将这个类添加到项目中

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;

public class QueryStringBuilder
{
    private readonly List<KeyValuePair<string, object>> _list;

    public QueryStringBuilder()
    {
        _list = new List<KeyValuePair<string, object>>();
    }

    public void Add(string name, object value)
    {
        _list.Add(new KeyValuePair<string, object>(name, value));
    }

    public override string ToString()
    {
        return String.Join("&", _list.Select(kvp => String.Concat(Uri.EscapeDataString(kvp.Key), "=", Uri.EscapeDataString(kvp.Value.ToString()))));
    }
}

像这样使用它:

var actual = new QueryStringBuilder {
    {"foo", 123},
    {"bar", "val31"},
    {"bar", "val32"}
};

actual.Add("a+b", "c+d");

actual.ToString(); // "foo=123&bar=val31&bar=val32&a%2bb=c%2bd"

我为我的剃刀项目写了一个助手，使用了其他答案的一些提示。

ParseQueryString业务是必要的，因为我们不允许篡改当前请求的QueryString对象。

@helper GetQueryStringWithValue(string key, string value) {
    var queryString = System.Web.HttpUtility.ParseQueryString(HttpContext.Current.Request.QueryString.ToString());
    queryString[key] = value;
    @Html.Raw(queryString.ToString())
}

我是这样使用的:

location.search = '?@Helpers.GetQueryStringWithValue("var-name", "var-value")';

如果希望它接受多个值，只需将参数更改为Dictionary，并将对添加到查询字符串中。

你可以通过调用system . web . httputiity . parsequerystring (string.Empty)来创建一个新的可写的HttpValueCollection实例，然后将它用作任何NameValueCollection。一旦你添加了你想要的值，你可以在集合上调用ToString来获得一个查询字符串，如下所示:

NameValueCollection queryString = System.Web.HttpUtility.ParseQueryString(string.Empty);

queryString.Add("key1", "value1");
queryString.Add("key2", "value2");

return queryString.ToString(); // Returns "key1=value1&key2=value2", all URL-encoded

HttpValueCollection是内部的，所以你不能直接构造一个实例。然而，一旦你获得了一个实例，你就可以像使用其他NameValueCollection一样使用它。因为你正在使用的实际对象是一个HttpValueCollection，调用ToString方法将调用HttpValueCollection上的重写方法，它将集合格式化为url编码的查询字符串。

在SO和网络上搜索类似问题的答案后，这是我能找到的最简单的解决方案。

net核心

如果你在。net Core中工作，你可以使用Microsoft.AspNetCore.WebUtilities.QueryHelpers类，它极大地简化了这一点。

https://learn.microsoft.com/en-us/dotnet/api/microsoft.aspnetcore.webutilities.queryhelpers

示例代码:

const string url = "https://customer-information.azure-api.net/customers/search/taxnbr";
var param = new Dictionary<string, string>() { { "CIKey", "123456789" } };

var newUrl = new Uri(QueryHelpers.AddQueryString(url, param));

如果你仔细观察，QueryString属性是一个NameValueCollection。当我做了类似的事情，我通常对序列化和反序列化感兴趣，所以我的建议是建立一个NameValueCollection，然后传递给:

using System.Linq;
using System.Web;
using System.Collections.Specialized;

private string ToQueryString(NameValueCollection nvc)
{
    var array = (
        from key in nvc.AllKeys
        from value in nvc.GetValues(key)
            select string.Format(
                "{0}={1}",
                HttpUtility.UrlEncode(key),
                HttpUtility.UrlEncode(value))
        ).ToArray();
    return "?" + string.Join("&", array);
}

我想在LINQ中也有一种非常优雅的方式来做到这一点……

这是我最近的记录。由于种种原因，我不喜欢其他的，所以我自己写了一个。

这个版本的特点:

Use of StringBuilder only. No ToArray() calls or other extension methods. It doesn't look as pretty as some of the other responses, but I consider this a core function so efficiency is more important than having "fluent", "one-liner" code which hide inefficiencies. Handles multiple values per key. (Didn't need it myself but just to silence Mauricio ;) public string ToQueryString(NameValueCollection nvc) { StringBuilder sb = new StringBuilder("?"); bool first = true; foreach (string key in nvc.AllKeys) { foreach (string value in nvc.GetValues(key)) { if (!first) { sb.Append("&"); } sb.AppendFormat("{0}={1}", Uri.EscapeDataString(key), Uri.EscapeDataString(value)); first = false; } } return sb.ToString(); }

示例使用

        var queryParams = new NameValueCollection()
        {
            { "x", "1" },
            { "y", "2" },
            { "foo", "bar" },
            { "foo", "baz" },
            { "special chars", "? = &" },
        };

        string url = "http://example.com/stuff" + ToQueryString(queryParams);

        Console.WriteLine(url);

输出

http://example.com/stuff?x=1&y=2&foo=bar&foo=baz&special%20chars=%3F%20%3D%20%26

我有一个扩展方法的Uri:

