我有下面的数组
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
我想从数组中删除空白元素，并希望得到以下结果:
cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]
有没有像compact这样不需要循环的方法?
当前回答
试试这个:
puts ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"] - [""]
其他回答
纯Ruby:
values = [1,2,3, " ", "", "", nil] - ["", " ", nil]
puts values # [1,2,3]
1.9.3p194 :001 > ["", "A", "B", "C", ""].reject(&:empty?)
=> ["A", "B", "C"]
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].delete_if {|c| c.empty? }
以下是对我有效的方法:
[1, "", 2, "hello", nil].reject(&:blank?)
输出:
[1, 2, "hello"]
另一种方法:
> ["a","b","c","","","f","g"].keep_if{|some| some.present?}
=> ["a","b","c","f","g"]
