在MDN文章《面向对象Javascript介绍》中关于继承的部分,我注意到他们设置了prototype.constructor:
// correct the constructor pointer because it points to Person
Student.prototype.constructor = Student;
这有什么重要的目的吗?可以省略吗?
在MDN文章《面向对象Javascript介绍》中关于继承的部分,我注意到他们设置了prototype.constructor:
// correct the constructor pointer because it points to Person
Student.prototype.constructor = Student;
这有什么重要的目的吗?可以省略吗?
当前回答
现在不需要加糖的函数'类'或使用'New'。使用对象字面量。
Object原型已经是一个“类”。当你定义一个对象文字时,它已经是原型对象的一个实例。这些也可以作为另一个对象的原型,等等。
const Person = {
name: '[Person.name]',
greeting: function() {
console.log( `My name is ${ this.name || '[Name not assigned]' }` );
}
};
// Person.greeting = function() {...} // or define outside the obj if you must
// Object.create version
const john = Object.create( Person );
john.name = 'John';
console.log( john.name ); // John
john.greeting(); // My name is John
// Define new greeting method
john.greeting = function() {
console.log( `Hi, my name is ${ this.name }` )
};
john.greeting(); // Hi, my name is John
// Object.assign version
const jane = Object.assign( Person, { name: 'Jane' } );
console.log( jane.name ); // Jane
// Original greeting
jane.greeting(); // My name is Jane
// Original Person obj is unaffected
console.log( Person.name ); // [Person.name]
console.log( Person.greeting() ); // My name is [Person.name]
这里值得一读:
Class-based object-oriented languages, such as Java and C++, are founded on the concept of two distinct entities: classes and instances. ... A prototype-based language, such as JavaScript, does not make this distinction: it simply has objects. A prototype-based language has the notion of a prototypical object, an object used as a template from which to get the initial properties for a new object. Any object can specify its own properties, either when you create it or at run time. In addition, any object can be associated as the prototype for another object, allowing the second object to share the first object's properties
其他回答
编辑,其实我错了。注释掉一行并不会改变它的行为。(我测试过)
是的,这是必要的。当你这样做时
Student.prototype = new Person();
student。prototype。constructor变成Person。因此,调用Student()将返回Person创建的对象。如果你这样做了
Student.prototype.constructor = Student;
Student.prototype.constructor被重置回Student。现在,当您调用Student()时,它执行Student,它调用父构造函数parent(),它返回正确继承的对象。如果你在调用Student.prototype.constructor之前没有重置它,你将得到一个没有在Student()中设置的任何属性的对象。
我不同意。不需要设置原型。取完全相同的代码,但去掉原型。构造函数。有什么变化吗?不。现在,进行以下更改:
Person = function () {
this.favoriteColor = 'black';
}
Student = function () {
Person.call(this);
this.favoriteColor = 'blue';
}
在测试代码的末尾……
alert(student1.favoriteColor);
颜色是蓝色的。
对原型的更改。构造函数,根据我的经验,没有做太多,除非你做非常具体,非常复杂的事情,这可能不是一个好的实践:)
Edit: After poking around the web for a bit and doing some experimentation, it looks like people set the constructor so that it 'looks' like the thing that is being constructed with 'new'. I guess I would argue that the problem with this is that javascript is a prototype language - there is no such thing as inheritence. But most programmers come from a background of programming that pushes inheritence as 'the way'. So we come up with all sorts of things to try and make this prototypical language a 'classic' language.. such as extending 'classes'. Really, in the example they gave, a new student is a person - it isn't 'extending' from another student.. the student is all about the person, and whatever the person is the student is as well. Extend the student, and whatever you've extended is a student at heart, but is customized to fit your needs.
克罗克福德有点疯狂和过分热心,但认真阅读他写的一些东西。它会让你从不同的角度看待这个问题。
下面是MDN的一个例子,我发现它对理解它的用法很有帮助。
在JavaScript中,我们有返回AsyncFunction对象的async函数。AsyncFunction不是一个全局对象,但可以通过使用构造函数属性检索它并利用它。
function resolveAfter2Seconds(x) {
return new Promise(resolve => {
setTimeout(() => {
resolve(x);
}, 2000);
});
}
// AsyncFunction constructor
var AsyncFunction = Object.getPrototypeOf(async function(){}).constructor
var a = new AsyncFunction('a',
'b',
'return await resolveAfter2Seconds(a) + await resolveAfter2Seconds(b);');
a(10, 20).then(v => {
console.log(v); // prints 30 after 4 seconds
});
这是不必要的。这只是传统的OOP拥护者所做的许多事情之一,他们试图将JavaScript的原型继承转变为经典继承。唯一的事情是,下面
Student.prototype.constructor = Student;
你现在有了当前“构造函数”的引用。
在Wayne的答案中,它被标记为正确,你可以做与下面代码完全相同的事情
Person.prototype.copy = function() {
// return new Person(this.name); // just as bad
return new this.constructor(this.name);
};
使用下面的代码(只需替换此代码。构造师与Person)
Person.prototype.copy = function() {
// return new Person(this.name); // just as bad
return new Person(this.name);
};
感谢上帝,在ES6中,经典继承主义者可以使用语言的原生操作符,如class、extends和super,我们不必看到prototype。构造函数更正和父引用。
得到了一个很好的代码示例,为什么真的有必要设置原型构造函数..
function CarFactory(name){
this.name=name;
}
CarFactory.prototype.CreateNewCar = function(){
return new this.constructor("New Car "+ this.name);
}
CarFactory.prototype.toString=function(){
return 'Car Factory ' + this.name;
}
AudiFactory.prototype = new CarFactory(); // Here's where the inheritance occurs
AudiFactory.prototype.constructor=AudiFactory; // Otherwise instances of Audi would have a constructor of Car
function AudiFactory(name){
this.name=name;
}
AudiFactory.prototype.toString=function(){
return 'Audi Factory ' + this.name;
}
var myAudiFactory = new AudiFactory('');
alert('Hay your new ' + myAudiFactory + ' is ready.. Start Producing new audi cars !!! ');
var newCar = myAudiFactory.CreateNewCar(); // calls a method inherited from CarFactory
alert(newCar);
/*
Without resetting prototype constructor back to instance, new cars will not come from New Audi factory, Instead it will come from car factory ( base class ).. Dont we want our new car from Audi factory ????
*/