如何在Django中获取用户的IP ?
我的观点是这样的:
# Create your views
from django.contrib.gis.utils import GeoIP
from django.template import RequestContext
from django.shortcuts import render_to_response
def home(request):
g = GeoIP()
client_ip = request.META['REMOTE_ADDR']
lat,long = g.lat_lon(client_ip)
return render_to_response('home_page_tmp.html',locals())
但是我得到了这个错误:
KeyError at /mypage/
'REMOTE_ADDR'
Request Method: GET
Request URL: http://mywebsite.example/mypage/
Django Version: 1.2.4
Exception Type: KeyError
Exception Value:
'REMOTE_ADDR'
Exception Location: /mysite/homepage/views.py in home, line 9
Python Executable: /usr/bin/python
Python Version: 2.6.6
Python Path: ['/mysite', '/usr/local/lib/python2.6/dist-packages/flup-1.0.2-py2.6.egg', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/local/lib/python2.6/dist-packages', '/usr/lib/python2.6/dist-packages', '/usr/lib/pymodules/python2.6']
Server time: Sun, 2 Jan 2011 20:42:50 -0600
我在上面的回答中也缺少了代理。我使用get_ip_address_from_request from django_easy_timezones。
from easy_timezones.utils import get_ip_address_from_request, is_valid_ip, is_local_ip
ip = get_ip_address_from_request(request)
try:
if is_valid_ip(ip):
geoip_record = IpRange.objects.by_ip(ip)
except IpRange.DoesNotExist:
return None
这里是方法get_ip_address_from_request, IPv4和IPv6就绪:
def get_ip_address_from_request(request):
""" Makes the best attempt to get the client's real IP or return the loopback """
PRIVATE_IPS_PREFIX = ('10.', '172.', '192.', '127.')
ip_address = ''
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR', '')
if x_forwarded_for and ',' not in x_forwarded_for:
if not x_forwarded_for.startswith(PRIVATE_IPS_PREFIX) and is_valid_ip(x_forwarded_for):
ip_address = x_forwarded_for.strip()
else:
ips = [ip.strip() for ip in x_forwarded_for.split(',')]
for ip in ips:
if ip.startswith(PRIVATE_IPS_PREFIX):
continue
elif not is_valid_ip(ip):
continue
else:
ip_address = ip
break
if not ip_address:
x_real_ip = request.META.get('HTTP_X_REAL_IP', '')
if x_real_ip:
if not x_real_ip.startswith(PRIVATE_IPS_PREFIX) and is_valid_ip(x_real_ip):
ip_address = x_real_ip.strip()
if not ip_address:
remote_addr = request.META.get('REMOTE_ADDR', '')
if remote_addr:
if not remote_addr.startswith(PRIVATE_IPS_PREFIX) and is_valid_ip(remote_addr):
ip_address = remote_addr.strip()
if not ip_address:
ip_address = '127.0.0.1'
return ip_address
我想对yanchenko的回答提出一个改进。
而不是在X_FORWARDED_FOR列表中取第一个ip，我取第一个不知道内部ip，因为一些路由器不尊重协议，你可以看到内部ip作为列表的第一个值。
PRIVATE_IPS_PREFIX = ('10.', '172.', '192.', )
def get_client_ip(request):
"""get the client ip from the request
"""
remote_address = request.META.get('REMOTE_ADDR')
# set the default value of the ip to be the REMOTE_ADDR if available
# else None
ip = remote_address
# try to get the first non-proxy ip (not a private ip) from the
# HTTP_X_FORWARDED_FOR
x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
if x_forwarded_for:
proxies = x_forwarded_for.split(',')
# remove the private ips from the beginning
while (len(proxies) > 0 and
proxies[0].startswith(PRIVATE_IPS_PREFIX)):
proxies.pop(0)
# take the first ip which is not a private one (of a proxy)
if len(proxies) > 0:
ip = proxies[0]
return ip
我希望这能帮助那些有同样问题的谷歌同事。
django。版本
(2,1,1， 'final'， 0)
请求处理程序
sock=request._stream.stream.raw._sock
#<socket.socket fd=1236, family=AddressFamily.AF_INET, type=SocketKind.SOCK_STREAM, proto=0, laddr=('192.168.1.111', 8000), raddr=('192.168.1.111', 64725)>
client_ip,port=sock.getpeername()
如果你调用以上代码两次，你可能会得到
AttributeError(“_io。BytesIO的对象没有属性“stream”
AttributeError("'LimitedStream'对象没有'raw'属性")
