如何在Java中杀死一个线程?

如何在Java中杀死Java .lang. thread ?

当前回答

线程。停止是不赞成的，所以我们如何停止一个线程在Java ?

总是使用中断方法和未来请求取消

当任务响应中断信号时，例如阻塞队列采取方法。

Callable < String > callable = new Callable < String > () {
    @Override
    public String call() throws Exception {
        String result = "";
        try {
            //assume below take method is blocked as no work is produced.
            result = queue.take();
        } catch (InterruptedException e) {
            Thread.currentThread().interrupt();
        }
        return result;
    }
};
Future future = executor.submit(callable);
try {
    String result = future.get(5, TimeUnit.SECONDS);
} catch (TimeoutException e) {
    logger.error("Thread timedout!");
    return "";
} finally {
    //this will call interrupt on queue which will abort the operation.
    //if it completes before time out, it has no side effects
    future.cancel(true);
}

当任务不响应中断信号时。假设任务执行套接字I/O，不响应中断信号，因此使用上述方法将不会中止任务，future将超时，但取消finally块将没有影响，线程将继续侦听套接字。如果由pool实现，我们可以关闭套接字或在连接时调用close方法。

public interface CustomCallable < T > extends Callable < T > {
    void cancel();
    RunnableFuture < T > newTask();
}

public class CustomExecutorPool extends ThreadPoolExecutor {
    protected < T > RunnableFuture < T > newTaskFor(Callable < T > callable) {
        if (callable instanceof CancellableTask)
            return ((CancellableTask < T > ) callable).newTask();
        else
            return super.newTaskFor(callable);
    }
}

public abstract class UnblockingIOTask < T > implements CustomCallable < T > {
    public synchronized void cancel() {
        try {
            obj.close();
        } catch (IOException e) {
            logger.error("io exception", e);
        }
    }

    public RunnableFuture < T > newTask() {
        return new FutureTask < T > (this) {
            public boolean cancel(boolean mayInterruptIfRunning) {
                try {
                    this.cancel();
                } finally {
                    return super.cancel(mayInterruptIfRunning);
                }
            }

        };
    }
}

2020-05-21 20:47:27

其他回答

我没有得到中断工作在Android，所以我用这个方法，工作完美:

boolean shouldCheckUpdates = true;

private void startupCheckForUpdatesEveryFewSeconds() {
    Thread t = new Thread(new CheckUpdates());
    t.start();
}

private class CheckUpdates implements Runnable{
    public void run() {
        while (shouldCheckUpdates){
            //Thread sleep 3 seconds
            System.out.println("Do your thing here");
        }
    }
}

 public void stop(){
        shouldCheckUpdates = false;
 }

2017-07-07 10:48:17

There is of course the case where you are running some kind of not-completely-trusted code. (I personally have this by allowing uploaded scripts to execute in my Java environment. Yes, there are security alarm bell ringing everywhere, but it's part of the application.) In this unfortunate instance you first of all are merely being hopeful by asking script writers to respect some kind of boolean run/don't-run signal. Your only decent fail safe is to call the stop method on the thread if, say, it runs longer than some timeout.

但是，这只是“体面的”，而不是绝对的，因为代码可以捕获ThreadDeath错误(或您显式抛出的任何异常)，而不是像一个绅士线程应该做的那样重新抛出它。所以，AFAIA的底线是没有绝对的故障保险。

2011-02-20 19:25:03

一般来说你不会…

你可以使用Thread.interrupt() (javadoc link)命令它中断正在做的事情。

在javadoc中有一个很好的解释(java technote链接)

2009-03-22 14:07:06

通常不杀死、停止或中断线程(或检查它是否被中断())，而是让它自然终止。

这很简单。你可以在run()方法中使用任何循环和(volatile)布尔变量来控制线程的活动。您还可以从活动线程返回到主线程以停止它。

这样你就优雅地杀死了一个线程:)。

2018-06-23 22:59:03

试图突然终止线程是众所周知的糟糕编程实践，也是糟糕应用程序设计的证据。多线程应用程序中的所有线程显式或隐式地共享相同的进程状态，并被迫相互协作以保持一致，否则您的应用程序将容易出现很难诊断的错误。因此，开发人员有责任通过仔细和清晰的应用程序设计来保证这种一致性。

对于受控线程终止，有两种主要的正确解决方案: