我找不到一个明确的答案。据我所知,在Python类中不能有多个__init__函数。那么如何解决这个问题呢?
假设我有一个名为Cheese的类,它具有number_of_holes属性。我怎么能有两种方法来创建奶酪对象…
其中一个需要像这样的洞的数量:帕玛森=奶酪(num_holes = 15)。
还有一个不带参数,只是随机number_of_holes属性:gouda = Cheese()。
我只能想到一种方法来做到这一点,但这似乎很笨拙:
class Cheese():
def __init__(self, num_holes = 0):
if (num_holes == 0):
# Randomize number_of_holes
else:
number_of_holes = num_holes
你说呢?还有别的办法吗?
人们肯定更喜欢已经发布的解决方案,但由于还没有人提到这个解决方案,我认为为了完整性,值得一提。
@classmethod方法可以修改为提供一个不调用默认构造函数(__init__)的替代构造函数。相反,使用__new__创建实例。
如果不能根据构造函数参数的类型选择初始化类型,并且构造函数不共享代码,则可以使用此方法。
例子:
class MyClass(set):
def __init__(self, filename):
self._value = load_from_file(filename)
@classmethod
def from_somewhere(cls, somename):
obj = cls.__new__(cls) # Does not call __init__
super(MyClass, obj).__init__() # Don't forget to call any polymorphic base class initializers
obj._value = load_from_somewhere(somename)
return obj
这就是我如何解决一个我必须创建的YearQuarter类。我创建了一个__init__,它对各种各样的输入非常宽容。
你可以这样使用它:
>>> from datetime import date
>>> temp1 = YearQuarter(year=2017, month=12)
>>> print temp1
2017-Q4
>>> temp2 = YearQuarter(temp1)
>>> print temp2
2017-Q4
>>> temp3 = YearQuarter((2017, 6))
>>> print temp3
2017-Q2
>>> temp4 = YearQuarter(date(2017, 1, 18))
>>> print temp4
2017-Q1
>>> temp5 = YearQuarter(year=2017, quarter = 3)
>>> print temp5
2017-Q3
这就是__init__和类的其余部分的样子:
import datetime
class YearQuarter:
def __init__(self, *args, **kwargs):
if len(args) == 1:
[x] = args
if isinstance(x, datetime.date):
self._year = int(x.year)
self._quarter = (int(x.month) + 2) / 3
elif isinstance(x, tuple):
year, month = x
self._year = int(year)
month = int(month)
if 1 <= month <= 12:
self._quarter = (month + 2) / 3
else:
raise ValueError
elif isinstance(x, YearQuarter):
self._year = x._year
self._quarter = x._quarter
elif len(args) == 2:
year, month = args
self._year = int(year)
month = int(month)
if 1 <= month <= 12:
self._quarter = (month + 2) / 3
else:
raise ValueError
elif kwargs:
self._year = int(kwargs["year"])
if "quarter" in kwargs:
quarter = int(kwargs["quarter"])
if 1 <= quarter <= 4:
self._quarter = quarter
else:
raise ValueError
elif "month" in kwargs:
month = int(kwargs["month"])
if 1 <= month <= 12:
self._quarter = (month + 2) / 3
else:
raise ValueError
def __str__(self):
return '{0}-Q{1}'.format(self._year, self._quarter)
class Cheese:
def __init__(self, *args, **kwargs):
"""A user-friendly initialiser for the general-purpose constructor.
"""
...
def _init_parmesan(self, *args, **kwargs):
"""A special initialiser for Parmesan cheese.
"""
...
def _init_gauda(self, *args, **kwargs):
"""A special initialiser for Gauda cheese.
"""
...
@classmethod
def make_parmesan(cls, *args, **kwargs):
new = cls.__new__(cls)
new._init_parmesan(*args, **kwargs)
return new
@classmethod
def make_gauda(cls, *args, **kwargs):
new = cls.__new__(cls)
new._init_gauda(*args, **kwargs)
return new
由于我最初的回答受到了批评,因为我的特殊用途构造函数没有调用(唯一的)默认构造函数,我在这里发布了一个修改版本,以尊重所有构造函数都应该调用默认构造函数的愿望:
class Cheese:
def __init__(self, *args, _initialiser="_default_init", **kwargs):
"""A multi-initialiser.
"""
getattr(self, _initialiser)(*args, **kwargs)
def _default_init(self, ...):
"""A user-friendly smart or general-purpose initialiser.
"""
...
def _init_parmesan(self, ...):
"""A special initialiser for Parmesan cheese.
"""
...
def _init_gouda(self, ...):
"""A special initialiser for Gouda cheese.
"""
...
@classmethod
def make_parmesan(cls, *args, **kwargs):
return cls(*args, **kwargs, _initialiser="_init_parmesan")
@classmethod
def make_gouda(cls, *args, **kwargs):
return cls(*args, **kwargs, _initialiser="_init_gouda")
为什么你认为你的解决方案“笨拙”?就我个人而言,在你这样的情况下,我更喜欢一个具有默认值的构造函数,而不是多个重载构造函数(Python不支持方法重载):
def __init__(self, num_holes=None):
if num_holes is None:
# Construct a gouda
else:
# custom cheese
# common initialization
对于有很多不同构造函数的非常复杂的情况,使用不同的工厂函数可能会更干净:
@classmethod
def create_gouda(cls):
c = Cheese()
# ...
return c
@classmethod
def create_cheddar(cls):
# ...
在你的奶酪的例子中,你可能想要使用奶酪的一个Gouda子类…