我有JavaScript,它周期性地执行活动。当用户没有在看站点时(例如,窗口或选项卡没有焦点),最好不要运行。

是否有一种方法可以使用JavaScript来做到这一点?

我的参考点:如果你正在使用的窗口不活跃,Gmail聊天就会播放声音。


当前回答

简单的/立即检查:

if(document.hidden) {
  // do something
}

可见性变化事件:

document.addEventListener("visibilitychange", function() {
  console.log(document.visibilityState); // "hidden" or "visible"
}, false);

基于承诺的事件:

// An `await`able function that resolves when page visibility changes:
function visibilityChange(state="") {
  return new Promise(resolve => {
    document.addEventListener("visibilitychange", function() {
      if(!state || document.visibilityState === state) { 
        resolve(document.visibilityState);
        document.removeEventListener("visibilitychange", arguments.callee);
      }
    });
  });
}

// Use it like this:
await visibilityChange();
console.log(document.visibilityState);

// Or wait for page to become...
await visibilityChange("visible");
await visibilityChange("hidden");

(注:后两个解是我加到这个答案里的,因为这个问题现在已经结束了,我不能加我自己的答案。以防有人认为我抄袭了那篇文章而没有注明出处。)

其他回答

var visibilityChange = (function (window) {
    var inView = false;
    return function (fn) {
        window.onfocus = window.onblur = window.onpageshow = window.onpagehide = function (e) {
            if ({focus:1, pageshow:1}[e.type]) {
                if (inView) return;
                fn("visible");
                inView = true;
            } else if (inView) {
                fn("hidden");
                inView = false;
            }
        };
    };
}(this));

visibilityChange(function (state) {
    console.log(state);
});

http://jsfiddle.net/ARTsinn/JTxQY/

从最初编写这个答案开始,由于W3C,一个新的规范已经达到了推荐状态。页面可见性API(在MDN上)现在允许我们更准确地检测页面何时对用户隐藏。

document.addEventListener("visibilitychange", onchange);

当前浏览器支持:

铬13 + Internet Explorer 10+ Firefox 10 + Opera 12.10+[阅读笔记]

下面的代码在不兼容的浏览器中退回到不太可靠的模糊/聚焦方法:

(function() {
  var hidden = "hidden";

  // Standards:
  if (hidden in document)
    document.addEventListener("visibilitychange", onchange);
  else if ((hidden = "mozHidden") in document)
    document.addEventListener("mozvisibilitychange", onchange);
  else if ((hidden = "webkitHidden") in document)
    document.addEventListener("webkitvisibilitychange", onchange);
  else if ((hidden = "msHidden") in document)
    document.addEventListener("msvisibilitychange", onchange);
  // IE 9 and lower:
  else if ("onfocusin" in document)
    document.onfocusin = document.onfocusout = onchange;
  // All others:
  else
    window.onpageshow = window.onpagehide
    = window.onfocus = window.onblur = onchange;

  function onchange (evt) {
    var v = "visible", h = "hidden",
        evtMap = {
          focus:v, focusin:v, pageshow:v, blur:h, focusout:h, pagehide:h
        };

    evt = evt || window.event;
    if (evt.type in evtMap)
      document.body.className = evtMap[evt.type];
    else
      document.body.className = this[hidden] ? "hidden" : "visible";
  }

  // set the initial state (but only if browser supports the Page Visibility API)
  if( document[hidden] !== undefined )
    onchange({type: document[hidden] ? "blur" : "focus"});
})();

ie9及以下版本需要onfocusin和onfocusout,而所有其他都使用onfocus和onblur,除了iOS,它使用onpageshow和onpagehide。

我重读了@daniel-buckmaster的版本 我没有做多次尝试,但是,代码对我来说似乎更优雅…

// on-visibility-change.js v1.0.1, based on https://stackoverflow.com/questions/1060008/is-there-a-way-to-detect-if-a-browser-window-is-not-currently-active#38710376
function onVisibilityChange(callback) {
    let d = document;
    let visible = true;
    let prefix;
    if ('hidden' in d) {
        prefix = 'h';
    } else if ('webkitHidden' in d) {
        prefix = 'webkitH';
    } else if ('mozHidden' in d) {
        prefix = 'mozH';
    } else if ('msHidden' in d) {
        prefix = 'msH';
    } else if ('onfocusin' in d) { // ie 9 and lower
        d.onfocusin = focused;
        d.onfocusout = unfocused;
    } else { // others
        window.onpageshow = window.onfocus = focused;
        window.onpagehide = window.onblur = unfocused;
    };
    if (prefix) {
        visible = !d[prefix + 'idden'];
        d.addEventListener(prefix.substring(0, prefix.length - 1) + 'visibilitychange', function() {
            (d[prefix + 'idden'] ? unfocused : focused)();
        });
    };

    function focused() {
        if (!visible) {
            callback(visible = true);
        };
    };

    function unfocused() {
        if (visible) {
            callback(visible = false);
        };
    };
};

稍微复杂一点的方法是使用setInterval()检查鼠标位置并与上次检查进行比较。如果鼠标在一段时间内没有移动,则用户可能处于空闲状态。

这有一个额外的好处,可以告诉用户是否空闲,而不仅仅是检查窗口是否处于活动状态。

正如许多人指出的那样,这并不总是一种检查用户或浏览器窗口是否空闲的好方法,因为用户甚至可能没有使用鼠标或正在观看视频或类似的内容。我只是建议一种检查空闲状态的方法。

我开始使用社区维基答案,但意识到它没有检测alt-tab事件在Chrome。这是因为它使用了第一个可用的事件源,在这种情况下,它是页面可见性API,在Chrome中似乎不跟踪alt-tab。

我决定稍微修改一下脚本,以跟踪页面焦点更改的所有可能事件。这是一个你可以放入的函数:

function onVisibilityChange(callback) {
    var visible = true;

    if (!callback) {
        throw new Error('no callback given');
    }

    function focused() {
        if (!visible) {
            callback(visible = true);
        }
    }

    function unfocused() {
        if (visible) {
            callback(visible = false);
        }
    }

    // Standards:
    if ('hidden' in document) {
        visible = !document.hidden;
        document.addEventListener('visibilitychange',
            function() {(document.hidden ? unfocused : focused)()});
    }
    if ('mozHidden' in document) {
        visible = !document.mozHidden;
        document.addEventListener('mozvisibilitychange',
            function() {(document.mozHidden ? unfocused : focused)()});
    }
    if ('webkitHidden' in document) {
        visible = !document.webkitHidden;
        document.addEventListener('webkitvisibilitychange',
            function() {(document.webkitHidden ? unfocused : focused)()});
    }
    if ('msHidden' in document) {
        visible = !document.msHidden;
        document.addEventListener('msvisibilitychange',
            function() {(document.msHidden ? unfocused : focused)()});
    }
    // IE 9 and lower:
    if ('onfocusin' in document) {
        document.onfocusin = focused;
        document.onfocusout = unfocused;
    }
    // All others:
    window.onpageshow = window.onfocus = focused;
    window.onpagehide = window.onblur = unfocused;
};

像这样使用它:

onVisibilityChange(function(visible) {
    console.log('the page is now', visible ? 'focused' : 'unfocused');
});

该版本监听所有不同的可见性事件,并在其中任何事件导致更改时触发回调。焦点处理程序和非焦点处理程序确保如果多个api捕捉到相同的可见性更改,不会多次调用回调。