我遇到了绑定到密码盒的问题。这似乎是一个安全风险,但我正在使用MVVM模式,所以我希望绕过这个。我在这里发现了一些有趣的代码(有人使用过这个或类似的代码吗?)

http://www.wpftutorial.net/PasswordBox.html

从技术上讲,它看起来很棒,但我不确定如何检索密码。

我基本上有属性在我的LoginViewModel用户名和密码。用户名是好的,正在工作,因为它是一个文本框。

我使用上面的代码,并输入这个

<PasswordBox ff:PasswordHelper.Attach="True"
    ff:PasswordHelper.Password="{Binding Path=Password}" Width="130"/>

当我有PasswordBox作为一个文本框和绑定路径=密码,然后在我的LoginViewModel属性更新。

我的代码非常简单,基本上我有一个命令为我的按钮。当我按下它CanLogin被调用,如果它返回真,它调用Login。 你可以看到,我检查了我的用户名属性,这很好。

在登录我发送到我的服务的用户名和密码,用户名包含数据从我的视图,但密码是空|空

private DelegateCommand loginCommand;

public string Username { get; set; }
public string Password { get; set; }


public ICommand LoginCommand
{
    get
    {
        if (loginCommand == null)
        {
            loginCommand = new DelegateCommand(
                Login, CanLogin );
        }
        return loginCommand;
    }
}

private bool CanLogin()
{
    return !string.IsNullOrEmpty(Username);
}

private void Login()
{
    bool result = securityService.IsValidLogin(Username, Password);

    if (result) { }
    else { }
}

这就是我正在做的

<TextBox Text="{Binding Path=Username, UpdateSourceTrigger=PropertyChanged}"
         MinWidth="180" />

<PasswordBox ff:PasswordHelper.Attach="True" 
             ff:PasswordHelper.Password="{Binding Path=Password}" Width="130"/>

我有我的文本框,这是没有问题的,但在我的ViewModel密码是空的。

是我做错了什么还是漏了一步?

我放了一个断点,果然代码进入静态助手类,但它从不更新我的ViewModel中的密码。


当前回答

我想我应该把我的解决方案放在一起,因为这是一个很常见的问题……拥有大量的选择总是一件好事。

I simply wrapped a PasswordBox in a UserControl and implemented a DependencyProperty to be able to bind. I'm doing everything I can to avoid storing any clear text in the memory, so everything is done through a SecureString and the PasswordBox.Password property. During the foreach loop, each character does get exposed, but it's very brief. Honestly, if you're worried about your WPF application to be compromised from this brief exposure, you've got bigger security issues that should be handled.

这样做的好处是你没有违反任何MVVM规则,即使是“最纯粹的”规则,因为这是一个UserControl,所以它允许有代码隐藏。当你使用它时,你可以在View和ViewModel之间进行纯通信,而你的VideModel不知道View的任何部分或密码的来源。只要确保你在ViewModel中绑定到SecureString。

BindablePasswordBox.xaml

<UserControl x:Class="BK.WPF.CustomControls.BindanblePasswordBox"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" 
             xmlns:d="http://schemas.microsoft.com/expression/blend/2008" 
             mc:Ignorable="d" d:DesignHeight="22" d:DesignWidth="150">
    <PasswordBox x:Name="PswdBox"/>
</UserControl>

BindablePasswordBox.xaml.cs(版本1 -不支持双向绑定)

using System.ComponentModel;
using System.Security;
using System.Windows;
using System.Windows.Controls;

namespace BK.WPF.CustomControls
{
    public partial class BindanblePasswordBox : UserControl
    {
        public static readonly DependencyProperty PasswordProperty =
            DependencyProperty.Register("Password", typeof(SecureString), typeof(BindanblePasswordBox));

        public SecureString Password
        {
            get { return (SecureString)GetValue(PasswordProperty); }
            set { SetValue(PasswordProperty, value); }
        }

        public BindanblePasswordBox()
        {
            InitializeComponent();
            PswdBox.PasswordChanged += PswdBox_PasswordChanged;
        }

        private void PswdBox_PasswordChanged(object sender, RoutedEventArgs e)
        {
            var secure = new SecureString();
            foreach (var c in PswdBox.Password)
            {
                secure.AppendChar(c);
            }
            Password = secure;
        }
    }
}

版本1的用法:

<local:BindanblePasswordBox Width="150" HorizontalAlignment="Center"
                            VerticalAlignment="Center"
                            Password="{Binding Password, Mode=OneWayToSource}"/>

