我有下面的数组
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
我想从数组中删除空白元素，并希望得到以下结果:
cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]
有没有像compact这样不需要循环的方法?
当前回答
已经有很多答案了，但如果你在Rails世界里，这里有另一种方法:
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].select &:present?
其他回答
纯Ruby:
values = [1,2,3, " ", "", "", nil] - ["", " ", nil]
puts values # [1,2,3]
有很多方法可以做到这一点，其中之一是拒绝
noEmptyCities = cities.reject { |c| c.empty? }
你也可以用reject!，这将改变城市的位置。如果拒绝某项，它将返回cities作为返回值，如果没有拒绝，则返回nil。如果你不小心，这可能是一个陷阱(感谢ninja08在评论中指出这一点)。
使用严格的join & split更新
cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]
cities.join(' ').split
结果将是:
["Kathmandu", "Pokhara", "Dharan", "Butwal"]
注意:这对有空间的城市不起作用
以下是对我有效的方法:
[1, "", 2, "hello", nil].reject(&:blank?)
输出:
[1, 2, "hello"]
使用拒绝:
>> cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].reject{ |e| e.empty? }
=> ["Kathmandu", "Pokhara", "Dharan", "Butwal"]
