如何在JavaScript中将字符串编码为Base64 ?

我有一个PHP脚本，可以将PNG图像编码为Base64字符串。

我想用JavaScript做同样的事情。我知道如何打开文件，但我不知道如何进行编码。我不习惯使用二进制数据。

当前回答

如果有人想在Typescript中将一个字符串编码为base64

我调整了Peter Mortensen的答案并添加了类型(在需要的地方)

const Base64 = {


_keyStr: "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",

// added type string to input
encode: function(input: string) {
    let output = "";
    let chr1, chr2, chr3, enc1, enc2, enc3, enc4;
    let i = 0;

    input = Base64._utf8_encode(input);

    while (i < input.length) {

        chr1 = input.charCodeAt(i++);
        chr2 = input.charCodeAt(i++);
        chr3 = input.charCodeAt(i++);

        enc1 = chr1 >> 2;
        enc2 = ((chr1 & 3) << 4) | (chr2 >> 4);
        enc3 = ((chr2 & 15) << 2) | (chr3 >> 6);
        enc4 = chr3 & 63;

        if (isNaN(chr2)) {
            enc3 = enc4 = 64;
        } else if (isNaN(chr3)) {
            enc4 = 64;
        }

        output = output + this._keyStr.charAt(enc1) + this._keyStr.charAt(enc2) + this._keyStr.charAt(enc3) + this._keyStr.charAt(enc4);

    }

    return output;
},
// added type string to input
_utf8_encode: function(input: string) {
    input= input.replace(/\r\n/g, "\n");
    let utftext = "";

    for (let n = 0; n < input.length; n++) {

        let c = input.charCodeAt(n);

        if (c < 128) {
            utftext += String.fromCharCode(c);
        }
        else if ((c > 127) && (c < 2048)) {
            utftext += String.fromCharCode((c >> 6) | 192);
            utftext += String.fromCharCode((c & 63) | 128);
        }
        else {
            utftext += String.fromCharCode((c >> 12) | 224);
            utftext += String.fromCharCode(((c >> 6) & 63) | 128);
            utftext += String.fromCharCode((c & 63) | 128);
        }

    }

    return utftext;
  },
}
 
// function that consumes that Base64.encode function
const encode = ( cipher : string) => {

  const encodedString: string = Base64.encode(cipher)

  return encodedString;
}

console.log(encode('Hello World!'))

JSFIDDLE 链接

2022-03-30 07:10:42

其他回答

Sunny的代码很棒，只是因为引用了“this”而在Internet Explorer 7中崩溃了。通过将这些引用替换为"Base64"来修复:

var Base64 = {
    // private property
    _keyStr : "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",

    // public method for encoding
    encode : function (input) {
        var output = "";
        var chr1, chr2, chr3, enc1, enc2, enc3, enc4;
        var i = 0;

        input = Base64._utf8_encode(input);

        while (i < input.length) {

            chr1 = input.charCodeAt(i++);
            chr2 = input.charCodeAt(i++);
            chr3 = input.charCodeAt(i++);

            enc1 = chr1 >> 2;
            enc2 = ((chr1 & 3) << 4) | (chr2 >> 4);
            enc3 = ((chr2 & 15) << 2) | (chr3 >> 6);
            enc4 = chr3 & 63;

            if (isNaN(chr2)) {
                enc3 = enc4 = 64;
            } else if (isNaN(chr3)) {
                enc4 = 64;
            }

            output = output +
            Base64._keyStr.charAt(enc1) + Base64._keyStr.charAt(enc2) +
            Base64._keyStr.charAt(enc3) + Base64._keyStr.charAt(enc4);
        }

        return output;
    },

    // public method for decoding
    decode : function (input) {
        var output = "";
        var chr1, chr2, chr3;
        var enc1, enc2, enc3, enc4;
        var i = 0;

        input = input.replace(/[^A-Za-z0-9\+\/\=]/g, "");

        while (i < input.length) {

            enc1 = Base64._keyStr.indexOf(input.charAt(i++));
            enc2 = Base64._keyStr.indexOf(input.charAt(i++));
            enc3 = Base64._keyStr.indexOf(input.charAt(i++));
            enc4 = Base64._keyStr.indexOf(input.charAt(i++));

