是否有一种方法可以使用Tuple类，但在其中提供项目的名称?
例如:
public Tuple<int, int, int int> GetOrderRelatedIds()
它返回OrderGroupId、OrderTypeId、OrderSubTypeId和OrderRequirementId的id。
让我的方法的用户知道哪个是哪个就好了。(当您调用该方法时，结果为result。Item1,结果。第二条,结果。Item3 result.Item4。不清楚哪个是哪个。)
(我知道我可以创建一个类来保存所有这些id，但这些id已经有自己的类，它们生活在其中，为这个方法的返回值创建一个类似乎很愚蠢。)
当前回答
到今天为止，就是这么简单。而不是使用Tuple关键字
public Tuple<int, int, int int> GetOrderRelatedIds()
用这个。
public (int alpha, int beta, int candor) GetOrderRelatedIds()
得到这样的值。
var a = GetOrderRelatedIds();
var c = a.alpha;
其他回答
在c# 7.0 (Visual Studio 2017)中，有一个新的结构可以做到这一点:
(string first, string middle, string last) LookupName(long id)
如果你的项目类型都不同，这里是一个类，我做了更直观地获得他们。
这个类的用法:
var t = TypedTuple.Create("hello", 1, new MyClass());
var s = t.Get<string>();
var i = t.Get<int>();
var c = t.Get<MyClass>();
源代码:
public static class TypedTuple
{
public static TypedTuple<T1> Create<T1>(T1 t1)
{
return new TypedTuple<T1>(t1);
}
public static TypedTuple<T1, T2> Create<T1, T2>(T1 t1, T2 t2)
{
return new TypedTuple<T1, T2>(t1, t2);
}
public static TypedTuple<T1, T2, T3> Create<T1, T2, T3>(T1 t1, T2 t2, T3 t3)
{
return new TypedTuple<T1, T2, T3>(t1, t2, t3);
}
public static TypedTuple<T1, T2, T3, T4> Create<T1, T2, T3, T4>(T1 t1, T2 t2, T3 t3, T4 t4)
{
return new TypedTuple<T1, T2, T3, T4>(t1, t2, t3, t4);
}
public static TypedTuple<T1, T2, T3, T4, T5> Create<T1, T2, T3, T4, T5>(T1 t1, T2 t2, T3 t3, T4 t4, T5 t5)
{
return new TypedTuple<T1, T2, T3, T4, T5>(t1, t2, t3, t4, t5);
}
public static TypedTuple<T1, T2, T3, T4, T5, T6> Create<T1, T2, T3, T4, T5, T6>(T1 t1, T2 t2, T3 t3, T4 t4, T5 t5, T6 t6)
{
return new TypedTuple<T1, T2, T3, T4, T5, T6>(t1, t2, t3, t4, t5, t6);
}
public static TypedTuple<T1, T2, T3, T4, T5, T6, T7> Create<T1, T2, T3, T4, T5, T6, T7>(T1 t1, T2 t2, T3 t3, T4 t4, T5 t5, T6 t6, T7 t7)
{
return new TypedTuple<T1, T2, T3, T4, T5, T6, T7>(t1, t2, t3, t4, t5, t6, t7);
}
public static TypedTuple<T1, T2, T3, T4, T5, T6, T7, T8> Create<T1, T2, T3, T4, T5, T6, T7, T8>(T1 t1, T2 t2, T3 t3, T4 t4, T5 t5, T6 t6, T7 t7, T8 t8)
{
return new TypedTuple<T1, T2, T3, T4, T5, T6, T7, T8>(t1, t2, t3, t4, t5, t6, t7, t8);
}
}
public class TypedTuple<T>
{
protected Dictionary<Type, object> items = new Dictionary<Type, object>();
public TypedTuple(T item1)
{
Item1 = item1;
}
public TSource Get<TSource>()
{
object value;
if (this.items.TryGetValue(typeof(TSource), out value))
{
return (TSource)value;
}
else
return default(TSource);
}
private T item1;
public T Item1 { get { return this.item1; } set { this.item1 = value; this.items[typeof(T)] = value; } }
}
public class TypedTuple<T1, T2> : TypedTuple<T1>
{
public TypedTuple(T1 item1, T2 item2)
: base(item1)
{
Item2 = item2;
}
private T2 item2;
public T2 Item2 { get { return this.item2; } set { this.item2 = value; this.items[typeof(T2)] = value; } }
}
public class TypedTuple<T1, T2, T3> : TypedTuple<T1, T2>
{
public TypedTuple(T1 item1, T2 item2, T3 item3)
: base(item1, item2)
{
Item3 = item3;
}
private T3 item3;
public T3 Item3 { get { return this.item3; } set { this.item3 = value; this.items[typeof(T3)] = value; } }
}
public class TypedTuple<T1, T2, T3, T4> : TypedTuple<T1, T2, T3>
{
public TypedTuple(T1 item1, T2 item2, T3 item3, T4 item4)
: base(item1, item2, item3)
{
Item4 = item4;
}
private T4 item4;
public T4 Item4 { get { return this.item4; } set { this.item4 = value; this.items[typeof(T4)] = value; } }
}
public class TypedTuple<T1, T2, T3, T4, T5> : TypedTuple<T1, T2, T3, T4>
{
public TypedTuple(T1 item1, T2 item2, T3 item3, T4 item4, T5 item5)
