给定一个这样的字符串:

"The dog      has a long   tail, and it     is RED!"

什么样的jQuery或JavaScript魔法可以用来保持空间只有一个最大空间?

目标:

"The dog has a long tail, and it is RED!"

当前回答

var myregexp = new RegExp(/ {2,}/g);

str = str.replace(myregexp,' ');

其他回答

let nameCorrection = function (str) {
  let strPerfect = str.replace(/\s+/g, " ").trim();
  let strSmall = strPerfect.toLowerCase();
  let arrSmall = strSmall.split(" ");
  let arrCapital = [];
  for (let x of arrSmall.values()) {
    arrCapital.push(x[0].toUpperCase() + x.slice(1));
  }

  let result = arrCapital.join(" ");
  console.log(result);
};
nameCorrection("Pradeep kumar dHital");

我知道我迟到了,但我发现了一个很好的解决方案。

下面就是:

var myStr = myStr.replace(/[ ][ ]*/g, ' ');

以下是对我来说很有效的解决方案:

var text = “ Tes ddas dMd WAlkman 3Dsfd ” .toLowerCase() .replace(/\b\s+/g, “ ”) .replace(/\b\w/g, s => s.toUpperCase()) .trimStart() .trimEnd(); 控制台.log(文本); 结果: Tes Ddas Dmd 随身听 3dsfd

var str = "The      dog        has a long tail,      and it is RED!";
str = str.replace(/ {2,}/g,' ');

编辑: 如果你想替换所有类型的空白字符,最有效的方法是这样的:

str = str.replace(/\s{2,}/g,' ');

这个脚本删除了单词和修饰之间的任何空白(多个空格,制表符,返回值等):

// Trims & replaces any wihtespacing to single space between words
String.prototype.clearExtraSpace = function(){
  var _trimLeft  = /^\s+/,
      _trimRight = /\s+$/,
      _multiple  = /\s+/g;

  return this.replace(_trimLeft, '').replace(_trimRight, '').replace(_multiple, ' ');
};