许多应用程序都有文本,文本中是圆角矩形的web超链接,当我点击它们时,UIWebView就会打开。让我困惑的是,他们经常有自定义链接,例如,如果单词以#开头,它也是可点击的,应用程序通过打开另一个视图来响应。我该怎么做呢?是否可以用UILabel或者我需要UITextView或者其他什么?


当前回答

我遵循这个版本,

斯威夫特4:

import Foundation

class AELinkedClickableUILabel: UILabel {

    typealias YourCompletion = () -> Void

    var linkedRange: NSRange!
    var completion: YourCompletion?

    @objc func linkClicked(sender: UITapGestureRecognizer){

        if let completionBlock = completion {

            let textView = UITextView(frame: self.frame)
            textView.text = self.text
            textView.attributedText = self.attributedText
            let index = textView.layoutManager.characterIndex(for: sender.location(in: self),
                                                              in: textView.textContainer,
                                                              fractionOfDistanceBetweenInsertionPoints: nil)

            if linkedRange.lowerBound <= index && linkedRange.upperBound >= index {

                completionBlock()
            }
        }
    }

/**
 *  This method will be used to set an attributed text specifying the linked text with a
 *  handler when the link is clicked
 */
    public func setLinkedTextWithHandler(text:String, link: String, handler: @escaping ()->()) -> Bool {

        let attributextText = NSMutableAttributedString(string: text)
        let foundRange = attributextText.mutableString.range(of: link)

        if foundRange.location != NSNotFound {
            self.linkedRange = foundRange
            self.completion = handler
            attributextText.addAttribute(NSAttributedStringKey.link, value: text, range: foundRange)
            self.isUserInteractionEnabled = true
            self.addGestureRecognizer(UITapGestureRecognizer(target: self, action: #selector(linkClicked(sender:))))
            return true
        }
        return false
    }
}

电话的例子:

button.setLinkedTextWithHandler(text: "This website (stackoverflow.com) is awesome", link: "stackoverflow.com") 
{
    // show popup or open to link
}

其他回答

这个通用方法也可以!

func didTapAttributedTextInLabel(gesture: UITapGestureRecognizer, inRange targetRange: NSRange) -> Bool {

        let layoutManager = NSLayoutManager()
        let textContainer = NSTextContainer(size: CGSize.zero)
        guard let strAttributedText = self.attributedText else {
            return false
        }

        let textStorage = NSTextStorage(attributedString: strAttributedText)

        // Configure layoutManager and textStorage
        layoutManager.addTextContainer(textContainer)
        textStorage.addLayoutManager(layoutManager)

        // Configure textContainer
        textContainer.lineFragmentPadding = Constants.lineFragmentPadding
        textContainer.lineBreakMode = self.lineBreakMode
        textContainer.maximumNumberOfLines = self.numberOfLines
        let labelSize = self.bounds.size
        textContainer.size = CGSize(width: labelSize.width, height: CGFloat.greatestFiniteMagnitude)

        // Find the tapped character location and compare it to the specified range
        let locationOfTouchInLabel = gesture.location(in: self)

        let xCordLocationOfTouchInTextContainer = locationOfTouchInLabel.x
        let yCordLocationOfTouchInTextContainer = locationOfTouchInLabel.y
        let locOfTouch = CGPoint(x: xCordLocationOfTouchInTextContainer ,
                                 y: yCordLocationOfTouchInTextContainer)

        let indexOfCharacter = layoutManager.characterIndex(for: locOfTouch, in: textContainer, fractionOfDistanceBetweenInsertionPoints: nil)

        guard let strLabel = text else {
            return false
        }

        let charCountOfLabel = strLabel.count

        if indexOfCharacter < (charCountOfLabel - 1) {
            return NSLocationInRange(indexOfCharacter, targetRange)
        } else {
            return false
        }
    }

你可以用

let text = yourLabel.text
let termsRange = (text as NSString).range(of: fullString)
if yourLabel.didTapAttributedTextInLabel(gesture: UITapGestureRecognizer, inRange: termsRange) {
            showCorrespondingViewController()
        }

我正在扩展@NAlexN原始的详细解决方案,与@zekel优秀的UITapGestureRecognizer扩展,并在Swift中提供。

Extending UITapGestureRecognizer

extension UITapGestureRecognizer {

    func didTapAttributedTextInLabel(label: UILabel, inRange targetRange: NSRange) -> Bool {
        // Create instances of NSLayoutManager, NSTextContainer and NSTextStorage
        let layoutManager = NSLayoutManager()
        let textContainer = NSTextContainer(size: CGSize.zero)
        let textStorage = NSTextStorage(attributedString: label.attributedText!)

