我有下面的数组
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
我想从数组中删除空白元素，并希望得到以下结果:
cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]
有没有像compact这样不需要循环的方法?
当前回答
试试这个:
puts ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"] - [""]
其他回答
试试这个:
puts ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"] - [""]
删除空值:
['a', nil, 'b'].compact ## o/p => ["a", "b"]
删除空字符串:
['a', 'b', ''].select{ |a| !a.empty? } ## o/p => ["a", "b"]
删除空字符串和空字符串:
['a', nil, 'b', ''].select{ |a| a.present? } ## o/p => ["a", "b"]
使用严格的join & split更新
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
cities.join(' ').split
结果将是:
["Kathmandu", "Pokhara", "Dharan", "Butwal"]
注意:这对有空间的城市不起作用
cities.reject! { |c| c.blank? }
为什么要用空白?在空的吗?blank可以识别nil，空字符串和空白。例如:
cities = ["Kathmandu", "Pokhara", " ", nil, "", "Dharan", "Butwal"].reject { |c| c.blank? }
仍然会返回:
["Kathmandu", "Pokhara", "Dharan", "Butwal"]
叫空?On " "将返回false，您可能希望它为true。
注:空白?只能通过Rails访问，Ruby只支持空?
有很多方法可以做到这一点，其中之一是拒绝
noEmptyCities = cities.reject { |c| c.empty? }
你也可以用reject!，这将改变城市的位置。如果拒绝某项，它将返回cities作为返回值，如果没有拒绝，则返回nil。如果你不小心，这可能是一个陷阱(感谢ninja08在评论中指出这一点)。
