假设我有一个可序列化的类AppMessage。
我想通过套接字将它作为字节[]传输到另一台机器,在那里它从接收到的字节重建。
我怎么才能做到呢?
假设我有一个可序列化的类AppMessage。
我想通过套接字将它作为字节[]传输到另一台机器,在那里它从接收到的字节重建。
我怎么才能做到呢?
准备要发送的字节数组:
ByteArrayOutputStream bos = new ByteArrayOutputStream();
ObjectOutputStream out = null;
try {
out = new ObjectOutputStream(bos);
out.writeObject(yourObject);
out.flush();
byte[] yourBytes = bos.toByteArray();
...
} finally {
try {
bos.close();
} catch (IOException ex) {
// ignore close exception
}
}
从字节数组创建一个对象:
ByteArrayInputStream bis = new ByteArrayInputStream(yourBytes);
ObjectInput in = null;
try {
in = new ObjectInputStream(bis);
Object o = in.readObject();
...
} finally {
try {
if (in != null) {
in.close();
}
} catch (IOException ex) {
// ignore close exception
}
}
最好的方法是使用Apache Commons Lang中的SerializationUtils。
序列化:
byte[] data = SerializationUtils.serialize(yourObject);
反序列化:
YourObject yourObject = SerializationUtils.deserialize(data)
如前所述,这需要Commons Lang库。它可以使用Gradle导入:
compile 'org.apache.commons:commons-lang3:3.5'
Maven:
<!-- https://mvnrepository.com/artifact/org.apache.commons/commons-lang3 -->
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-lang3</artifactId>
<version>3.5</version>
</dependency>
Jar文件
这里提到了更多的方法
或者,可以导入整个集合。参考这个连结
如果你使用Java >= 7,你可以使用try和资源改进接受的解决方案:
private byte[] convertToBytes(Object object) throws IOException {
try (ByteArrayOutputStream bos = new ByteArrayOutputStream();
ObjectOutputStream out = new ObjectOutputStream(bos)) {
out.writeObject(object);
return bos.toByteArray();
}
}
反过来说:
private Object convertFromBytes(byte[] bytes) throws IOException, ClassNotFoundException {
try (ByteArrayInputStream bis = new ByteArrayInputStream(bytes);
ObjectInputStream in = new ObjectInputStream(bis)) {
return in.readObject();
}
}
可以通过SerializationUtils完成,通过ApacheUtils的serialize & deserialize方法将对象转换为字节[],反之亦然,如@uris answer中所述。
通过序列化将一个对象转换为字节[]:
byte[] data = SerializationUtils.serialize(object);
通过反序列化将byte[]转换为object::
Object object = (Object) SerializationUtils.deserialize(byte[] data)
点击下载org-apache-commons-lang.jar的链接
通过点击整合.jar文件:
FileName ->打开Medule Settings ->选择你的模块-> Dependencies ->添加Jar文件,完成。
希望这能有所帮助。
我也推荐使用SerializationUtils工具。我想对@Abilash的错误评论做一个调整。SerializationUtils.serialize()方法不限制为1024字节,这与这里的另一个答案相反。
public static byte[] serialize(Object object) {
if (object == null) {
return null;
}
ByteArrayOutputStream baos = new ByteArrayOutputStream(1024);
try {
ObjectOutputStream oos = new ObjectOutputStream(baos);
oos.writeObject(object);
oos.flush();
}
catch (IOException ex) {
throw new IllegalArgumentException("Failed to serialize object of type: " + object.getClass(), ex);
}
return baos.toByteArray();
}
乍一看,您可能认为新的ByteArrayOutputStream(1024)只允许固定的大小。但是如果你仔细观察ByteArrayOutputStream,你会发现流在必要时还会增长:
该类实现了一个输出流,其中数据为 写入字节数组。缓冲区自动作为数据增长 被写入。 可以使用toByteArray()和 toString ()。
我想通过套接字将它作为字节[]传输到另一台机器
// When you connect
ObjectOutputStream oos = new ObjectOutputStream(socket.getOutputStream());
// When you want to send it
oos.writeObject(appMessage);
从接收到的字节重新构建。
// When you connect
ObjectInputStream ois = new ObjectInputStream(socket.getInputStream());
// When you want to receive it
AppMessage appMessage = (AppMessage)ois.readObject();
Java 8+的代码示例:
public class Person implements Serializable {
private String lastName;
private String firstName;
public Person() {
}
public Person(String firstName, String lastName) {
this.firstName = firstName;
this.lastName = lastName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getFirstName() {
return firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
@Override
public String toString() {
return "firstName: " + firstName + ", lastName: " + lastName;
}
}
public interface PersonMarshaller {
default Person fromStream(InputStream inputStream) {
try (ObjectInputStream objectInputStream = new ObjectInputStream(inputStream)) {
Person person= (Person) objectInputStream.readObject();
return person;
} catch (IOException | ClassNotFoundException e) {
System.err.println(e.getMessage());
return null;
}
}
default OutputStream toStream(Person person) {
try (OutputStream outputStream = new ByteArrayOutputStream()) {
ObjectOutput objectOutput = new ObjectOutputStream(outputStream);
objectOutput.writeObject(person);
objectOutput.flush();
return outputStream;
} catch (IOException e) {
System.err.println(e.getMessage());
return null;
}
}
}
另一个有趣的方法来自com.fasterxml.jackson.databind.ObjectMapper
byte[] data = new ObjectMapper().writeValueAsBytes(JAVA_OBJECT_HERE)
Maven的依赖
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
</dependency>
Spring框架org.springframework.util.SerializationUtils
byte[] data = SerializationUtils.serialize(obj);
如果你使用spring,在spring-core中有一个util类可用。你可以简单地
import org.springframework.util.SerializationUtils;
byte[] bytes = SerializationUtils.serialize(anyObject);
Object object = SerializationUtils.deserialize(bytes);
如果你想要一个不错的无依赖复制粘贴解决方案。获取下面的代码。
例子
MyObject myObject = ...
byte[] bytes = SerializeUtils.serialize(myObject);
myObject = SerializeUtils.deserialize(bytes);
源
import java.io.*;
public class SerializeUtils {
public static byte[] serialize(Serializable value) throws IOException {
ByteArrayOutputStream out = new ByteArrayOutputStream();
try(ObjectOutputStream outputStream = new ObjectOutputStream(out)) {
outputStream.writeObject(value);
}
return out.toByteArray();
}
public static <T extends Serializable> T deserialize(byte[] data) throws IOException, ClassNotFoundException {
try(ByteArrayInputStream bis = new ByteArrayInputStream(data)) {
//noinspection unchecked
return (T) new ObjectInputStream(bis).readObject();
}
}
}
这只是一个被接受的答案的优化代码形式,以防有人想在生产中使用它:
public static void byteArrayOps() throws IOException, ClassNotFoundException{
String str="123";
byte[] yourBytes = null;
// Convert to byte[]
try(ByteArrayOutputStream bos = new ByteArrayOutputStream();
ObjectOutputStream out = new ObjectOutputStream(bos);) {
out.writeObject(str);
out.flush();
yourBytes = bos.toByteArray();
} finally {
}
// convert back to Object
try(ByteArrayInputStream bis = new ByteArrayInputStream(yourBytes);
ObjectInput in = new ObjectInputStream(bis);) {
Object o = in.readObject();
} finally {
}
}