我有JavaScript,它周期性地执行活动。当用户没有在看站点时(例如,窗口或选项卡没有焦点),最好不要运行。

是否有一种方法可以使用JavaScript来做到这一点?

我的参考点:如果你正在使用的窗口不活跃,Gmail聊天就会播放声音。


当前回答

对于没有jQuery的解决方案,请参阅Visibility.js,它提供了关于三个页面状态的信息

visible    ... page is visible
hidden     ... page is not visible
prerender  ... page is being prerendered by the browser

以及setInterval的方便包装器

/* Perform action every second if visible */
Visibility.every(1000, function () {
    action();
});

/* Perform action every second if visible, every 60 sec if not visible */
Visibility.every(1000, 60*1000, function () {
    action();
});

旧版浏览器(IE < 10;iOS < 7)也可用

其他回答

我会使用jQuery,因为这样你所要做的就是:

$(window).blur(function(){
  //your code here
});
$(window).focus(function(){
  //your code
});

至少对我有用。

这在chrome 67和firefox 67上都适用,

if(!document.hasFocus()) {
    // do stuff
}

这适用于所有现代浏览器:

更改制表符时 更改窗口时(Alt+Tab) 当从任务栏最大化另一个程序时

var eventName;
var visible = true;
var propName = "hidden";
if (propName in document) eventName = "visibilitychange";
else if ((propName = "msHidden") in document) eventName = "msvisibilitychange";
else if ((propName = "mozHidden") in document) eventName = "mozvisibilitychange";
else if ((propName = "webkitHidden") in document) eventName = "webkitvisibilitychange";
if (eventName) document.addEventListener(eventName, handleChange);

if ("onfocusin" in document) document.onfocusin = document.onfocusout = handleChange; //IE 9
window.onpageshow = window.onpagehide = window.onfocus = window.onblur = handleChange;// Changing tab with alt+tab

// Initialize state if Page Visibility API is supported
if (document[propName] !== undefined) handleChange({ type: document[propName] ? "blur" : "focus" });

function handleChange(evt) {
  evt = evt || window.event;
  if (visible && (["blur", "focusout", "pagehide"].includes(evt.type) || (this && this[propName]))){
    visible = false;
    console.log("Out...")
  }
  else if (!visible && (["focus", "focusin", "pageshow"].includes(evt.type) || (this && !this[propName]))){
    visible = true;
    console.log("In...")
  }
}

我开始使用社区维基答案,但意识到它没有检测alt-tab事件在Chrome。这是因为它使用了第一个可用的事件源,在这种情况下,它是页面可见性API,在Chrome中似乎不跟踪alt-tab。

我决定稍微修改一下脚本,以跟踪页面焦点更改的所有可能事件。这是一个你可以放入的函数:

function onVisibilityChange(callback) {
    var visible = true;

    if (!callback) {
        throw new Error('no callback given');
    }

    function focused() {
        if (!visible) {
            callback(visible = true);
        }
    }

    function unfocused() {
        if (visible) {
            callback(visible = false);
        }
    }

    // Standards:
    if ('hidden' in document) {
        visible = !document.hidden;
        document.addEventListener('visibilitychange',
            function() {(document.hidden ? unfocused : focused)()});
    }
    if ('mozHidden' in document) {
        visible = !document.mozHidden;
        document.addEventListener('mozvisibilitychange',
            function() {(document.mozHidden ? unfocused : focused)()});
    }
    if ('webkitHidden' in document) {
        visible = !document.webkitHidden;
        document.addEventListener('webkitvisibilitychange',
            function() {(document.webkitHidden ? unfocused : focused)()});
    }
    if ('msHidden' in document) {
        visible = !document.msHidden;
        document.addEventListener('msvisibilitychange',
            function() {(document.msHidden ? unfocused : focused)()});
    }
    // IE 9 and lower:
    if ('onfocusin' in document) {
        document.onfocusin = focused;
        document.onfocusout = unfocused;
    }
    // All others:
    window.onpageshow = window.onfocus = focused;
    window.onpagehide = window.onblur = unfocused;
};

像这样使用它:

onVisibilityChange(function(visible) {
    console.log('the page is now', visible ? 'focused' : 'unfocused');
});

该版本监听所有不同的可见性事件,并在其中任何事件导致更改时触发回调。焦点处理程序和非焦点处理程序确保如果多个api捕捉到相同的可见性更改,不会多次调用回调。

使用:页面可见性API

document.addEventListener( 'visibilitychange' , function() {
    if (document.hidden) {
        console.log('bye');
    } else {
        console.log('well back');
    }
}, false );

我能用吗?http://caniuse.com/#feat=pagevisibility