我正在使用. net JSON解析器,并想序列化我的配置文件,使其可读。所以不要:

{"blah":"v", "blah2":"v2"}

我想要更好的东西,比如:

{
    "blah":"v", 
    "blah2":"v2"
}

我的代码是这样的:

using System.Web.Script.Serialization; 

var ser = new JavaScriptSerializer();
configSz = ser.Serialize(config);
using (var f = (TextWriter)File.CreateText(configFn))
{
    f.WriteLine(configSz);
    f.Close();
}

当前回答

2023年更新

对于那些问我如何使用c#在。net中获得格式化JSON并想要看到如何立即使用它的人和一行爱好者。以下是缩进的JSON字符串一行代码:

有两种知名的JSON格式化器或解析器可以序列化:

Newtonsoft Json。网版:

using Newtonsoft.Json;

var jsonString = JsonConvert.SerializeObject(yourObj, Formatting.Indented);

.Net 7版本:

using System.Text.Json;

var jsonString = JsonSerializer.Serialize(yourObj, new JsonSerializerOptions { WriteIndented = true });

其他回答

所有这些都可以在一行中完成:

string jsonString = JsonConvert.SerializeObject(yourObject, Formatting.Indented);

2023年更新

对于那些问我如何使用c#在。net中获得格式化JSON并想要看到如何立即使用它的人和一行爱好者。以下是缩进的JSON字符串一行代码:

有两种知名的JSON格式化器或解析器可以序列化:

Newtonsoft Json。网版:

using Newtonsoft.Json;

var jsonString = JsonConvert.SerializeObject(yourObj, Formatting.Indented);

.Net 7版本:

using System.Text.Json;

var jsonString = JsonSerializer.Serialize(yourObj, new JsonSerializerOptions { WriteIndented = true });

这对我很管用。以防有人在找VB。净版。

@imports System
@imports System.IO
@imports Newtonsoft.Json
    
Public Shared Function JsonPrettify(ByVal json As String) As String
  Using stringReader = New StringReader(json)

    Using stringWriter = New StringWriter()
      Dim jsonReader = New JsonTextReader(stringReader)
      Dim jsonWriter = New JsonTextWriter(stringWriter) With {
          .Formatting = Formatting.Indented
      }
      jsonWriter.WriteToken(jsonReader)
      Return stringWriter.ToString()
    End Using
  End Using
End Function

你可以使用以下标准方法来获取格式化的Json

JsonReaderWriterFactory。CreateJsonWriter(流流,编码编码,bool ownsStream, bool缩进,字符串indentChars)

只设置"缩进==true"

试试这样的方法

    public readonly DataContractJsonSerializerSettings Settings = 
            new DataContractJsonSerializerSettings
            { UseSimpleDictionaryFormat = true };

    public void Keep<TValue>(TValue item, string path)
    {
        try
        {
            using (var stream = File.Open(path, FileMode.Create))
            {
                //var currentCulture = Thread.CurrentThread.CurrentCulture;
                //Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;

                try
                {
                    using (var writer = JsonReaderWriterFactory.CreateJsonWriter(
                        stream, Encoding.UTF8, true, true, "  "))
                    {
                        var serializer = new DataContractJsonSerializer(type, Settings);
                        serializer.WriteObject(writer, item);
                        writer.Flush();
                    }
                }
                catch (Exception exception)
                {
                    Debug.WriteLine(exception.ToString());
                }
                finally
                {
                    //Thread.CurrentThread.CurrentCulture = currentCulture;
                }
            }
        }
        catch (Exception exception)
        {
            Debug.WriteLine(exception.ToString());
        }
    }

注意线条

    var currentCulture = Thread.CurrentThread.CurrentCulture;
    Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
    ....
    Thread.CurrentThread.CurrentCulture = currentCulture;

对于某些类型的xml序列化器,您应该使用InvariantCulture来避免在具有不同区域设置的计算机上反序列化期间出现异常。例如,double或DateTime的无效格式有时会导致错误。

在反序列化

    public TValue Revive<TValue>(string path, params object[] constructorArgs)
    {
        try
        {
            using (var stream = File.OpenRead(path))
            {
                //var currentCulture = Thread.CurrentThread.CurrentCulture;
                //Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;

                try
                {
                    var serializer = new DataContractJsonSerializer(type, Settings);
                    var item = (TValue) serializer.ReadObject(stream);
                    if (Equals(item, null)) throw new Exception();
                    return item;
                }
                catch (Exception exception)
                {
                    Debug.WriteLine(exception.ToString());
                    return (TValue) Activator.CreateInstance(type, constructorArgs);
                }
                finally
                {
                    //Thread.CurrentThread.CurrentCulture = currentCulture;
                }
            }
        }
        catch
        {
            return (TValue) Activator.CreateInstance(typeof (TValue), constructorArgs);
        }
    }

谢谢!

用JavaScriptSerializer来完成这个任务会很困难。

试试JSON.Net。

对JSON进行了少量修改。净的例子

using System;
using Newtonsoft.Json;

namespace JsonPrettyPrint
{
    internal class Program
    {
        private static void Main(string[] args)
        {
            Product product = new Product
                {
                    Name = "Apple",
                    Expiry = new DateTime(2008, 12, 28),
                    Price = 3.99M,
                    Sizes = new[] { "Small", "Medium", "Large" }
                };

            string json = JsonConvert.SerializeObject(product, Formatting.Indented);
            Console.WriteLine(json);

            Product deserializedProduct = JsonConvert.DeserializeObject<Product>(json);
        }
    }

    internal class Product
    {
        public String[] Sizes { get; set; }
        public decimal Price { get; set; }
        public DateTime Expiry { get; set; }
        public string Name { get; set; }
    }
}

结果

{
  "Sizes": [
    "Small",
    "Medium",
    "Large"
  ],
  "Price": 3.99,
  "Expiry": "\/Date(1230447600000-0700)\/",
  "Name": "Apple"
}

文档:序列化对象