假设我有一个可序列化的类AppMessage。

我想通过套接字将它作为字节[]传输到另一台机器,在那里它从接收到的字节重建。

我怎么才能做到呢?


当前回答

最好的方法是使用Apache Commons Lang中的SerializationUtils。

序列化:

byte[] data = SerializationUtils.serialize(yourObject);

反序列化:

YourObject yourObject = SerializationUtils.deserialize(data)

如前所述,这需要Commons Lang库。它可以使用Gradle导入:

compile 'org.apache.commons:commons-lang3:3.5'

Maven:

<!-- https://mvnrepository.com/artifact/org.apache.commons/commons-lang3 -->
<dependency>
    <groupId>org.apache.commons</groupId>
    <artifactId>commons-lang3</artifactId>
    <version>3.5</version>
</dependency>

Jar文件

这里提到了更多的方法

或者,可以导入整个集合。参考这个连结

其他回答

准备要发送的字节数组:

ByteArrayOutputStream bos = new ByteArrayOutputStream();
ObjectOutputStream out = null;
try {
  out = new ObjectOutputStream(bos);   
  out.writeObject(yourObject);
  out.flush();
  byte[] yourBytes = bos.toByteArray();
  ...
} finally {
  try {
    bos.close();
  } catch (IOException ex) {
    // ignore close exception
  }
}

从字节数组创建一个对象:

ByteArrayInputStream bis = new ByteArrayInputStream(yourBytes);
ObjectInput in = null;
try {
  in = new ObjectInputStream(bis);
  Object o = in.readObject(); 
  ...
} finally {
  try {
    if (in != null) {
      in.close();
    }
  } catch (IOException ex) {
    // ignore close exception
  }
}

我想通过套接字将它作为字节[]传输到另一台机器

// When you connect
ObjectOutputStream oos = new ObjectOutputStream(socket.getOutputStream());
// When you want to send it
oos.writeObject(appMessage);

从接收到的字节重新构建。

// When you connect
ObjectInputStream ois = new ObjectInputStream(socket.getInputStream());
// When you want to receive it
AppMessage appMessage = (AppMessage)ois.readObject();

如果你使用spring,在spring-core中有一个util类可用。你可以简单地

import org.springframework.util.SerializationUtils;

byte[] bytes = SerializationUtils.serialize(anyObject);
Object object = SerializationUtils.deserialize(bytes);

可以通过SerializationUtils完成,通过ApacheUtils的serialize & deserialize方法将对象转换为字节[],反之亦然,如@uris answer中所述。

通过序列化将一个对象转换为字节[]:

byte[] data = SerializationUtils.serialize(object);

通过反序列化将byte[]转换为object::

Object object = (Object) SerializationUtils.deserialize(byte[] data)

点击下载org-apache-commons-lang.jar的链接

通过点击整合.jar文件:

FileName ->打开Medule Settings ->选择你的模块-> Dependencies ->添加Jar文件,完成。

希望这能有所帮助。

Java 8+的代码示例:

public class Person implements Serializable {

private String lastName;
private String firstName;

public Person() {
}

public Person(String firstName, String lastName) {
    this.firstName = firstName;
    this.lastName = lastName;
}

public void setFirstName(String firstName) {
    this.firstName = firstName;
}

public String getFirstName() {
    return firstName;
}

public String getLastName() {
    return lastName;
}

public void setLastName(String lastName) {
    this.lastName = lastName;
}

@Override
public String toString() {
    return "firstName: " + firstName + ", lastName: " + lastName;
}
}


public interface PersonMarshaller {
default Person fromStream(InputStream inputStream) {
    try (ObjectInputStream objectInputStream = new ObjectInputStream(inputStream)) {
        Person person= (Person) objectInputStream.readObject();
        return person;
    } catch (IOException | ClassNotFoundException e) {
        System.err.println(e.getMessage());
        return null;
    }
}

default OutputStream toStream(Person person) {
    try (OutputStream outputStream = new ByteArrayOutputStream()) {
        ObjectOutput objectOutput = new ObjectOutputStream(outputStream);
        objectOutput.writeObject(person);
        objectOutput.flush();
        return outputStream;
    } catch (IOException e) {
        System.err.println(e.getMessage());
        return null;
    }

}

}