如何在Python中连接两个列表?
例子:
listone = [1, 2, 3]
listtwo = [4, 5, 6]
预期结果:
>>> joinedlist
[1, 2, 3, 4, 5, 6]
如何在Python中连接两个列表?
例子:
listone = [1, 2, 3]
listtwo = [4, 5, 6]
预期结果:
>>> joinedlist
[1, 2, 3, 4, 5, 6]
当前回答
如果要以排序形式合并这两个列表,可以使用heapq库中的merge函数。
from heapq import merge
a = [1, 2, 4]
b = [2, 4, 6, 7]
print list(merge(a, b))
其他回答
使用简单的列表理解:
joined_list = [item for list_ in [list_one, list_two] for item in list_]
它具有使用Additional Unpacking Generalization的最新方法的所有优点-即,您可以以这种方式连接任意数量的不同可迭代项(例如,列表、元组、范围和生成器)-并且它不限于Python 3.5或更高版本。
您可以使用在列表对象上定义的append()方法:
mergedlist =[]
for elem in listone:
mergedlist.append(elem)
for elem in listtwo:
mergedlist.append(elem)
a = [1, 2, 3]
b = [4, 5, 6]
c = a + b
print(c)
输出
>>> [1, 2, 3, 4, 5, 6]
在上面的代码中,“+”运算符用于将两个列表连接成一个列表。
另一种解决方案
a = [1, 2, 3]
b = [4, 5, 6]
c = [] # Empty list in which we are going to append the values of list (a) and (b)
for i in a:
c.append(i)
for j in b:
c.append(j)
print(c)
输出
>>> [1, 2, 3, 4, 5, 6]
值得注意的是,itertools.chain函数接受可变数量的参数:
>>> l1 = ['a']; l2 = ['b', 'c']; l3 = ['d', 'e', 'f']
>>> [i for i in itertools.chain(l1, l2)]
['a', 'b', 'c']
>>> [i for i in itertools.chain(l1, l2, l3)]
['a', 'b', 'c', 'd', 'e', 'f']
如果输入是可迭代的(元组、列表、生成器等),则可以使用from_iteable类方法:
>>> il = [['a'], ['b', 'c'], ['d', 'e', 'f']]
>>> [i for i in itertools.chain.from_iterable(il)]
['a', 'b', 'c', 'd', 'e', 'f']
这很简单,我认为它甚至在教程中显示了:
>>> listone = [1,2,3]
>>> listtwo = [4,5,6]
>>>
>>> listone + listtwo
[1, 2, 3, 4, 5, 6]