对我来说这很有效

Object[] forNow = template.getForObject("URL", Object[].class);
    searchList= Arrays.asList(forNow);

Object是你想要的类的位置

也许这样……

ResponseEntity<Object[]> responseEntity = restTemplate.getForEntity(urlGETList, Object[].class);
Object[] objects = responseEntity.getBody();
MediaType contentType = responseEntity.getHeaders().getContentType();
HttpStatus statusCode = responseEntity.getStatusCode();

RequestMapping的控制器代码

@RequestMapping(value="/Object/getList/", method=RequestMethod.GET)
public @ResponseBody List<Object> findAllObjects() {

    List<Object> objects = new ArrayList<Object>();
    return objects;
}

ResponseEntity是HttpEntity的扩展，它添加了HttpStatus状态码。在RestTemplate和@Controller方法中使用。 在RestTemplate中，该类由getForEntity()和exchange()返回。

对我来说这很有效

Object[] forNow = template.getForObject("URL", Object[].class);
    searchList= Arrays.asList(forNow);

Object是你想要的类的位置

实际上，我之前为我的一个项目开发了一些功能，以下是代码:

/**
 * @param url             is the URI address of the WebService
 * @param parameterObject the object where all parameters are passed.
 * @param returnType      the return type you are expecting. Exemple : someClass.class
 */

public static <T> T getObject(String url, Object parameterObject, Class<T> returnType) {
    try {
        ResponseEntity<T> res;
        ObjectMapper mapper = new ObjectMapper();
        RestTemplate restTemplate = new RestTemplate();
        restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
        restTemplate.getMessageConverters().add(0, new StringHttpMessageConverter(Charset.forName("UTF-8")));
        ((SimpleClientHttpRequestFactory) restTemplate.getRequestFactory()).setConnectTimeout(2000);
        HttpHeaders headers = new HttpHeaders();
        headers.setContentType(MediaType.APPLICATION_JSON);
        HttpEntity<T> entity = new HttpEntity<T>((T) parameterObject, headers);
        String json = mapper.writeValueAsString(restTemplate.exchange(url, org.springframework.http.HttpMethod.POST, entity, returnType).getBody());
        return new Gson().fromJson(json, returnType);
    } catch (Exception e) {
        e.printStackTrace();
        return null;
    }
}

/**
 * @param url             is the URI address of the WebService
 * @param parameterObject the object where all parameters are passed.
 * @param returnType      the type of the returned object. Must be an array. Exemple : someClass[].class
 */
public static <T> List<T> getListOfObjects(String url, Object parameterObject, Class<T[]> returnType) {
    try {
        ObjectMapper mapper = new ObjectMapper();
        RestTemplate restTemplate = new RestTemplate();
        restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
        restTemplate.getMessageConverters().add(0, new StringHttpMessageConverter(Charset.forName("UTF-8")));
        ((SimpleClientHttpRequestFactory) restTemplate.getRequestFactory()).setConnectTimeout(2000);
        HttpHeaders headers = new HttpHeaders();
        headers.setContentType(MediaType.APPLICATION_JSON);
        HttpEntity<T> entity = new HttpEntity<T>((T) parameterObject, headers);
        ResponseEntity<Object[]> results = restTemplate.exchange(url, org.springframework.http.HttpMethod.POST, entity, Object[].class);
        String json = mapper.writeValueAsString(results.getBody());
        T[] arr = new Gson().fromJson(json, returnType);
        return Arrays.asList(arr);
    } catch (Exception e) {
        e.printStackTrace();
        return null;
    }
}

我希望这能帮助到别人!

考虑一下这个答案，特别是如果你想在列表中使用泛型 Spring RestTemplate和泛型类型ParameterizedTypeReference集合，如List<T>

你可以为每个条目创建POJO，

class BitPay{
private String code;
private String name;
private double rate;
}

然后使用BitPay列表的ParameterizedTypeReference，你可以使用:

RestTemplate restTemplate = new RestTemplate();
ResponseEntity<List<Employee>> response = restTemplate.exchange(
  "https://bitpay.com/api/rates",
  HttpMethod.GET,
  null,
  new ParameterizedTypeReference<List<BitPay>>(){});
List<Employee> employees = response.getBody();