            chr1 = (enc1 << 2) | (enc2 >> 4);
            chr2 = ((enc2 & 15) << 4) | (enc3 >> 2);
            chr3 = ((enc3 & 3) << 6) | enc4;

            output = output + String.fromCharCode(chr1);

            if (enc3 != 64) {
                output = output + String.fromCharCode(chr2);
            }
            if (enc4 != 64) {
                output = output + String.fromCharCode(chr3);
            }
        }

        output = Base64._utf8_decode(output);

        return output;
    },

    // private method for UTF-8 encoding
    _utf8_encode : function (string) {
        string = string.replace(/\r\n/g,"\n");
        var utftext = "";

        for (var n = 0; n < string.length; n++) {

            var c = string.charCodeAt(n);

            if (c < 128) {
                utftext += String.fromCharCode(c);
            }
            else if((c > 127) && (c < 2048)) {
                utftext += String.fromCharCode((c >> 6) | 192);
                utftext += String.fromCharCode((c & 63) | 128);
            }
            else {
                utftext += String.fromCharCode((c >> 12) | 224);
                utftext += String.fromCharCode(((c >> 6) & 63) | 128);
                utftext += String.fromCharCode((c & 63) | 128);
            }
        }
        return utftext;
    },

    // private method for UTF-8 decoding
    _utf8_decode : function (utftext) {
        var string = "";
        var i = 0;
        var c = c1 = c2 = 0;

        while ( i < utftext.length ) {

            c = utftext.charCodeAt(i);

            if (c < 128) {
                string += String.fromCharCode(c);
                i++;
            }
            else if((c > 191) && (c < 224)) {
                c2 = utftext.charCodeAt(i+1);
                string += String.fromCharCode(((c & 31) << 6) | (c2 & 63));
                i += 2;
            }
            else {
                c2 = utftext.charCodeAt(i+1);
                c3 = utftext.charCodeAt(i+2);
                string += String.fromCharCode(((c & 15) << 12) | ((c2 & 63) << 6) | (c3 & 63));
                i += 3;
            }
        }
        return string;
    }
}

2011-07-18 22:08:34

当我使用

btoa("☸☹☺☻☼☾☿"))

我得到:

InvalidCharacterError:要编码的字符串包含Latin1范围之外的字符。

我发现文档，Unicode字符串，提供了一个解决方案如下。

2021-05-06 09:47:44

这里的所有解决方案在某些情况下似乎都失败了，而且理解起来相当复杂。特别是对于非拉丁语言，如阿拉伯语

这里有一个解码UTF-16的简短解决方案

//decodes utf-16 characters such as ARABIC, URDU,PASHTO text
function decodeBase64(s) {
    var percentEncodedStr = atob(s).split('').map(function (c) {
        return '%' + ('00' + c.charCodeAt(0).toString(16)).slice(-2);
    }).join('');
    return decodeURIComponent(percentEncodedStr);
}

2022-01-28 12:16:27

2022年弃用警告更新

我在我的vscode上看到了弃用警告

This function is only provided for compatibility with legacy web platform APIs and should never be used in new code, 
because they use strings to represent binary data and predate the introduction of typed arrays in JavaScript. 
For code running using Node.js APIs, 
converting between base64-encoded strings and binary data should be performed using Buffer.from(str, 'base64') andbuf.toString('base64').

在搜索了一些之后，我发现这个问题说它没有被弃用

https://github.com/microsoft/TypeScript/issues/45566

所以解决web JS弃用警告的方法是使用window.btoa 警告就会消失。

2022-02-08 10:53:38

JavaScript没有btoa中间步骤(没有库)

在问题标题中你写的是字符串转换，但在问题中你谈论的是二进制数据(图片)，所以这里有一个函数，从PNG图片二进制数据开始进行适当的转换(详细信息和反转转换在这里)。

2020-07-27 11:43:48

如何在JavaScript中将字符串编码为Base64 ?

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