在Javascript中伪造函数重载的最好方法是什么?

我知道在Javascript中不可能像在其他语言中那样重载函数。 如果我需要一个函数有两个使用foo(x)和foo(x,y,z),这是最好的/首选的方式:

一开始就用不同的名字 使用可选参数,如y = y || 'default' 使用参数数量 检查参数类型 还是如何?


当前回答

我不确定最佳实践,但我是这样做的:

/*
 * Object Constructor
 */
var foo = function(x) {
    this.x = x;
};

/*
 * Object Protoype
 */
foo.prototype = {
    /*
     * f is the name that is going to be used to call the various overloaded versions
     */
    f: function() {

        /*
         * Save 'this' in order to use it inside the overloaded functions
         * because there 'this' has a different meaning.
         */   
        var that = this;  

        /* 
         * Define three overloaded functions
         */
        var f1 = function(arg1) {
            console.log("f1 called with " + arg1);
            return arg1 + that.x;
        }

        var f2 = function(arg1, arg2) {
             console.log("f2 called with " + arg1 + " and " + arg2);
             return arg1 + arg2 + that.x;
        }

        var f3 = function(arg1) {
             console.log("f3 called with [" + arg1[0] + ", " + arg1[1] + "]");
             return arg1[0] + arg1[1];
        }

        /*
         * Use the arguments array-like object to decide which function to execute when calling f(...)
         */
        if (arguments.length === 1 && !Array.isArray(arguments[0])) {
            return f1(arguments[0]);
        } else if (arguments.length === 2) {
            return f2(arguments[0], arguments[1]);
        } else if (arguments.length === 1 && Array.isArray(arguments[0])) {
            return f3(arguments[0]);
        }
    } 
}

/* 
 * Instantiate an object
 */
var obj = new foo("z");

/*
 * Call the overloaded functions using f(...)
 */
console.log(obj.f("x"));         // executes f1, returns "xz"
console.log(obj.f("x", "y"));    // executes f2, returns "xyz"
console.log(obj.f(["x", "y"]));  // executes f3, returns "xy"

其他回答

看看这个。它很酷。 http://ejohn.org/blog/javascript-method-overloading/ 技巧Javascript,让你做这样的调用:

var users = new Users();
users.find(); // Finds all
users.find("John"); // Finds users by name
users.find("John", "Resig"); // Finds users by first and last name

对于你的用例,这是我用ES6解决它的方法(因为它已经是2017年底了):

const foo = (x, y, z) => {
  if (y && z) {
    // Do your foo(x, y, z); functionality
    return output;
  }
  // Do your foo(x); functionality
  return output;
}

显然,您可以将其用于任何数量的参数,并相应地更改条件语句。

在JS中没有实际的重载,无论如何我们仍然可以用几种方式模拟方法重载:

方法# 1: 使用对象

function test(x,options){
  if("a" in options)doSomething();
  else if("b" in options)doSomethingElse();
}
test("ok",{a:1});
test("ok",{b:"string"});

方法# 2: 使用rest (spread)参数

function test(x,...p){
 if(p[2])console.log("3 params passed"); //or if(typeof p[2]=="string")
else if (p[1])console.log("2 params passed");
else console.log("1 param passed");
}

方法# 3: 使用未定义的

function test(x, y, z){
 if(typeof(z)=="undefined")doSomething();
}

方法# 4: 类型检查

function test(x){
 if(typeof(x)=="string")console.log("a string passed")
 else ...
}

这是一个老问题,但我认为需要另一个条目(尽管我怀疑是否有人会读它)。立即调用函数表达式(IIFE)的使用可以与闭包和内联函数结合使用,以允许函数重载。考虑以下(人为的)例子:

var foo;

// original 'foo' definition
foo = function(a) {
  console.log("a: " + a);
}

// define 'foo' to accept two arguments
foo = (function() {
  // store a reference to the previous definition of 'foo'
  var old = foo;

  // use inline function so that you can refer to it internally
  return function newFoo(a,b) {

    // check that the arguments.length == the number of arguments 
    // defined for 'newFoo'
    if (arguments.length == newFoo.length) {
      console.log("a: " + a);
      console.log("b: " + b);

    // else if 'old' is a function, apply it to the arguments
    } else if (({}).toString.call(old) === '[object Function]') {
      old.apply(null, arguments);
    }
  }
})();

foo(1);
> a: 1
foo(1,2);
> a: 1
> b: 2
foo(1,2,3)
> a: 1

简而言之,IIFE的使用创建了一个局部作用域,允许我们定义私有变量old来存储对函数foo的初始定义的引用。这个函数然后返回一个内联函数newFoo,如果传递给它的恰好是两个参数a和b,或者调用旧函数if参数,则该函数将记录两个参数的内容。长度!== 2。此模式可以重复任意次数,以赋予一个变量若干不同的函数定义。

我不确定最佳实践,但我是这样做的:

/*
 * Object Constructor
 */
var foo = function(x) {
    this.x = x;
};

/*
 * Object Protoype
 */
foo.prototype = {
    /*
     * f is the name that is going to be used to call the various overloaded versions
     */
    f: function() {

        /*
         * Save 'this' in order to use it inside the overloaded functions
         * because there 'this' has a different meaning.
         */   
        var that = this;  

        /* 
         * Define three overloaded functions
         */
        var f1 = function(arg1) {
            console.log("f1 called with " + arg1);
            return arg1 + that.x;
        }

        var f2 = function(arg1, arg2) {
             console.log("f2 called with " + arg1 + " and " + arg2);
             return arg1 + arg2 + that.x;
        }

        var f3 = function(arg1) {
             console.log("f3 called with [" + arg1[0] + ", " + arg1[1] + "]");
             return arg1[0] + arg1[1];
        }

        /*
         * Use the arguments array-like object to decide which function to execute when calling f(...)
         */
        if (arguments.length === 1 && !Array.isArray(arguments[0])) {
            return f1(arguments[0]);
        } else if (arguments.length === 2) {
            return f2(arguments[0], arguments[1]);
        } else if (arguments.length === 1 && Array.isArray(arguments[0])) {
            return f3(arguments[0]);
        }
    } 
}

/* 
 * Instantiate an object
 */
var obj = new foo("z");

/*
 * Call the overloaded functions using f(...)
 */
console.log(obj.f("x"));         // executes f1, returns "xz"
console.log(obj.f("x", "y"));    // executes f2, returns "xyz"
console.log(obj.f(["x", "y"]));  // executes f3, returns "xy"