我有一个这样定义的枚举:
export enum GoalProgressMeasurements {
Percentage = 1,
Numeric_Target = 2,
Completed_Tasks = 3,
Average_Milestone_Progress = 4,
Not_Measured = 5
}
然而，我希望它被表示为一个对象数组/列表从我们的API如下:
[{id: 1, name: 'Percentage'},
{id: 2, name: 'Numeric Target'},
{id: 3, name: 'Completed Tasks'},
{id: 4, name: 'Average Milestone Progress'},
{id: 5, name: 'Not Measured'}]
是否有简单和本地的方法来做到这一点，或者我必须构建一个函数，将枚举转换为int和字符串，并将对象构建为数组?
当前回答
this worked for me :
export enum FeedBackType {
FEEDBACK1= 'FEEDBACK1',
FEEDBACK2= 'FEEDBACK2',
FEEDBACK3= 'FEEDBACK3',
}
-----------------------------------------------------------------
export function getTypeFeedBackList() {
let feedbackList: FeedBackType[] = [];
Object.keys(FeedBackType).map((key) => {
let strEnum = key as unknown as FeedBackType;
feedbackList.push(strEnum);
});
return feedbackList;
}
----------------------------------------------------------------
declare this :
public feedbackList: FeedBackType[] = [];
and after call your function in :
ngOnInit(): void {
this.feedbackList = getTypeFeedBackList();
console.log(this.feedbackList);
}
Happy coding ;)
其他回答
我已经解出来了。 假设您有一个如下所示的枚举
export enum UnitEnum {
GRAM = 'gm',
KILOGRAM = 'kg',
LITRE = 'lt',
CENTIMETER = 'cm',
INCH = 'in',
METER = 'mt',
KILOMETER = 'km',
}
你有这样一门课，
export interface Unit {
Name: string;
Symbol: string;
}
然后，您可以创建一个如下所示的函数，将异构枚举映射到某个类型的对象，
export function getDefaultUnits() {
const myUnits = Object.entries(UnitEnum).map(x => {
return { Name: x[0], Symbol: x[1] } as Unit
})
console.log(myUnits);
return myUnits;
}
枚举是运行时存在的真实对象。所以你可以这样反向映射:
let value = GoalProgressMeasurements.Not_Measured;
console.log(GoalProgressMeasurements[value]);
// => Not_Measured
基于此，您可以使用以下代码:
export enum GoalProgressMeasurements {
Percentage = 1,
Numeric_Target = 2,
Completed_Tasks = 3,
Average_Milestone_Progress = 4,
Not_Measured = 5
}
let map: {id: number; name: string}[] = [];
for(var n in GoalProgressMeasurements) {
if (typeof GoalProgressMeasurements[n] === 'number') {
map.push({id: <any>GoalProgressMeasurements[n], name: n});
}
}
console.log(map);
参考:https://www.typescriptlang.org/docs/handbook/enums.html
TS:
仅适用于短(<10个元素)enum
const keys = Object.keys(Enum).filter((el: string) => el.length > 1)
console.log(keys)
Object.keys()将返回一个包含['0'，'1'，'2'，'enumElement1'， 'enumElement2'， enumElement3']的数组 Filter()获取每个元素并检查其长度(因为字符串)，并从结果数组中排除所有数字
我是这样解的
const listKeys = Object.keys(TripStatus); //TripStatus is enum type
const numOfItem = listKeys.length/2;
for(let i=0; i<numOfItem; i++){
this.listStatus.push({
id: listKeys[i],
name: listKeys[numOfItem+i]
})
}
该方法基于语句: enum的键不能是数字
export const isNumeric = (num?: Value | null): num is number => {
if (num === undefined || num === null) {
return false;
}
const number = +num;
if (number - number !== 0) {
// Discard Infinity and NaN
return false;
}
if (number === num) {
return true;
}
if (typeof num === 'string') {
return !(number === 0 && num.trim() === '');
}
return false;
};
enum En {
ewq1 = 1,
we2 = 'ss',
sad = 'sad',
}
type TEnum = {
[id: string]: number | string;
}
export const getEnumValues = <T extends TEnum>(enumerable: T) =>
Object.keys(enumerable)
.filter((x) => !isNumeric(x))
.map((key) => enumerable[key] as T[keyof T])
console.log(getEnumValues(En)) // [1, "ss", "sad"]
