当手动生成JSON对象或数组时,通常更容易在对象或数组的最后一项上留下逗号。例如,从字符串数组输出的代码可能像这样(在c++中像伪代码):
s.append("[");
for (i = 0; i < 5; ++i) {
s.appendF("\"%d\",", i);
}
s.append("]");
给你一个字符串
[0,1,2,3,4,5,]
这是允许的吗?
当手动生成JSON对象或数组时,通常更容易在对象或数组的最后一项上留下逗号。例如,从字符串数组输出的代码可能像这样(在c++中像伪代码):
s.append("[");
for (i = 0; i < 5; ++i) {
s.appendF("\"%d\",", i);
}
s.append("]");
给你一个字符串
[0,1,2,3,4,5,]
这是允许的吗?
当前回答
String l = "[" + List<int>.generate(5, (i) => i + 1).join(",") + "]";
其他回答
PHP程序员可能需要检查implode()。它接受一个数组,使用字符串将其连接起来。
从医生那里…
$array = array('lastname', 'email', 'phone');
echo implode(",", $array); // lastname,email,phone
Using a trailing comma is not allowed for json. A solution I like, which you could do if you're not writing for an external recipient but for your own project, is to just strip (or replace by whitespace) the trailing comma on the receiving end before feeding it to the json parser. I do this for the trailing comma in the outermost json object. The convenient thing is then if you add an object at the end, you don't have to add a comma to the now second last object. This also makes for cleaner diffs if your config file is in a version control system, since it will only show the lines of the stuff you actually added.
char* str = readFile("myConfig.json");
char* chr = strrchr(str, '}') - 1;
int i = 0;
while( chr[i] == ' ' || chr[i] == '\n' ){
i--;
}
if( chr[i] == ',' ) chr[i] = ' ';
JsonParser parser;
parser.parse(str);
不。在http://json.org中维护的JSON规范不允许后面有逗号。据我所知,一些解析器在读取JSON字符串时可能会默默地允许它们,而其他解析器则会抛出错误。对于互操作性,不应该包含它。
上面的代码可以重新构造,可以在添加数组结束符时删除后面的逗号,也可以在项之前添加逗号,对第一个项跳过逗号。
String l = "[" + List<int>.generate(5, (i) => i + 1).join(",") + "]";
我保持当前的计数,并将其与总计数进行比较。如果当前计数小于总计数,则显示逗号。
如果在执行JSON生成之前没有总计数,则可能无法工作。
同样,如果您使用的是PHP 5.2.0或更高版本,则可以使用内置的JSON API格式化响应。