如何从数组中删除空白元素?

我有下面的数组

cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"]

我想从数组中删除空白元素，并希望得到以下结果:

cities = ["Kathmandu", "Pokhara", "Dharan", "Butwal"]

有没有像compact这样不需要循环的方法?

当前回答

这里还有一种方法可以实现这一点

我们可以使用presence和select

cities = ["Kathmandu", "Pokhara", "", "Dharan", nil, "Butwal"]

cities.select(&:presence)

["Kathmandu", "Pokhara", "Dharan", "Butwal"]

其他回答

1.9.3p194 :001 > ["", "A", "B", "C", ""].reject(&:empty?)

=> ["A", "B", "C"]

 cities = ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"].delete_if {|c| c.empty? }

纯Ruby:

values = [1,2,3, " ", "", "", nil] - ["", " ", nil]
puts values # [1,2,3]

如果你的数组中有混合类型，下面是一个解决方案:

[nil,"some string here","",4,3,2]

解决方案:

[nil,"some string here","",4,3,2].compact.reject{|r| r.empty? if r.class == String}

输出:

=> ["some string here", 4, 3, 2]

试试这个:

puts ["Kathmandu", "Pokhara", "", "Dharan", "Butwal"] - [""]

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