在使用sqlalchemy在类中编写序列化装饰器时，我得到了相同的错误消息。所以不要:

Class Puppy(Base):
    ...
    @property
    def serialize(self):
        return { 'id':self.id,
                 'date_birth':self.date_birth,
                  ...
                }

我只是借用了jgbarah使用isoformat()的想法，并将原始值附加到isoformat()，这样它现在看起来就像:

                  ...
                 'date_birth':self.date_birth.isoformat(),
                  ...

我在外部化django模型对象转储为JSON时也遇到了同样的问题。 以下是解决方法。

def externalize(model_obj):
  keys = model_obj._meta.get_all_field_names() 
  data = {}
  for key in keys:
    if key == 'date_time':
      date_time_obj = getattr(model_obj, key)
      data[key] = date_time_obj.strftime("%A %d. %B %Y")
    else:
      data[key] = getattr(model_obj, key)
  return data

在其他答案的基础上，一个简单的解决方案基于只转换datetime的特定序列化器。Datetime和Datetime。将对象日期指定为字符串。

from datetime import date, datetime

def json_serial(obj):
    """JSON serializer for objects not serializable by default json code"""

    if isinstance(obj, (datetime, date)):
        return obj.isoformat()
    raise TypeError ("Type %s not serializable" % type(obj))

As seen, the code just checks to find out if object is of class datetime.datetime or datetime.date, and then uses .isoformat() to produce a serialized version of it, according to ISO 8601 format, YYYY-MM-DDTHH:MM:SS (which is easily decoded by JavaScript). If more complex serialized representations are sought, other code could be used instead of str() (see other answers to this question for examples). The code ends by raising an exception, to deal with the case it is called with a non-serializable type.

这个json_serial函数可以这样使用:

from datetime import datetime
from json import dumps

print dumps(datetime.now(), default=json_serial)

详细说明如何将默认参数设置为json。可以在json模块文档的基本用法章节中找到dump作品。

Another approach is to adopt a concept from FEEL (the Friendly Enough Expression Language) defined in DMN (Decision Model Notation) - namely @strings. Any string starting with @" and ending with " is decoded separately with FEEL decoding. Of course the sender and the receiver have to agree to this convention, but ... the code below lets you encode lots of other things as well as dates, times, date/times, timedeltas. You can encode year/month durations and ranges (so long as you except a 4 element tuple of chr, expr, expr, chr as being a good representation of a range - where the two chrs are open/close brackets). So, @"P4Y2M" is a duration of 4 years and 2 months. @"P2DT5H" is a timedelta of 2 days and 4 hours, @"(2021-01-02 .. 2021-12-31)" is a year range.

下面的代码可用于序列化和反序列化@strings。

import datetime
import pySFeel

parser = pySFeel.SFeelParser()


def convertAtString(thisString):
    # Convert an @string
    (status, newValue) = parser.sFeelParse(thisString[2:-1])
    if 'errors' in status:
        return thisString
    else:
        return newValue


def convertIn(newValue):
    if isinstance(newValue, dict):
        for key in newValue:
            if isinstance(newValue[key], int):
                newValue[key] = float(newValue[key])
            elif isinstance(newValue[key], str) and (newValue[key][0:2] == '@"') and (newValue[key][-1] == '"'):
                newValue[key] = convertAtString(newValue[key])
            elif isinstance(newValue[key], dict) or isinstance(newValue[key], list):
                newValue[key] = convertIn(newValue[key])
    elif isinstance(newValue, list):
        for i in range(len(newValue)):
            if isinstance(newValue[i], int):
                newValue[i] = float(newValue[i])
            elif isinstance(newValue[i], str) and (newValue[i][0:2] == '@"') and (newValue[i][-1] == '"'):
                newValue[i] = convertAtString(newValue[i])
            elif isinstance(newValue[i], dict) or isinstance(newValue[i], list):
                newValue[i] = convertIn(newValue[i])
    elif isinstance(newValue, str) and (newValue[0:2] == '@"') and (newValue[-1] == '"'):
        newValue = convertAtString(newValue)
    return newValue


  def convertOut(thisValue):
      if isinstance(thisValue, datetime.date):
          return '@"' + thisValue.isoformat() + '"'
      elif isinstance(thisValue, datetime.datetime):
          return '@"' + thisValue.isoformat(sep='T') + '"'
      elif isinstance(thisValue, datetime.time):
          return '@"' + thisValue.isoformat() + '"'
      elif isinstance(thisValue, datetime.timedelta):
          sign = ''
          duration = thisValue.total_seconds()
          if duration < 0:
              duration = -duration
              sign = '-'
          secs = duration % 60
          duration = int(duration / 60)
          mins = duration % 60
          duration = int(duration / 60)
          hours = duration % 24
          days = int(duration / 24)
          return '@"%sP%dDT%dH%dM%fS"' % (sign, days, hours, mins, secs)
      elif isinstance(thisValue, bool):
          return thisValue:
      elif thisValue is None:
          return thisValue:
      elif isinstance(thisValue, int):
          sign = ''
          if thisValue < 0:
              thisValue = -thisValue
              sign = '-'
          years = int(thisValue / 12)
          months = (thisValue % 12)
          return '@"%sP%dY%dM"' % (sign, years, months)
      elif isinstance(thisValue, tuple) and (len(thisValue) == 4):
          (lowEnd, lowVal, highVal, highEnd) = thisValue
          return '@"' + lowEnd + str(lowVal) + ' .. ' + str(highVal) + highEnd
      elif thisValue is None:
          return 'null'
      elif isinstance(thisValue, dict):
          for item in thisValue:
              thisValue[item] = convertOut(thisValue[item])
          return thisValue
      elif isinstance(thisValue, list):
          for i in range(len(thisValue)):
              thisValue[i] = convertOut(thisValue[i])
          return thisValue
      else:
          return thisValue

根据@jjmontes的回答，我使用了以下方法。 适用于flask和flask-rest用户

# get json string
jsonStr = json.dumps(my_dictionary, indent=1, sort_keys=True, default=str)
# then covert json string to json object
return json.loads(jsonStr)

2018年更新

最初的答案适应了MongoDB“date”字段的表示方式:

{" $日期":1506816000000}

如果你想要一个通用的Python解决方案来将datetime序列化为json，请查看@jjmontes的答案，这是一个不需要依赖的快速解决方案。

当你在使用mongoengine(每个注释)而pymongo是一个依赖时，pymongo有内置的实用工具来帮助json序列化: http://api.mongodb.org/python/1.10.1/api/bson/json_util.html

示例用法(序列化):

from bson import json_util
import json

json.dumps(anObject, default=json_util.default)

示例用法(反序列化):

json.loads(aJsonString, object_hook=json_util.object_hook)

Django

Django提供了一个原生的DjangoJSONEncoder序列化器来正确地处理这类问题。

看到https://docs.djangoproject.com/en/dev/topics/serialization/ djangojsonencoder

from django.core.serializers.json import DjangoJSONEncoder

return json.dumps(
  item,
  sort_keys=True,
  indent=1,
  cls=DjangoJSONEncoder
)

我注意到DjangoJSONEncoder和使用自定义默认之间的一个区别:

import datetime
import json

def default(o):
    if isinstance(o, (datetime.date, datetime.datetime)):
        return o.isoformat()

return json.dumps(
  item,
  sort_keys=True,
  indent=1,
  default=default
)

Django剥离了一些数据:

 "last_login": "2018-08-03T10:51:42.990", # DjangoJSONEncoder 
 "last_login": "2018-08-03T10:51:42.990239", # default

所以，在某些情况下，你可能需要小心。