Java 7+值得一试：

 Files.write(Paths.get("./output.txt"), "Information string herer".getBytes());

看起来很有希望。。。

请注意，下面的每个代码示例都可能引发IOException。为了简洁起见，省略了Try/catch/finally块。有关异常处理的信息，请参阅本教程。

请注意，如果文件已经存在，下面的每个代码示例都将覆盖该文件

创建文本文件：

PrintWriter writer = new PrintWriter("the-file-name.txt", "UTF-8");
writer.println("The first line");
writer.println("The second line");
writer.close();

创建二进制文件：

byte data[] = ...
FileOutputStream out = new FileOutputStream("the-file-name");
out.write(data);
out.close();

Java 7+用户可以使用Files类写入文件：

创建文本文件：

List<String> lines = Arrays.asList("The first line", "The second line");
Path file = Paths.get("the-file-name.txt");
Files.write(file, lines, StandardCharsets.UTF_8);
//Files.write(file, lines, StandardCharsets.UTF_8, StandardOpenOption.APPEND);

创建二进制文件：

byte data[] = ...
Path file = Paths.get("the-file-name");
Files.write(file, data);
//Files.write(file, data, StandardOpenOption.APPEND);

Use:

JFileChooser c = new JFileChooser();
c.showOpenDialog(c);
File writeFile = c.getSelectedFile();
String content = "Input the data here to be written to your file";

try {
    FileWriter fw = new FileWriter(writeFile);
    BufferedWriter bw = new BufferedWriter(fw);
    bw.append(content);
    bw.append("hiiiii");
    bw.close();
    fw.close();
}
catch (Exception exc) {
   System.out.println(exc);
}

package fileoperations;
import java.io.File;
import java.io.IOException;

public class SimpleFile {
    public static void main(String[] args) throws IOException {
        File file =new File("text.txt");
        file.createNewFile();
        System.out.println("File is created");
        FileWriter writer = new FileWriter(file);

        // Writes the content to the file
        writer.write("Enter the text that you want to write"); 
        writer.flush();
        writer.close();
        System.out.println("Data is entered into file");
    }
}

如果我们使用的是Java7及以上版本，并且还知道要添加（附加）到文件中的内容，我们可以使用NIO包中的newBufferedWriter方法。

public static void main(String[] args) {
    Path FILE_PATH = Paths.get("C:/temp", "temp.txt");
    String text = "\n Welcome to Java 8";

    //Writing to the file temp.txt
    try (BufferedWriter writer = Files.newBufferedWriter(FILE_PATH, StandardCharsets.UTF_8, StandardOpenOption.APPEND)) {
        writer.write(text);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

有几点需要注意：

指定字符集编码总是一个好习惯，因此我们在类StandardCharset中有常量。代码使用try with resource语句，其中资源在try之后自动关闭。

虽然OP没有询问，但为了以防万一我们想搜索具有特定关键字的行，例如机密，我们可以使用Java中的流API：

//Reading from the file the first line which contains word "confidential"
try {
    Stream<String> lines = Files.lines(FILE_PATH);
    Optional<String> containsJava = lines.filter(l->l.contains("confidential")).findFirst();
    if(containsJava.isPresent()){
        System.out.println(containsJava.get());
    }
} catch (IOException e) {
    e.printStackTrace();
}

我认为这是最短的路：

FileWriter fr = new FileWriter("your_file_name.txt"); // After '.' write
// your file extention (".txt" in this case)
fr.write("Things you want to write into the file"); // Warning: this will REPLACE your old file content!
fr.close();