我有以下gulpfile.js,我通过命令行gulp消息执行:

var gulp = require('gulp');

gulp.task('message', function() {
  console.log("HTTP Server Started");
});

我得到以下错误消息:

[14:14:41] Using gulpfile ~\Documents\node\first\gulpfile.js
[14:14:41] Starting 'message'...
HTTP Server Started
[14:14:41] The following tasks did not complete: message
[14:14:41] Did you forget to signal async completion?

我在Windows 10系统上使用gulp 4。下面是gulp——version的输出:

[14:15:15] CLI version 0.4.0
[14:15:15] Local version 4.0.0-alpha.2

当前回答

我的解决方案:把所有东西都放在async中,然后等待gulp。

async function min_css() {
    return await gulp
        .src(cssFiles, { base: "." })
        .pipe(concat(cssOutput))
        .pipe(cssmin())
        .pipe(gulp.dest("."));
}

async function min_js() {
    return await gulp
        .src(jsFiles, { base: "." })
        .pipe(concat(jsOutput))
        .pipe(uglify())
        .pipe(gulp.dest("."));  
}

const min = async () => await gulp.series(min_css, min_js);

exports.min = min;

其他回答

我的解决方案:把所有东西都放在async中,然后等待gulp。

async function min_css() {
    return await gulp
        .src(cssFiles, { base: "." })
        .pipe(concat(cssOutput))
        .pipe(cssmin())
        .pipe(gulp.dest("."));
}

async function min_js() {
    return await gulp
        .src(jsFiles, { base: "." })
        .pipe(concat(jsOutput))
        .pipe(uglify())
        .pipe(gulp.dest("."));  
}

const min = async () => await gulp.series(min_css, min_js);

exports.min = min;

解决方案很简单,但我概述了我所做的更改、我得到的错误、前后的gulpfile以及包版本——因此使它看起来很长。

除了遵循保存.scss文件时输出的错误外,我还通过遵循前面多个答案的方向解决了这个问题。

简而言之:

我改变了gulp-sass的输入方式——见(A) 我把所有函数都改成了ASYNC函数——参见(B)

(A) gulp-sass import的改动:

之前:var sass = require('gulp-sass) After: var sass = require('gulp-sass')(require('sass'));

简单地将函数转换为ASYNC -

我的gulpfile看起来像以前:

'use strict';
 
// dependencies
var gulp = require('gulp');
var sass = require('gulp-sass');
var minifyCSS = require('gulp-clean-css');
var uglify = require('gulp-uglify');
var rename = require('gulp-rename');
var changed = require('gulp-changed');
 
var SCSS_SRC = './src/Assets/scss/**/*.scss';
var SCSS_DEST = './src/Assets/css';
 
function compile_scss() {
    return gulp.src(SCSS_SRC)
        .pipe(sass().on('error', sass.logError))
        .pipe(minifyCSS())
        .pipe(rename({ suffix: '.min' }))
        .pipe(changed(SCSS_DEST))
        .pipe(gulp.dest(SCSS_DEST));
}
 
 
function watch_scss() {
    gulp.watch(SCSS_SRC, compile_scss);
}

gulp.task('default', watch_scss); //Run tasks
 
exports.compile_scss = compile_scss;
exports.watch_scss = watch_scss;

我的gulpfile看起来像:

'use strict';
 
// dependencies
var gulp = require('gulp');
//var sass = require('gulp-sass');
var sass = require('gulp-sass')(require('sass'));
var minifyCSS = require('gulp-clean-css');
var uglify = require('gulp-uglify');
var rename = require('gulp-rename');
var changed = require('gulp-changed');

var SCSS_SRC = './src/Assets/scss/**/*.scss';
var SCSS_DEST = './src/Assets/css';
 
async function compile_scss() {
    return gulp.src(SCSS_SRC)
        .pipe(sass().on('error', sass.logError))
        .pipe(minifyCSS())
        .pipe(rename({ suffix: '.min' }))
        .pipe(changed(SCSS_DEST))
        .pipe(gulp.dest(SCSS_DEST));
}
 
async function watch_scss() {
    gulp.watch(SCSS_SRC, compile_scss);
}
 
gulp.task('default', watch_scss); // Run tasks
 
exports.compile_scss = compile_scss;
exports.watch_scss = watch_scss;

包版本:

"gulp": "^4.0.2",
"gulp-changed": "^4.0.3",
"gulp-rename": "^2.0.0",
"gulp-uglify": "^3.0.2",
"gulp-clean-css": "^4.3.0",
"gulp-sass": "^5.0.0",
"sass": "^1.38.0"

我得到的错误:

Error in plugin "gulp-sass"
Message:

gulp-sass 5 does not have a default Sass compiler; please set one yourself.
Both the `sass` and `node-sass` packages are permitted.
For example, in your gulpfile:

  var sass = require('gulp-sass')(require('sass'));

[14:00:37] The following tasks did not complete: default, compile_scss
[14:00:37] Did you forget to signal async completion?

我得到了同样的错误试图运行一个非常简单的SASS/CSS构建。

我的解决方案(可以解决相同或类似的错误)是简单地添加done作为默认任务函数的参数,并在默认任务的末尾调用它:

// Sass configuration
var gulp = require('gulp');
var sass = require('gulp-sass');

gulp.task('sass', function () {
    gulp.src('*.scss')
        .pipe(sass())
        .pipe(gulp.dest(function (f) {
            return f.base;
        }))
});

gulp.task('clean', function() {
})

gulp.task('watch', function() {
    gulp.watch('*.scss', ['sass']);
})


gulp.task('default', function(done) { // <--- Insert `done` as a parameter here...
    gulp.series('clean','sass', 'watch')
    done(); // <--- ...and call it here.
})

希望这能有所帮助!

对于那些试图使用gulp进行本地部署的人,下面的代码将有所帮助

var gulp = require("gulp");
var yaml = require("js-yaml");
var path = require("path");
var fs = require("fs");

//Converts yaml to json
gulp.task("swagger", done => {
    var doc = yaml.safeLoad(fs.readFileSync(path.join(__dirname,"api/swagger/swagger.yaml")));
    fs.writeFileSync(
        path.join(__dirname,"../yourjsonfile.json"),
        JSON.stringify(doc, null, " ")
        );
    done();
});

//Watches for changes    
gulp.task('watch', function() {
  gulp.watch('api/swagger/swagger.yaml', gulp.series('swagger'));  
});

解决方案:我们需要调用回调函数(任务和匿名):

function electronTask(callbackA)
{
    return gulp.series(myFirstTask, mySeccondTask, (callbackB) =>
    {
        callbackA();
        callbackB();
    })();    
}