当路径中没有文件名时，我使用下面的代码片段获取路径的目录:

例如“c:\tmp\test\visual”;

string dir = @"c:\tmp\test\visual";
Console.WriteLine(dir.Replace(Path.GetDirectoryName(dir) + Path.DirectorySeparatorChar, ""));

输出:

视觉

下面的代码只帮助获取文件夹名称

 public ObservableCollection items = new ObservableCollection();

   try
            {
                string[] folderPaths = Directory.GetDirectories(stemp);
                items.Clear();
                foreach (string s in folderPaths)
                {
                    items.Add(new gridItems { foldername = s.Remove(0, s.LastIndexOf('\\') + 1), folderpath = s });

                }

            }
            catch (Exception a)
            {

            }
  public class gridItems
    {
        public string foldername { get; set; }
        public string folderpath { get; set; }
    }

DirectoryInfo执行剥离目录名的工作

string my_path = @"C:\Windows\System32";
DirectoryInfo dir_info = new DirectoryInfo(my_path);
string directory = dir_info.Name;  // System32

string Folder = Directory.GetParent(path).Name;

var fullPath = @"C:\folder1\folder2\file.txt";
var lastDirectory = Path.GetDirectoryName(fullPath).Split('\\').LastOrDefault();

简单干净。只使用System.IO.FileSystem -就像一个魅力:

string path = "C:/folder1/folder2/file.txt";
string folder = new DirectoryInfo(path).Name;