我如何获得一个人类可读的文件大小字节缩写使用。net ?
例子: 输入7,326,629,显示6.98 MB
我如何获得一个人类可读的文件大小字节缩写使用。net ?
例子: 输入7,326,629,显示6.98 MB
当前回答
1-liner(加上前缀常量)
const String prefixes = " KMGTPEY";
/// <summary> Returns the human-readable file size for an arbitrary, 64-bit file size. </summary>
public static String HumanSize(UInt64 bytes)
=> Enumerable
.Range(0, prefixes.Length)
.Where(i => bytes < 1024U<<(i*10))
.Select(i => $"{(bytes>>(10*i-10))/1024:0.###} {prefixes[i]}B")
.First();
或者,如果你想减少LINQ对象的分配,使用相同的for循环变量:
/// <summary>
/// Returns the human-readable file size for an arbitrary, 64-bit file size.
/// </summary>
public static String HumanSize(UInt64 bytes)
{
const String prefixes = " KMGTPEY";
for (var i = 0; i < prefixes.Length; i++)
if (bytes < 1024U<<(i*10))
return $"{(bytes>>(10*i-10))/1024:0.###} {prefixes[i]}B";
throw new ArgumentOutOfRangeException(nameof(bytes));
}
其他回答
我喜欢使用以下方法(它支持高达tb,这在大多数情况下已经足够了,但它可以很容易地扩展):
private string GetSizeString(long length)
{
long B = 0, KB = 1024, MB = KB * 1024, GB = MB * 1024, TB = GB * 1024;
double size = length;
string suffix = nameof(B);
if (length >= TB) {
size = Math.Round((double)length / TB, 2);
suffix = nameof(TB);
}
else if (length >= GB) {
size = Math.Round((double)length / GB, 2);
suffix = nameof(GB);
}
else if (length >= MB) {
size = Math.Round((double)length / MB, 2);
suffix = nameof(MB);
}
else if (length >= KB) {
size = Math.Round((double)length / KB, 2);
suffix = nameof(KB);
}
return $"{size} {suffix}";
}
请记住,这是为c# 6.0(2015)编写的,因此对于较早的版本可能需要进行一些编辑。
我使用下面的Long扩展方法将其转换为人类可读的大小字符串。这个方法是在Stack Overflow上发布的相同问题的Java解决方案的c#实现。
/// <summary>
/// Convert a byte count into a human readable size string.
/// </summary>
/// <param name="bytes">The byte count.</param>
/// <param name="si">Whether or not to use SI units.</param>
/// <returns>A human readable size string.</returns>
public static string ToHumanReadableByteCount(
this long bytes
, bool si
)
{
var unit = si
? 1000
: 1024;
if (bytes < unit)
{
return $"{bytes} B";
}
var exp = (int) (Math.Log(bytes) / Math.Log(unit));
return $"{bytes / Math.Pow(unit, exp):F2} " +
$"{(si ? "kMGTPE" : "KMGTPE")[exp - 1] + (si ? string.Empty : "i")}B";
}
所有溶液的混合:-)
/// <summary>
/// Converts a numeric value into a string that represents the number expressed as a size value in bytes,
/// kilobytes, megabytes, or gigabytes, depending on the size.
/// </summary>
/// <param name="fileSize">The numeric value to be converted.</param>
/// <returns>The converted string.</returns>
public static string FormatByteSize(double fileSize)
{
FileSizeUnit unit = FileSizeUnit.B;
while (fileSize >= 1024 && unit < FileSizeUnit.YB)
{
fileSize = fileSize / 1024;
unit++;
}
return string.Format("{0:0.##} {1}", fileSize, unit);
}
/// <summary>
/// Converts a numeric value into a string that represents the number expressed as a size value in bytes,
/// kilobytes, megabytes, or gigabytes, depending on the size.
/// </summary>
/// <param name="fileInfo"></param>
/// <returns>The converted string.</returns>
public static string FormatByteSize(FileInfo fileInfo)
{
return FormatByteSize(fileInfo.Length);
}
}
public enum FileSizeUnit : byte
{
B,
KB,
MB,
GB,
TB,
PB,
EB,
ZB,
YB
}
另一种皮肤的方法,没有任何类型的循环和负大小支持(对文件大小增量有意义):
public static class Format
{
static string[] sizeSuffixes = {
"B", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB" };
public static string ByteSize(long size)
{
Debug.Assert(sizeSuffixes.Length > 0);
const string formatTemplate = "{0}{1:0.#} {2}";
if (size == 0)
{
return string.Format(formatTemplate, null, 0, sizeSuffixes[0]);
}
var absSize = Math.Abs((double)size);
var fpPower = Math.Log(absSize, 1000);
var intPower = (int)fpPower;
var iUnit = intPower >= sizeSuffixes.Length
? sizeSuffixes.Length - 1
: intPower;
var normSize = absSize / Math.Pow(1000, iUnit);
return string.Format(
formatTemplate,
size < 0 ? "-" : null, normSize, sizeSuffixes[iUnit]);
}
}
下面是测试套件:
[TestFixture] public class ByteSize
{
[TestCase(0, Result="0 B")]
[TestCase(1, Result = "1 B")]
[TestCase(1000, Result = "1 KB")]
[TestCase(1500000, Result = "1.5 MB")]
[TestCase(-1000, Result = "-1 KB")]
[TestCase(int.MaxValue, Result = "2.1 GB")]
[TestCase(int.MinValue, Result = "-2.1 GB")]
[TestCase(long.MaxValue, Result = "9.2 EB")]
[TestCase(long.MinValue, Result = "-9.2 EB")]
public string Format_byte_size(long size)
{
return Format.ByteSize(size);
}
}
比如@NET3的解决方案。使用shift而不是除法来测试字节的范围,因为除法占用更多的CPU成本。
private static readonly string[] UNITS = new string[] { "B", "KB", "MB", "GB", "TB", "PB", "EB" };
public static string FormatSize(ulong bytes)
{
int c = 0;
for (c = 0; c < UNITS.Length; c++)
{
ulong m = (ulong)1 << ((c + 1) * 10);
if (bytes < m)
break;
}
double n = bytes / (double)((ulong)1 << (c * 10));
return string.Format("{0:0.##} {1}", n, UNITS[c]);
}