swift 4支持多行字符串字面值。除了换行符，它们还可以包含未转义的引号。

var text = """
    This is some text
    over multiple lines
    """

旧版本的Swift不允许你在多行上有一个字面值，但你可以在多行上添加字面值:

var text = "This is some text\n"
         + "over multiple lines\n"

正如litso所指出的，在一个表达式中重复使用+-操作符会导致Xcode Beta挂起(刚刚用Xcode 6 Beta 5检查过):Xcode 6 Beta无法编译

目前，多行字符串的另一种替代方法是使用一个字符串数组，并将其压缩为+:

var text = ["This is some text ",
            "over multiple lines"].reduce("", +)

或者，可以更简单地使用join:

var text = "".join(["This is some text ",
                    "over multiple lines"])

我写了一个小扩展。

extension String {

    init(swiftLintMultiline strings: String...) {
        self = strings.reduce("", +)
    }
}

你可以这样使用它:

String(swiftLintMultiline:
    "Lorem ipsum dolor sit amet, consectetur adipiscing",
    "elit. Ut vulputate ultrices volutpat. Vivamus eget",
    "nunc maximus, tempus neque vel, suscipit velit.",
    "Quisque quam quam, malesuada et accumsan sodales,",
    "rutrum non odio. Praesent a est porta, hendrerit",
    "lectus scelerisque, pharetra magna. Proin id nulla",
    "pharetra, lobortis ipsum sit amet, vehicula elit. Nulla",
    "dapibus ipsum ipsum, sit amet congue arcu efficitur ac. Nunc imperdi"
)

样本

var yourString = "first line \n second line \n third line"

以防您发现+运算符不合适

下面是一个代码片段，用n个字符分隔字符串:

//: A UIKit based Playground for presenting user interface

import UIKit
import PlaygroundSupport

class MyViewController : UIViewController {
    override func loadView() {

        let str = String(charsPerLine: 5, "Hello World!")
        print(str) // "Hello\n Worl\nd!\n"

    }
}

extension String {

    init(charsPerLine:Int, _ str:String){

        self = ""
        var idx = 0
        for char in str {
            self += "\(char)"
            idx = idx + 1
            if idx == charsPerLine {
                self += "\n"
                idx = 0
            }
        }

    }
}