如果JavaScript中未定义变量,最合适的测试方法是什么?

我见过几种可能的方法:

if (window.myVariable)

Or

if (typeof(myVariable) != "undefined")

Or

if (myVariable) // This throws an error if undefined. Should this be in Try/Catch?

当前回答

与@Thomas Eding的回答相反:

如果我忘记在代码中声明myVar,那么我将得到myVar未定义。

让我们举一个真实的例子:

我有一个变量名,但我不确定它是否在某处声明。

那么@Anurak的回答会有所帮助:

var myVariableToCheck = 'myVar';
if (window[myVariableToCheck] === undefined)
    console.log("Not declared or declared, but undefined.");

// Or you can check it directly 
if (window['myVar'] === undefined) 
    console.log("Not declared or declared, but undefined.");

其他回答

由于其他答案对我都没有帮助,我建议这样做。它在Internet Explorer 8中对我有效:

if (typeof variable_name.value === 'undefined') {
    // variable_name is undefined
}
    var x;
    if (x === undefined) {
        alert ("I am declared, but not defined.")
    };
    if (typeof y === "undefined") {
        alert ("I am not even declared.")
    };

    /* One more thing to understand: typeof ==='undefined' also checks 
       for if a variable is declared, but no value is assigned. In other 
       words, the variable is declared, but not defined. */

    // Will repeat above logic of x for typeof === 'undefined'
    if (x === undefined) {
        alert ("I am declared, but not defined.")
    };
    /* So typeof === 'undefined' works for both, but x === undefined 
       only works for a variable which is at least declared. */

    /* Say if I try using typeof === undefined (not in quotes) for 
       a variable which is not even declared, we will get run a 
       time error. */

    if (z === undefined) {
        alert ("I am neither declared nor defined.")
    };
    // I got this error for z ReferenceError: z is not defined 

您可以使用typeof,如下所示:

if (typeof something != "undefined") {
    // ...
}

我知道检查undefined最可靠的方法是使用void 0。

这与较新和较旧的浏览器都兼容,并且不能像window那样被覆盖。在某些情况下,未定义的浏览器可以被覆盖。

if( myVar === void 0){
    //yup it's undefined
}

我使用它作为函数参数,并在函数执行时排除它,这样我就得到了未定义的“真实”。尽管它确实需要您将代码放在函数中。我在阅读jQuery源代码时发现了这一点。

undefined = 2;

(function (undefined) {
   console.log(undefined); // prints out undefined
   // and for comparison:
   if (undeclaredvar === undefined) console.log("it works!")
})()

当然,你可以使用typeof。但无论如何,我的所有代码通常都在一个包含函数中,所以使用这个方法可能会在这里和那里节省一些字节。