我正在使用. net JSON解析器,并想序列化我的配置文件,使其可读。所以不要:
{"blah":"v", "blah2":"v2"}
我想要更好的东西,比如:
{
"blah":"v",
"blah2":"v2"
}
我的代码是这样的:
using System.Web.Script.Serialization;
var ser = new JavaScriptSerializer();
configSz = ser.Serialize(config);
using (var f = (TextWriter)File.CreateText(configFn))
{
f.WriteLine(configSz);
f.Close();
}
. net 5内置了在System.Text.Json命名空间下处理JSON解析、序列化、反序列化的类。下面是一个序列化器的例子,它将。net对象转换为JSON字符串,
using System.Text.Json;
using System.Text.Json.Serialization;
private string ConvertJsonString(object obj)
{
JsonSerializerOptions options = new JsonSerializerOptions();
options.WriteIndented = true; //Pretty print using indent, white space, new line, etc.
options.NumberHandling = JsonNumberHandling.AllowNamedFloatingPointLiterals; //Allow NANs
string jsonString = JsonSerializer.Serialize(obj, options);
return jsonString;
}
用JavaScriptSerializer来完成这个任务会很困难。
试试JSON.Net。
对JSON进行了少量修改。净的例子
using System;
using Newtonsoft.Json;
namespace JsonPrettyPrint
{
internal class Program
{
private static void Main(string[] args)
{
Product product = new Product
{
Name = "Apple",
Expiry = new DateTime(2008, 12, 28),
Price = 3.99M,
Sizes = new[] { "Small", "Medium", "Large" }
};
string json = JsonConvert.SerializeObject(product, Formatting.Indented);
Console.WriteLine(json);
Product deserializedProduct = JsonConvert.DeserializeObject<Product>(json);
}
}
internal class Product
{
public String[] Sizes { get; set; }
public decimal Price { get; set; }
public DateTime Expiry { get; set; }
public string Name { get; set; }
}
}
结果
{
"Sizes": [
"Small",
"Medium",
"Large"
],
"Price": 3.99,
"Expiry": "\/Date(1230447600000-0700)\/",
"Name": "Apple"
}
文档:序列化对象
你可以使用以下标准方法来获取格式化的Json
JsonReaderWriterFactory。CreateJsonWriter(流流,编码编码,bool ownsStream, bool缩进,字符串indentChars)
只设置"缩进==true"
试试这样的方法
public readonly DataContractJsonSerializerSettings Settings =
new DataContractJsonSerializerSettings
{ UseSimpleDictionaryFormat = true };
public void Keep<TValue>(TValue item, string path)
{
try
{
using (var stream = File.Open(path, FileMode.Create))
{
//var currentCulture = Thread.CurrentThread.CurrentCulture;
//Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
try
{
using (var writer = JsonReaderWriterFactory.CreateJsonWriter(
stream, Encoding.UTF8, true, true, " "))
{
var serializer = new DataContractJsonSerializer(type, Settings);
serializer.WriteObject(writer, item);
writer.Flush();
}
}
catch (Exception exception)
{
Debug.WriteLine(exception.ToString());
}
finally
{
//Thread.CurrentThread.CurrentCulture = currentCulture;
}
}
}
catch (Exception exception)
{
Debug.WriteLine(exception.ToString());
}
}
注意线条
var currentCulture = Thread.CurrentThread.CurrentCulture;
Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
....
Thread.CurrentThread.CurrentCulture = currentCulture;
对于某些类型的xml序列化器,您应该使用InvariantCulture来避免在具有不同区域设置的计算机上反序列化期间出现异常。例如,double或DateTime的无效格式有时会导致错误。
在反序列化
public TValue Revive<TValue>(string path, params object[] constructorArgs)
{
try
{
using (var stream = File.OpenRead(path))
{
//var currentCulture = Thread.CurrentThread.CurrentCulture;
//Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
try
{
var serializer = new DataContractJsonSerializer(type, Settings);
var item = (TValue) serializer.ReadObject(stream);
if (Equals(item, null)) throw new Exception();
return item;
}
catch (Exception exception)
{
Debug.WriteLine(exception.ToString());
return (TValue) Activator.CreateInstance(type, constructorArgs);
}
finally
{
//Thread.CurrentThread.CurrentCulture = currentCulture;
}
}
}
catch
{
return (TValue) Activator.CreateInstance(typeof (TValue), constructorArgs);
}
}
谢谢!