我正在使用. net JSON解析器,并想序列化我的配置文件,使其可读。所以不要:

{"blah":"v", "blah2":"v2"}

我想要更好的东西,比如:

{
    "blah":"v", 
    "blah2":"v2"
}

我的代码是这样的:

using System.Web.Script.Serialization; 

var ser = new JavaScriptSerializer();
configSz = ser.Serialize(config);
using (var f = (TextWriter)File.CreateText(configFn))
{
    f.WriteLine(configSz);
    f.Close();
}

当前回答

你可以使用以下标准方法来获取格式化的Json

JsonReaderWriterFactory。CreateJsonWriter(流流,编码编码,bool ownsStream, bool缩进,字符串indentChars)

只设置"缩进==true"

试试这样的方法

    public readonly DataContractJsonSerializerSettings Settings = 
            new DataContractJsonSerializerSettings
            { UseSimpleDictionaryFormat = true };

    public void Keep<TValue>(TValue item, string path)
    {
        try
        {
            using (var stream = File.Open(path, FileMode.Create))
            {
                //var currentCulture = Thread.CurrentThread.CurrentCulture;
                //Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;

                try
                {
                    using (var writer = JsonReaderWriterFactory.CreateJsonWriter(
                        stream, Encoding.UTF8, true, true, "  "))
                    {
                        var serializer = new DataContractJsonSerializer(type, Settings);
                        serializer.WriteObject(writer, item);
                        writer.Flush();
                    }
                }
                catch (Exception exception)
                {
                    Debug.WriteLine(exception.ToString());
                }
                finally
                {
                    //Thread.CurrentThread.CurrentCulture = currentCulture;
                }
            }
        }
        catch (Exception exception)
        {
            Debug.WriteLine(exception.ToString());
        }
    }

注意线条

    var currentCulture = Thread.CurrentThread.CurrentCulture;
    Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
    ....
    Thread.CurrentThread.CurrentCulture = currentCulture;

对于某些类型的xml序列化器,您应该使用InvariantCulture来避免在具有不同区域设置的计算机上反序列化期间出现异常。例如,double或DateTime的无效格式有时会导致错误。

在反序列化

    public TValue Revive<TValue>(string path, params object[] constructorArgs)
    {
        try
        {
            using (var stream = File.OpenRead(path))
            {
                //var currentCulture = Thread.CurrentThread.CurrentCulture;
                //Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;

                try
                {
                    var serializer = new DataContractJsonSerializer(type, Settings);
                    var item = (TValue) serializer.ReadObject(stream);
                    if (Equals(item, null)) throw new Exception();
                    return item;
                }
                catch (Exception exception)
                {
                    Debug.WriteLine(exception.ToString());
                    return (TValue) Activator.CreateInstance(type, constructorArgs);
                }
                finally
                {
                    //Thread.CurrentThread.CurrentCulture = currentCulture;
                }
            }
        }
        catch
        {
            return (TValue) Activator.CreateInstance(typeof (TValue), constructorArgs);
        }
    }

谢谢!

其他回答

所有这些都可以在一行中完成:

string jsonString = JsonConvert.SerializeObject(yourObject, Formatting.Indented);
using System.Text.Json;
...
var parsedJson = JsonSerializer.Deserialize<ExpandoObject>(json);
var options = new JsonSerializerOptions() { WriteIndented = true };
return JsonSerializer.Serialize(parsedJson, options);

我有一些非常简单的方法。你可以输入任何需要转换成json格式的对象:

private static string GetJson<T> (T json)
{
    return JsonConvert.SerializeObject(json, Formatting.Indented);
}

下面的代码为我工作:

JsonConvert.SerializeObject(JToken.Parse(yourobj.ToString()))

修饰现有JSON的最短版本:(编辑:使用JSON.net)

JToken.Parse("mystring").ToString()

输入:

{"menu": { "id": "file", "value": "File", "popup": { "menuitem": [ {"value": "New", "onclick": "CreateNewDoc()"}, {"value": "Open", "onclick": "OpenDoc()"}, {"value": "Close", "onclick": "CloseDoc()"} ] } }}

输出:

{
  "menu": {
    "id": "file",
    "value": "File",
    "popup": {
      "menuitem": [
        {
          "value": "New",
          "onclick": "CreateNewDoc()"
        },
        {
          "value": "Open",
          "onclick": "OpenDoc()"
        },
        {
          "value": "Close",
          "onclick": "CloseDoc()"
        }
      ]
    }
  }
}

漂亮地打印一个对象:

JToken.FromObject(myObject).ToString()