接受匿名对象:uri。WithQuery(new {name = "value"}) 接受字符串/字符串对的集合(例如Dictionary ' 2)。 接受字符串/对象对的集合(例如RouteValueDictionary)。 接受NameValueCollections。 按键对查询值进行排序，以便相同的值产生相同的uri。 每个键支持多个值，保持其原始顺序。

文档版本可以在这里找到。

扩展:

public static Uri WithQuery(this Uri uri, object values)
{
    if (uri == null)
        throw new ArgumentNullException(nameof(uri));

    if (values != null)
    {
        var query = string.Join(
            "&", from p in ParseQueryValues(values)
                 where !string.IsNullOrWhiteSpace(p.Key)
                 let k = HttpUtility.UrlEncode(p.Key.Trim())
                 let v = HttpUtility.UrlEncode(p.Value)
                 orderby k
                 select string.IsNullOrEmpty(v) ? k : $"{k}={v}");

        if (query.Length != 0 || uri.Query.Length != 0)
            uri = new UriBuilder(uri) { Query = query }.Uri;
    }

    return uri;
}

查询解析器:

private static IEnumerable<KeyValuePair<string, string>> ParseQueryValues(object values)
{
    // Check if a name/value collection.
    var nvc = values as NameValueCollection;
    if (nvc != null)
        return from key in nvc.AllKeys
               from val in nvc.GetValues(key)
               select new KeyValuePair<string, string>(key, val);

    // Check if a string/string dictionary.
    var ssd = values as IEnumerable<KeyValuePair<string, string>>;
    if (ssd != null)
        return ssd;

    // Check if a string/object dictionary.
    var sod = values as IEnumerable<KeyValuePair<string, object>>;
    if (sod == null)
    {
        // Check if a non-generic dictionary.
        var ngd = values as IDictionary;
        if (ngd != null)
            sod = ngd.Cast<dynamic>().ToDictionary<dynamic, string, object>(
                p => p.Key.ToString(), p => p.Value as object);

        // Convert object properties to dictionary.
        if (sod == null)
            sod = new RouteValueDictionary(values);
    }

    // Normalize and return the values.
    return from pair in sod
           from val in pair.Value as IEnumerable<string>
            ?? new[] { pair.Value?.ToString() }
           select new KeyValuePair<string, string>(pair.Key, val);
}

下面是测试:

var uri = new Uri("https://stackoverflow.com/yo?oldKey=oldValue");

// Test with a string/string dictionary.
var q = uri.WithQuery(new Dictionary<string, string>
{
    ["k1"] = string.Empty,
    ["k2"] = null,
    ["k3"] = "v3"
});

Debug.Assert(q == new Uri(
    "https://stackoverflow.com/yo?k1&k2&k3=v3"));

// Test with a string/object dictionary.
q = uri.WithQuery(new Dictionary<string, object>
{
    ["k1"] = "v1",
    ["k2"] = new[] { "v2a", "v2b" },
    ["k3"] = null
});

Debug.Assert(q == new Uri(
    "https://stackoverflow.com/yo?k1=v1&k2=v2a&k2=v2b&k3"));

// Test with a name/value collection.
var nvc = new NameValueCollection()
{
    ["k1"] = string.Empty,
    ["k2"] = "v2a"
};

nvc.Add("k2", "v2b");

q = uri.WithQuery(nvc);
Debug.Assert(q == new Uri(
    "https://stackoverflow.com/yo?k1&k2=v2a&k2=v2b"));

// Test with any dictionary.
q = uri.WithQuery(new Dictionary<int, HashSet<string>>
{
    [1] = new HashSet<string> { "v1" },
    [2] = new HashSet<string> { "v2a", "v2b" },
    [3] = null
});

Debug.Assert(q == new Uri(
    "https://stackoverflow.com/yo?1=v1&2=v2a&2=v2b&3"));

// Test with an anonymous object.
q = uri.WithQuery(new
{
    k1 = "v1",
    k2 = new[] { "v2a", "v2b" },
    k3 = new List<string> { "v3" },
    k4 = true,
    k5 = null as Queue<string>
});

Debug.Assert(q == new Uri(
    "https://stackoverflow.com/yo?k1=v1&k2=v2a&k2=v2b&k3=v3&k4=True&k5"));

// Keep existing query using a name/value collection.
nvc = HttpUtility.ParseQueryString(uri.Query);
nvc.Add("newKey", "newValue");

q = uri.WithQuery(nvc);
Debug.Assert(q == new Uri(
    "https://stackoverflow.com/yo?newKey=newValue&oldKey=oldValue"));

// Merge two query objects using the RouteValueDictionary.
var an1 = new { k1 = "v1" };
var an2 = new { k2 = "v2" };

q = uri.WithQuery(
    new RouteValueDictionary(an1).Concat(
        new RouteValueDictionary(an2)));

Debug.Assert(q == new Uri(
    "https://stackoverflow.com/yo?k1=v1&k2=v2"));