这对我很管用。以防有人在找VB。净版。

@imports System
@imports System.IO
@imports Newtonsoft.Json
    
Public Shared Function JsonPrettify(ByVal json As String) As String
  Using stringReader = New StringReader(json)

    Using stringWriter = New StringWriter()
      Dim jsonReader = New JsonTextReader(stringReader)
      Dim jsonWriter = New JsonTextWriter(stringWriter) With {
          .Formatting = Formatting.Indented
      }
      jsonWriter.WriteToken(jsonReader)
      Return stringWriter.ToString()
    End Using
  End Using
End Function

首先我想在Duncan Smart的帖子下添加评论，但不幸的是，我还没有足够的声誉来留下评论。我在这里试试。

我只是想警告一下副作用。

JsonTextReader在内部将json解析为类型化的jtoken，然后将它们序列化回来。

例如，如果您的原始JSON是

{ "double":0.00002, "date":"\/Date(1198908717056)\/"}

美化之后你得到

{ 
    "double":2E-05,
    "date": "2007-12-29T06:11:57.056Z"
}

当然，这两个json字符串是等价的，并且将反序列化为结构上相等的对象，但如果您需要保留原始字符串值，则需要考虑这一点

修饰现有JSON的最短版本:(编辑:使用JSON.net)

JToken.Parse("mystring").ToString()

输入:

{"menu": { "id": "file", "value": "File", "popup": { "menuitem": [ {"value": "New", "onclick": "CreateNewDoc()"}, {"value": "Open", "onclick": "OpenDoc()"}, {"value": "Close", "onclick": "CloseDoc()"} ] } }}

输出:

{
  "menu": {
    "id": "file",
    "value": "File",
    "popup": {
      "menuitem": [
        {
          "value": "New",
          "onclick": "CreateNewDoc()"
        },
        {
          "value": "Open",
          "onclick": "OpenDoc()"
        },
        {
          "value": "Close",
          "onclick": "CloseDoc()"
        }
      ]
    }
  }
}

漂亮地打印一个对象:

JToken.FromObject(myObject).ToString()

你可以使用以下标准方法来获取格式化的Json

JsonReaderWriterFactory。CreateJsonWriter(流流，编码编码，bool ownsStream, bool缩进，字符串indentChars)

只设置"缩进==true"

试试这样的方法

    public readonly DataContractJsonSerializerSettings Settings = 
            new DataContractJsonSerializerSettings
            { UseSimpleDictionaryFormat = true };

    public void Keep<TValue>(TValue item, string path)
    {
        try
        {
            using (var stream = File.Open(path, FileMode.Create))
            {
                //var currentCulture = Thread.CurrentThread.CurrentCulture;
                //Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;

                try
                {
                    using (var writer = JsonReaderWriterFactory.CreateJsonWriter(
                        stream, Encoding.UTF8, true, true, "  "))
                    {
                        var serializer = new DataContractJsonSerializer(type, Settings);
                        serializer.WriteObject(writer, item);
                        writer.Flush();
                    }
                }
                catch (Exception exception)
                {
                    Debug.WriteLine(exception.ToString());
                }
                finally
                {
                    //Thread.CurrentThread.CurrentCulture = currentCulture;
                }
            }
        }
        catch (Exception exception)
        {
            Debug.WriteLine(exception.ToString());
        }
    }

注意线条

    var currentCulture = Thread.CurrentThread.CurrentCulture;
    Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
    ....
    Thread.CurrentThread.CurrentCulture = currentCulture;

对于某些类型的xml序列化器，您应该使用InvariantCulture来避免在具有不同区域设置的计算机上反序列化期间出现异常。例如，double或DateTime的无效格式有时会导致错误。

在反序列化

    public TValue Revive<TValue>(string path, params object[] constructorArgs)
    {
        try
        {
            using (var stream = File.OpenRead(path))
            {
                //var currentCulture = Thread.CurrentThread.CurrentCulture;
                //Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;

                try
                {
                    var serializer = new DataContractJsonSerializer(type, Settings);
                    var item = (TValue) serializer.ReadObject(stream);
                    if (Equals(item, null)) throw new Exception();
                    return item;
                }
                catch (Exception exception)
                {
                    Debug.WriteLine(exception.ToString());
                    return (TValue) Activator.CreateInstance(type, constructorArgs);
                }
                finally
                {
                    //Thread.CurrentThread.CurrentCulture = currentCulture;
                }
            }
        }
        catch
        {
            return (TValue) Activator.CreateInstance(typeof (TValue), constructorArgs);
        }
    }

谢谢!

如果你有一个JSON字符串，想要“美化”它，但不想将它序列化到一个已知的c#类型，那么下面的方法就可以了(使用JSON.NET):

using System;
using System.IO;
using Newtonsoft.Json;

class JsonUtil
{
    public static string JsonPrettify(string json)
    {
        using (var stringReader = new StringReader(json))
        using (var stringWriter = new StringWriter())
        {
            var jsonReader = new JsonTextReader(stringReader);
            var jsonWriter = new JsonTextWriter(stringWriter) { Formatting = Formatting.Indented };
            jsonWriter.WriteToken(jsonReader);
            return stringWriter.ToString();
        }
    }
}

所有这些都可以在一行中完成:

string jsonString = JsonConvert.SerializeObject(yourObject, Formatting.Indented);