我有一个这样定义的枚举:

export enum GoalProgressMeasurements {
    Percentage = 1,
    Numeric_Target = 2,
    Completed_Tasks = 3,
    Average_Milestone_Progress = 4,
    Not_Measured = 5
}

然而,我希望它被表示为一个对象数组/列表从我们的API如下:

[{id: 1, name: 'Percentage'}, 
 {id: 2, name: 'Numeric Target'},
 {id: 3, name: 'Completed Tasks'},
 {id: 4, name: 'Average Milestone Progress'},
 {id: 5, name: 'Not Measured'}]

是否有简单和本地的方法来做到这一点,或者我必须构建一个函数,将枚举转换为int和字符串,并将对象构建为数组?


当前回答

 this worked for me :

    export enum FeedBackType {
    FEEDBACK1= 'FEEDBACK1',
    FEEDBACK2= 'FEEDBACK2',
    FEEDBACK3= 'FEEDBACK3',
    }

----------------------------------------------------------------- 
    export function getTypeFeedBackList() {
    let feedbackList: FeedBackType[] = [];
    Object.keys(FeedBackType).map((key) => {
    let strEnum = key as unknown as FeedBackType;
    feedbackList.push(strEnum);
    });
    return feedbackList;
    }
---------------------------------------------------------------- 
declare this :

    public feedbackList: FeedBackType[] = [];

and after call your function in  :

    ngOnInit(): void {
    this.feedbackList = getTypeFeedBackList();
    console.log(this.feedbackList); 
    }

Happy coding ;) 

其他回答

我很惊讶,在一个TypeScript线程中,没有人给出支持类型的有效TypeScript函数。下面是@user8363解决方案的变化:

const isStringNumber = (value: string) => isNaN(Number(value)) === false;

function enumToArray<T extends {}>(givenEnum: T) {
  return (Object.keys(givenEnum).filter(isStringNumber) as (keyof T)[]).map(
    (key) => givenEnum[key]
  );
}

设enum变量为:

 enum EnumName {
      A = 1,
      B = 2
    };

那么列表是:

const list = Object.keys(Enum)
.filter((value => isNaN(Number(value)) === false))
      .map(key => ({ id: key, value: Enum[key] }));

list的值为

list = [ 
{ id:1 , value: A },
{ id:2 , value: B },
];

enum目标进度测量{ 百分比= 1, Numeric_Target = 2, Completed_Tasks = 3, average_milestone one_progress = 4, Not_Measured = 5 } Const数组= [] for (const [key, value] of Object.entries(GoalProgressMeasurements)) { if (!Number. isnan (Number(key)) { 继续; } 数组中。Push ({id:值,名称:键。Replace ('_', ")}); } console.log(数组);

我已经解出来了。 假设您有一个如下所示的枚举

export enum UnitEnum {
  GRAM = 'gm',
  KILOGRAM = 'kg',
  LITRE = 'lt',
  CENTIMETER = 'cm',
  INCH = 'in',
  METER = 'mt',
  KILOMETER = 'km',
}

你有这样一门课,

export interface Unit {
  Name: string;
  Symbol: string;
}

然后,您可以创建一个如下所示的函数,将异构枚举映射到某个类型的对象,

export function getDefaultUnits() {
  const myUnits = Object.entries(UnitEnum).map(x => {
    return { Name: x[0], Symbol: x[1] } as Unit
  })

  console.log(myUnits);

  return myUnits;
}

我不喜欢上面的答案,因为它们都不能正确地处理字符串/数字的混合,可以在TypeScript enum中作为值。

下面的函数遵循TypeScript枚举的语义,给出键到值的正确映射。从那里,获取一个对象数组或者仅仅是键或者仅仅是值是很简单的。

/**
 * Converts the given enum to a map of the keys to the values.
 * @param enumeration The enum to convert to a map.
 */
function enumToMap(enumeration: any): Map<string, string | number> {
  const map = new Map<string, string | number>();
  for (let key in enumeration) {
      //TypeScript does not allow enum keys to be numeric
      if (!isNaN(Number(key))) continue;

      const val = enumeration[key] as string | number;

      //TypeScript does not allow enum value to be null or undefined
      if (val !== undefined && val !== null)
          map.set(key, val);
  }

  return map;
}

使用示例:

enum Dog {
    Rover = 1,
    Lassie = "Collie",
    Fido = 3,
    Cody = "Mutt",
}

let map = enumToMap(Dog); //Map of keys to values

let objs = Array.from(map.entries()).map(m => ({id: m[1], name: m[0]})); //Objects as asked for in OP
let entries = Array.from(map.entries()); //Array of each entry
let keys = Array.from(map.keys()); //An array of keys
let values = Array.from(map.values()); //An array of values

我还要指出OP是逆向思考枚举的。枚举中的“键”在技术上是在左边,而值在右边。TypeScript允许你尽可能多地重复RHS上的值。