        // Configure layoutManager and textStorage
        layoutManager.addTextContainer(textContainer)
        textStorage.addLayoutManager(layoutManager)

        // Configure textContainer
        textContainer.lineFragmentPadding = 0.0
        textContainer.lineBreakMode = label.lineBreakMode
        textContainer.maximumNumberOfLines = label.numberOfLines
        let labelSize = label.bounds.size
        textContainer.size = labelSize

        // Find the tapped character location and compare it to the specified range
        let locationOfTouchInLabel = self.location(in: label)
        let textBoundingBox = layoutManager.usedRect(for: textContainer)
        let textContainerOffset = CGPoint(
            x: (labelSize.width - textBoundingBox.size.width) * 0.5 - textBoundingBox.origin.x,
            y: (labelSize.height - textBoundingBox.size.height) * 0.5 - textBoundingBox.origin.y
        )
        let locationOfTouchInTextContainer = CGPoint(
            x: locationOfTouchInLabel.x - textContainerOffset.x,
            y: locationOfTouchInLabel.y - textContainerOffset.y
        )
        let indexOfCharacter = layoutManager.characterIndex(for: locationOfTouchInTextContainer, in: textContainer, fractionOfDistanceBetweenInsertionPoints: nil)

        return NSLocationInRange(indexOfCharacter, targetRange)
    }

}

使用

设置UIGestureRecognizer发送动作到tapLabel:,你可以检测目标范围是否在myLabel上被点击。

@IBAction func tapLabel(gesture: UITapGestureRecognizer) {
    if gesture.didTapAttributedTextInLabel(myLabel, inRange: targetRange1) {
        print("Tapped targetRange1")
    } else if gesture.didTapAttributedTextInLabel(myLabel, inRange: targetRange2) {
        print("Tapped targetRange2")
    } else {
        print("Tapped none")
    }
}

重要提示:UILabel换行模式必须设置为按word/char换行。以某种方式,只有当换行模式为其他模式时,NSTextContainer才会假定文本为单行。

UITextView支持OS3.0中的数据检测器,而UILabel不支持。

如果你在UITextView上启用了数据检测器,并且你的文本包含url、电话号码等,它们将以链接的形式出现。

对于完全自定义的链接,你需要使用UIWebView -你可以拦截调用,这样当链接被按下时,你可以转到应用程序的其他部分。

就像在前面的回答中报告的那样,UITextView能够处理链接上的触摸。这可以通过将文本的其他部分作为链接来轻松扩展。AttributedTextView库是一个UITextView子类,它使得处理这些非常容易。更多信息请参见:https://github.com/evermeer/AttributedTextView

你可以让文本的任何部分像这样交互(其中textView1是一个UITextView IBOutlet):

textView1.attributer =
    "1. ".red
    .append("This is the first test. ").green
    .append("Click on ").black
    .append("evict.nl").makeInteract { _ in
        UIApplication.shared.open(URL(string: "http://evict.nl")!, options: [:], completionHandler: { completed in })
    }.underline
    .append(" for testing links. ").black
    .append("Next test").underline.makeInteract { _ in
        print("NEXT")
    }
    .all.font(UIFont(name: "SourceSansPro-Regular", size: 16))
    .setLinkColor(UIColor.purple) 

为了处理标签和提及,你可以使用这样的代码:

textView1.attributer = "@test: What #hashtags do we have in @evermeer #AtributedTextView library"
    .matchHashtags.underline
    .matchMentions
    .makeInteract { link in
        UIApplication.shared.open(URL(string: "https://twitter.com\(link.replacingOccurrences(of: "@", with: ""))")!, options: [:], completionHandler: { completed in })
    }