这里有一个最简单的Swift 5解决方案，它不需要你创建一个自定义的后退按钮，也不需要你放弃所有免费获得的UINavigationController左键功能。

正如Brandon A上面建议的那样，你需要在你想要与之交互的视图控制器中实现UINavigationControllerDelegate。一个好方法是创建一个unwind segue，你可以手动或自动地执行，并从自定义完成按钮或后退按钮重用相同的代码。

首先，让你感兴趣的视图控制器(你想检测返回的那个)在它的viewDidLoad中成为导航控制器的委托:

override func viewDidLoad() {
    super.viewDidLoad()
    navigationController?.delegate = self
}

其次，在文件底部添加一个扩展，覆盖navigationController(willShow:animated:)

extension PickerTableViewController: UINavigationControllerDelegate {

    func navigationController(_ navigationController: UINavigationController,
                              willShow viewController: UIViewController,
                              animated: Bool) {

        if let _ = viewController as? EditComicBookViewController {

            let selectedItemRow = itemList.firstIndex(of: selectedItemName)
            selectedItemIndex = IndexPath(row: selectedItemRow!, section: 0)

            if let selectedCell = tableView.cellForRow(at: selectedItemIndex) {
                performSegue(withIdentifier: "PickedItem", sender: selectedCell)
            }
        }
    }
}

因为你的问题包含了一个UITableViewController，所以我包含了一种获取用户点击行的索引路径的方法。

据我所知，你想清空你的数组，当你按下后退按钮，弹出到你之前的ViewController，让你的数组加载在这个屏幕上

let settingArray  = NSMutableArray()
@IBAction func Back(sender: AnyObject) {
    self. settingArray.removeAllObjects()
    self.dismissViewControllerAnimated(true, completion: nil)
} 

Swift 5+(带警报控制的后退按钮)

override func viewDidLoad() {
        super.viewDidLoad()
        
        self.navigationItem.hidesBackButton = true
        let newBackButton = UIBarButtonItem(title: "<Back", style: UIBarButtonItem.Style.plain, target: self, action: #selector(PGWebViewController.back(sender:)))
        self.navigationItem.leftBarButtonItem = newBackButton
}


@objc func back(sender: UIBarButtonItem) {
    
    let alert = UIAlertController(title: "Warning!", message: "Your payment process is not completed yet. Do you want to go back?", preferredStyle: .alert)
        
         let ok = UIAlertAction(title: "OK", style: .default, handler: { action in
             _ = self.navigationController?.popViewController(animated: true)
         })
         alert.addAction(ok)
         let cancel = UIAlertAction(title: "Cancel", style: .default, handler: { action in
         })
         alert.addAction(cancel)
         DispatchQueue.main.async(execute: {
            self.present(alert, animated: true)
    })}

这就是我的解

extension UINavigationController: UINavigationBarDelegate {
    public func navigationBar(_ navigationBar: UINavigationBar, shouldPop item: UINavigationItem) -> Bool {
        if let shouldBlock = self.topViewController?.shouldPopFromNavigation() {
            return shouldBlock
        }
        return true
    }
}

extension UIViewController {
    @objc func shouldPopFromNavigation() -> Bool {
        return true
    }
}

在你的视图控制器中，你可以这样处理:

@objc override func shouldPopFromNavigation() -> Bool {
        // Your dialog, example UIAlertViewController or whatever you want
        return false
    }

斯威夫特4.2:

override func viewWillDisappear(_ animated: Bool) {
    super.viewWillDisappear(animated)

    if self.isMovingFromParent {
        // Your code...

    }
}

在我的例子中，viewWillDisappear效果最好。但在某些情况下，必须修改之前的视图控制器。所以这是我的解决方案访问之前的视图控制器，它在Swift 4中工作:

override func viewWillDisappear(_ animated: Bool) {
        super.viewWillDisappear(animated)
        if isMovingFromParentViewController {
            if let viewControllers = self.navigationController?.viewControllers {
                if (viewControllers.count >= 1) {
                    let previousViewController = viewControllers[viewControllers.count-1] as! NameOfDestinationViewController
                    // whatever you want to do
                    previousViewController.callOrModifySomething()
                }
            }
        }
    }