如果你想对整个浏览器模糊: 正如我所评论的，如果浏览器失去焦点，建议的事件都不会触发。我的想法是在循环中计数，并在事件发生时重置计数器。如果计数器达到限制，我做一个位置。请转到另一页。如果你在开发工具上工作，这也会触发。

var iput=document.getElementById("hiddenInput");
   ,count=1
   ;
function check(){
         count++;
         if(count%2===0){
           iput.focus();
         }
         else{
           iput.blur();
         }
         iput.value=count;  
         if(count>3){
           location.href="http://Nirwana.com";
         }              
         setTimeout(function(){check()},1000);
}   
iput.onblur=function(){count=1}
iput.onfocus=function(){count=1}
check();

这是在FF上成功测试的草稿。

这在chrome 67和firefox 67上都适用，

if(!document.hasFocus()) {
    // do stuff
}

对于angular.js，这里有一个指令(基于已接受的答案)，它将允许你的控制器对可见性的变化做出反应:

myApp.directive('reactOnWindowFocus', function($parse) {
    return {
        restrict: "A",
        link: function(scope, element, attrs) {
            var hidden = "hidden";
            var currentlyVisible = true;
            var functionOrExpression = $parse(attrs.reactOnWindowFocus);

          // Standards:
          if (hidden in document)
            document.addEventListener("visibilitychange", onchange);
          else if ((hidden = "mozHidden") in document)
            document.addEventListener("mozvisibilitychange", onchange);
          else if ((hidden = "webkitHidden") in document)
            document.addEventListener("webkitvisibilitychange", onchange);
          else if ((hidden = "msHidden") in document)
            document.addEventListener("msvisibilitychange", onchange);
          else if ("onfocusin" in document) {
                // IE 9 and lower:
            document.onfocusin = onshow;
                document.onfocusout = onhide;
          } else {
                // All others:
            window.onpageshow = window.onfocus = onshow;
                window.onpagehide = window.onblur = onhide;
            }

          function onchange (evt) {
                //occurs both on leaving and on returning
                currentlyVisible = !currentlyVisible;
                doSomethingIfAppropriate();
          }

            function onshow(evt) {
                //for older browsers
                currentlyVisible = true;
                doSomethingIfAppropriate();
            }

            function onhide(evt) {
                //for older browsers
                currentlyVisible = false;
                doSomethingIfAppropriate();
            }

            function doSomethingIfAppropriate() {
                if (currentlyVisible) {
                    //trigger angular digest cycle in this scope
                    scope.$apply(function() {
                        functionOrExpression(scope);
                    });
                }
            }
        }
    };

});

你可以像这样使用它:<div react-on-window-focus="refresh()">，其中refresh()是范围内任何控制器范围内的范围函数。

var visibilityChange = (function (window) {
    var inView = false;
    return function (fn) {
        window.onfocus = window.onblur = window.onpageshow = window.onpagehide = function (e) {
            if ({focus:1, pageshow:1}[e.type]) {
                if (inView) return;
                fn("visible");
                inView = true;
            } else if (inView) {
                fn("hidden");
                inView = false;
            }
        };
    };
}(this));

visibilityChange(function (state) {
    console.log(state);
});

http://jsfiddle.net/ARTsinn/JTxQY/

在GitHub上有一个简洁的库:

https://github.com/serkanyersen/ifvisible.js

例子:

// If page is visible right now
if( ifvisible.now() ){
  // Display pop-up
  openPopUp();
}

我已经在我拥有的所有浏览器上测试了1.0.1版本，并可以确认它适用于:

的问世,IE9 FF 26.0 Chrome 34.0

．.． 可能还有所有更新的版本。

不完全适用于:

IE8 -总是指示标签/窗口当前是活跃的(.now()总是为我返回true)

我的代码

let browser_active = ((typeof document.hasFocus != 'undefined' ? document.hasFocus() : 1) ? 1 : 0);
if (!browser_active) {
 // active
}