在Python中如何找到列表的中值?列表可以是任意大小的,并且数字不保证是任何特定的顺序。
如果列表包含偶数个元素,则函数应返回中间两个元素的平均值。
以下是一些例子(为了便于展示,进行了排序):
median([1]) == 1
median([1, 1]) == 1
median([1, 1, 2, 4]) == 1.5
median([0, 2, 5, 6, 8, 9, 9]) == 6
median([0, 0, 0, 0, 4, 4, 6, 8]) == 2
在Python中如何找到列表的中值?列表可以是任意大小的,并且数字不保证是任何特定的顺序。
如果列表包含偶数个元素,则函数应返回中间两个元素的平均值。
以下是一些例子(为了便于展示,进行了排序):
median([1]) == 1
median([1, 1]) == 1
median([1, 1, 2, 4]) == 1.5
median([0, 2, 5, 6, 8, 9, 9]) == 6
median([0, 0, 0, 0, 4, 4, 6, 8]) == 2
当前回答
def median(array):
"""Calculate median of the given list.
"""
# TODO: use statistics.median in Python 3
array = sorted(array)
half, odd = divmod(len(array), 2)
if odd:
return array[half]
return (array[half - 1] + array[half]) / 2.0
其他回答
以下是我在Codecademy的练习中得出的结论:
def median(data):
new_list = sorted(data)
if len(new_list)%2 > 0:
return new_list[len(new_list)/2]
elif len(new_list)%2 == 0:
return (new_list[(len(new_list)/2)] + new_list[(len(new_list)/2)-1]) /2.0
print median([1,2,3,4,5,9])
def median(array):
if len(array) < 1:
return(None)
if len(array) % 2 == 0:
median = (array[len(array)//2-1: len(array)//2+1])
return sum(median) / len(median)
else:
return(array[len(array)//2])
实现它:
def median(numbers):
"""
Calculate median of a list numbers.
:param numbers: the numbers to be calculated.
:return: median value of numbers.
>>> median([1, 3, 3, 6, 7, 8, 9])
6
>>> median([1, 2, 3, 4, 5, 6, 8, 9])
4.5
>>> import statistics
>>> import random
>>> numbers = random.sample(range(-50, 50), k=100)
>>> statistics.median(numbers) == median(numbers)
True
"""
numbers = sorted(numbers)
mid_index = len(numbers) // 2
return (
(numbers[mid_index] + numbers[mid_index - 1]) / 2 if mid_index % 2 == 0
else numbers[mid_index]
)
if __name__ == "__main__":
from doctest import testmod
testmod()
来源
函数值:
def median(d):
d=np.sort(d)
n2=int(len(d)/2)
r=n2%2
if (r==0):
med=d[n2]
else:
med=(d[n2] + d[n2+1]) / 2
return med
(适用于python-2.x):
def median(lst):
n = len(lst)
s = sorted(lst)
return (s[n//2-1]/2.0+s[n//2]/2.0, s[n//2])[n % 2] if n else None
>>> median([-5, -5, -3, -4, 0, -1])
-3.5
numpy.median ():
>>> from numpy import median
>>> median([1, -4, -1, -1, 1, -3])
-1.0
python 3。X,使用statistics.median:
>>> from statistics import median
>>> median([5, 2, 3, 8, 9, -2])
4.0