BindablePasswordBox.xaml.cs(版本2 -支持双向绑定)

public partial class BindablePasswordBox : UserControl
{
    public static readonly DependencyProperty PasswordProperty =
        DependencyProperty.Register("Password", typeof(SecureString), typeof(BindablePasswordBox),
        new PropertyMetadata(PasswordChanged));

    public SecureString Password
    {
        get { return (SecureString)GetValue(PasswordProperty); }
        set { SetValue(PasswordProperty, value); }
    }

    public BindablePasswordBox()
    {
        InitializeComponent();
        PswdBox.PasswordChanged += PswdBox_PasswordChanged;
    }

    private void PswdBox_PasswordChanged(object sender, RoutedEventArgs e)
    {
        var secure = new SecureString();
        foreach (var c in PswdBox.Password)
        {
            secure.AppendChar(c);
        }
        if (Password != secure)
        {
            Password = secure;
        }
    }

    private static void PasswordChanged(DependencyObject d, DependencyPropertyChangedEventArgs e)
    {
        var pswdBox = d as BindablePasswordBox;
        if (pswdBox != null && e.NewValue != e.OldValue)
        {
            var newValue = e.NewValue as SecureString;
            if (newValue == null)
            {
                return;
            }

            var unmanagedString = IntPtr.Zero;
            string newString;
            try
            {
                unmanagedString = Marshal.SecureStringToGlobalAllocUnicode(newValue);
                newString = Marshal.PtrToStringUni(unmanagedString);
            }
            finally
            {
                Marshal.ZeroFreeGlobalAllocUnicode(unmanagedString);
            }

            var currentValue = pswdBox.PswdBox.Password;
            if (currentValue != newString)
            {
                pswdBox.PswdBox.Password = newString;
            }
        }
    }
}

版本2的用途:

<local:BindanblePasswordBox Width="150" HorizontalAlignment="Center"
                            VerticalAlignment="Center"
                            Password="{Binding Password, Mode=TwoWay}"/>

其他回答

对不起,你做错了。

人们应该在眼皮内侧纹以下安全指南: 永远不要在记忆中保存纯文本密码。

WPF/Silverlight PasswordBox不为Password属性公开DP的原因与安全有关。 如果WPF/Silverlight要为密码保留一个DP,那么就需要框架在内存中保持密码本身不加密。这被认为是一个相当麻烦的安全攻击载体。 PasswordBox使用加密内存(某种程度上),访问密码的唯一方法是通过CLR属性。

我建议访问密码框时。密码CLR属性,您将避免将它放在任何变量或作为任何属性的值。 在客户端机器RAM中以明文形式保存密码是一个安全禁忌。 所以去掉公共字符串Password {get;设置;你已经站在那里了。

访问PasswordBox时。密码,把它拿出来,尽快发到服务器上。 不要保留密码的值,也不要像对待任何其他客户端机器文本一样对待它。不要在记忆中保存清晰的文本密码。

我知道这打破了MVVM模式,但您不应该绑定到PasswordBox。密码附加DP,存储您的密码在ViewModel或任何其他类似的诡计。

如果你正在寻找一个过度架构的解决方案,这里有一个: 1. 使用一个方法创建IHavePassword接口,该方法返回密码明文。 2. 让你的UserControl实现一个IHavePassword接口。 3.注册UserControl实例到你的IoC实现IHavePassword接口。 4. 当服务器请求您的密码发生时,调用IoC实现IHavePassword,只会得到梦寐以求的密码。

这只是我的看法。

——贾斯汀

这个实现略有不同。通过绑定ViewModel中的属性将PasswordBox传递给View。它不使用任何命令参数。ViewModel对视图保持无知。 我有一个VB VS 2010项目,可以从SkyDrive下载。WPF MVVM PassWordBox Example.zip

我在WPF MVVM应用程序中使用PasswordBox的方式非常简单,对我来说工作得很好。

基本上你创建了一个公共只读属性,视图可以绑定到PasswordBox(实际控件):

Private _thePassWordBox As PasswordBox
Public ReadOnly Property ThePassWordBox As PasswordBox
    Get
        If IsNothing(_thePassWordBox) Then _thePassWordBox = New PasswordBox
        Return _thePassWordBox
    End Get
End Property

我使用了一个支持字段来完成属性的自我初始化。

然后从Xaml中绑定ContentControl或Control Container的内容:

 <ContentControl Grid.Column="1" Grid.Row="1" Height="23" Width="120" Content="{Binding Path=ThePassWordBox}" HorizontalAlignment="Center" VerticalAlignment="Center" />

从那里你可以完全控制密码盒。我还使用PasswordAccessor(只是一个字符串的函数)返回密码值时,做登录或任何其他你想要的密码。在这个例子中,我在通用用户对象模型中有一个公共属性。 例子:

Public Property PasswordAccessor() As Func(Of String)

在用户对象中,密码字符串属性是只读的,没有任何备份存储。它只是从PasswordBox返回Password。 例子:

Public ReadOnly Property PassWord As String
    Get
        Return If((PasswordAccessor Is Nothing), String.Empty, PasswordAccessor.Invoke())
    End Get
End Property

