如何找到本地IP地址(即192.168.x。x或10.0.x.x)在Python平台独立,只使用标准库?


当前回答

我决定使用ipfy: https://www.ipify.org的服务和/或API。

#!/usr/bin/env python3
from urllib.request import urlopen


def public_ip():
    data = urlopen('https://api.ipify.org').read()
    return str(data, encoding='utf-8')


print(public_ip())

还可以以JSON和JSONP格式获得响应。

Github上有一个ipify Python库。

其他回答

Socket API方法

参见https://stackoverflow.com/a/28950776/711085

缺点:

Not cross-platform. Requires more fallback code, tied to existence of particular addresses on the internet This will also not work if you're behind a NAT Probably creates a UDP connection, not independent of (usually ISP's) DNS availability (see other answers for ideas like using 8.8.8.8: Google's (coincidentally also DNS) server) Make sure you make the destination address UNREACHABLE, like a numeric IP address that is spec-guaranteed to be unused. Do NOT use some domain like fakesubdomain.google.com or somefakewebsite.com; you'll still be spamming that party (now or in the future), and spamming your own network boxes as well in the process.


反射器方法

(请注意,这并没有回答OP的本地IP地址问题,例如192.168…;它会给你你的公共IP地址,根据用例,这可能更可取。)

你可以查询一些网站,如whatismyip.com(但有一个API),例如:

from urllib.request import urlopen
import re
def getPublicIp():
    data = str(urlopen('http://checkip.dyndns.com/').read())
    # data = '<html><head><title>Current IP Check</title></head><body>Current IP Address: 65.96.168.198</body></html>\r\n'

    return re.compile(r'Address: (\d+\.\d+\.\d+\.\d+)').search(data).group(1)

或者如果使用python2:

from urllib import urlopen
import re
def getPublicIp():
    data = str(urlopen('http://checkip.dyndns.com/').read())
    # data = '<html><head><title>Current IP Check</title></head><body>Current IP Address: 65.96.168.198</body></html>\r\n'

    return re.compile(r'Address: (\d+\.\d+\.\d+\.\d+)').search(data).group(1)

优点:

这种方法的一个优点是它是跨平台的 它从丑陋的nat(例如你的家用路由器)后面工作。

缺点(和变通方法):

要求网站正常运行,格式不变(几乎肯定不会),DNS服务器正常工作。在失败的情况下,还可以通过查询其他第三方IP地址反射器来缓解这个问题。 如果您不查询多个反射器(以防止一个受损害的反射器告诉您您的地址不是某个东西),或者如果您不使用HTTPS(以防止假装是服务器的中间人攻击),则可能的攻击向量


edit: Though initially I thought these methods were really bad (unless you use many fallbacks, the code may be irrelevant many years from now), it does pose the question "what is the internet?". A computer may have many interfaces pointing to many different networks. For a more thorough description of the topic, google for gateways and routes. A computer may be able to access an internal network via an internal gateway, or access the world-wide web via a gateway on for example a router (usually the case). The local IP address that the OP asks about is only well-defined with respect to a single link layer, so you have to specify that ("is it the network card, or the ethernet cable, which we're talking about?"). There may be multiple non-unique answers to this question as posed. However the global IP address on the world-wide web is probably well-defined (in the absence of massive network fragmentation): probably the return path via the gateway which can access the TLDs.

127.0.1.1是您的真实IP地址。更一般地说,一台计算机可以有任意数量的IP地址。您可以过滤它们为私有网络- 127.0.0.0/8,10.0.0.0/8,172.16.0.0/12和192.168.0.0/16。

但是,没有跨平台的方法来获取所有的IP地址。在Linux上,可以使用SIOCGIFCONF ioctl。

在Debian上(经过测试),我怀疑大多数Linux ..

import commands

RetMyIP = commands.getoutput("hostname -I")

在MS Windows上(已测试)

import socket

socket.gethostbyname(socket.gethostname())

如果你正在寻找与本地主机IP地址127.0.0.1不同的IPV4地址,这里有一段简洁的python代码:

import subprocess
address = subprocess.check_output(['hostname', '-s', '-I'])
address = address.decode('utf-8') 
address=address[:-1]

也可以写成一行:

address = subprocess.check_output(['hostname', '-s', '-I']).decode('utf-8')[:-1]

即使您将localhost放在/etc/hostname中,代码仍然会给出本地IP地址。

from netifaces import interfaces, ifaddresses, AF_INET
iplist = [ifaddresses(face)[AF_INET][0]["addr"] for face in interfaces() if AF_INET in ifaddresses(face)]
print(iplist)
['10.8.0.2', '192.168.1.10', '127.0.0.1']