然后在ViewModel中,我确保Accessor被创建并设置为PasswordBox。密码属性:

Public Sub New()
    'Sets the Accessor for the Password Property
    SetPasswordAccessor(Function() ThePassWordBox.Password)
End Sub

Friend Sub SetPasswordAccessor(ByVal accessor As Func(Of String))
    If Not IsNothing(VMUser) Then VMUser.PasswordAccessor = accessor
End Sub

当我需要密码字符串说登录,我只是得到用户对象密码属性,真正调用函数抓取密码并返回它,然后实际的密码不存储在用户对象。 例如:将在ViewModel中

Private Function LogIn() as Boolean
    'Make call to your Authentication methods and or functions. I usally place that code in the Model
    Return AuthenticationManager.Login(New UserIdentity(User.UserName, User.Password)
End Function

That should do it. The ViewModel doesn't need any knowledge of the View's Controls. The View just binds to the Property in the ViewModel, not any different than the View Binding to an image or other resource. In this case that resource(Property) just happens to be a usercontrol. It allows for testing as the ViewModel creates and owns the Property and the Property is independent of the View. As for security I don't know how good this implementation is. But by using a Function the value is not stored in the Property itself just accessed by the Property.

<UserControl x:Class="Elections.Server.Handler.Views.LoginView" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:i="clr-namespace:System.Windows.Interactivity;assembly=System.Windows.Interactivity" xmlns:cal="http://www.caliburnproject.org" mc:Ignorable="d" Height="531" Width="1096"> <ContentControl> <ContentControl.Background> <ImageBrush/> </ContentControl.Background> <Grid > <Border BorderBrush="#FFABADB3" BorderThickness="1" HorizontalAlignment="Left" Height="23" Margin="900,100,0,0" VerticalAlignment="Top" Width="160"> <TextBox TextWrapping="Wrap"/> </Border> <Border BorderBrush="#FFABADB3" BorderThickness="1" HorizontalAlignment="Left" Height="23" Margin="900,150,0,0" VerticalAlignment="Top" Width="160"> <PasswordBox x:Name="PasswordBox"/> </Border> <Button Content="Login" HorizontalAlignment="Left" Margin="985,200,0,0" VerticalAlignment="Top" Width="75"> <i:Interaction.Triggers> <i:EventTrigger EventName="Click"> <cal:ActionMessage MethodName="Login"> <cal:Parameter Value="{Binding ElementName=PasswordBox}" /> </cal:ActionMessage> </i:EventTrigger> </i:Interaction.Triggers> </Button> </Grid> </ContentControl> </UserControl>

using System; using System.Windows; using System.Windows.Controls; using Caliburn.Micro; namespace Elections.Server.Handler.ViewModels { public class LoginViewModel : PropertyChangedBase { MainViewModel _mainViewModel; public void SetMain(MainViewModel mainViewModel) { _mainViewModel = mainViewModel; } public void Login(Object password) { var pass = (PasswordBox) password; MessageBox.Show(pass.Password); //_mainViewModel.ScreenView = _mainViewModel.ControlPanelView; //_mainViewModel.TitleWindow = "Panel de Control"; //HandlerBootstrapper.Title(_mainViewModel.TitleWindow); } } }

,简单!

我做过这样的事情:

XAML:

<PasswordBox x:Name="NewPassword" PasswordChanged="NewPassword_PasswordChanged"/>
<!--change tablenameViewSource: yours!-->
<Grid DataContext="{StaticResource tablenameViewSource}" Visibility="Hidden">
        <TextBox x:Name="Password" Text="{Binding password, Mode=TwoWay}"/>
</Grid>

C#:

private void NewPassword_PasswordChanged(object sender, RoutedEventArgs e)
    {
        try
        {
           //change tablenameDataTable: yours! and tablenameViewSource: yours!
           tablenameDataTable.Rows[tablenameViewSource.View.CurrentPosition]["password"] = NewPassword.Password;
        }
        catch
        {
            this.Password.Text = this.NewPassword.Password;
        }
    }

这对我很管用!

你可以使用这个XAML:

<PasswordBox>
    <i:Interaction.Triggers>
        <i:EventTrigger EventName="PasswordChanged">
            <i:InvokeCommandAction Command="{Binding RelativeSource={RelativeSource Mode=FindAncestor, AncestorType=PasswordBox}}" CommandParameter="{Binding ElementName=PasswordBox}"/>
        </i:EventTrigger>
    </i:Interaction.Triggers>
</PasswordBox>

该命令的执行方法:

private void ExecutePasswordChangedCommand(PasswordBox obj)
{ 
   if (obj != null)
     Password = obj.Password;
}

这需要将System.Windows.Interactivity程序集添加到项目中,并通过xmlns:i="clr-namespace:System.Windows.Interactivity;assembly=System.Windows.Interactivity"引用它。