: base(item1, item2, item3, item4)
{
Item5 = item5;
}
private T5 item5;
public T5 Item5 { get { return this.item5; } set { this.item5 = value; this.items[typeof(T5)] = value; } }
}
public class TypedTuple<T1, T2, T3, T4, T5, T6> : TypedTuple<T1, T2, T3, T4, T5>
{
public TypedTuple(T1 item1, T2 item2, T3 item3, T4 item4, T5 item5, T6 item6)
: base(item1, item2, item3, item4, item5)
{
Item6 = item6;
}
private T6 item6;
public T6 Item6 { get { return this.item6; } set { this.item6 = value; this.items[typeof(T6)] = value; } }
}
public class TypedTuple<T1, T2, T3, T4, T5, T6, T7> : TypedTuple<T1, T2, T3, T4, T5, T6>
{
public TypedTuple(T1 item1, T2 item2, T3 item3, T4 item4, T5 item5, T6 item6, T7 item7)
: base(item1, item2, item3, item4, item5, item6)
{
Item7 = item7;
}
private T7 item7;
public T7 Item7 { get { return this.item7; } set { this.item7 = value; this.items[typeof(T7)] = value; } }
}
public class TypedTuple<T1, T2, T3, T4, T5, T6, T7, T8> : TypedTuple<T1, T2, T3, T4, T5, T6, T7>
{
public TypedTuple(T1 item1, T2 item2, T3 item3, T4 item4, T5 item5, T6 item6, T7 item7, T8 item8)
: base(item1, item2, item3, item4, item5, item6, item7)
{
Item8 = item8;
}
private T8 item8;
public T8 Item8 { get { return this.item8; } set { this.item8 = value; this.items[typeof(T8)] = value; } }
}
只是补充一下@MichaelMocko的答案。元组目前有几个陷阱:
你不能在EF表达式树中使用它们
例子:
public static (string name, string surname) GetPersonName(this PersonContext ctx, int id)
{
return ctx.Persons
.Where(person => person.Id == id)
// Selecting as Tuple
.Select(person => (person.Name, person.Surname))
.First();
}
这将导致编译失败，出现“表达式树可能不包含元组文字”错误。不幸的是，表达式树API在向语言中添加元组时并没有扩展对元组的支持。
跟踪(并投票)这个问题的更新:https://github.com/dotnet/roslyn/issues/12897
为了解决这个问题，你可以先将其转换为匿名类型，然后将值转换为元组:
// Will work
public static (string name, string surname) GetPersonName(this PersonContext ctx, int id)
{
return ctx.Persons
.Where(person => person.Id == id)
.Select(person => new { person.Name, person.Surname })
.ToList()
.Select(person => (person.Name, person.Surname))
.First();
}
另一种选择是使用ValueTuple。创建:
// Will work
public static (string name, string surname) GetPersonName(this PersonContext ctx, int id)
{
return ctx.Persons
.Where(person => person.Id == id)
.Select(person => ValueTuple.Create(person.Name, person.Surname))
.First();
}
引用:
https://www.damirscorner.com/blog/posts/20181207-NoSupportForTuplesInExpressionTrees.html 将匿名类型转换为新的c# 7元组类型
你不能用lambda解构它们
有一个增加支持的提议:https://github.com/dotnet/csharplang/issues/258
例子:
public static IQueryable<(string name, string surname)> GetPersonName(this PersonContext ctx, int id)
{
return ctx.Persons
.Where(person => person.Id == id)
.Select(person => ValueTuple.Create(person.Name, person.Surname));
}
// This won't work
ctx.GetPersonName(id).Select((name, surname) => { return name + surname; })
// But this will
ctx.GetPersonName(id).Select(t => { return t.name + t.surname; })
引用:
c# 7元组和lambda
它们不会很好地连载
using System;
using Newtonsoft.Json;
public class Program
{
public static void Main() {
var me = (age: 21, favoriteFood: "Custard");
string json = JsonConvert.SerializeObject(me);
// Will output {"Item1":21,"Item2":"Custard"}
Console.WriteLine(json);
}
}
元组字段名仅在编译时可用，并在运行时完全删除。
引用:
使值元组属性名在运行时可解析 c# 7元组支持(Newtonsoft.Json)
不，你不能命名元组成员。
中间的方法是使用ExpandoObject而不是Tuple。
从这篇文章中复制我的答案，因为它更适合这里。
从c# v7.0开始，现在可以将元组属性命名为Item1、Item2等早先默认的名称。
命名元组字面量的属性:
var myDetails = (MyName: "Foo", MyAge: 22, MyFavoriteFood: "Bar");
Console.WriteLine($"Name - {myDetails.MyName}, Age - {myDetails.MyAge}, Passion - {myDetails.MyFavoriteFood}");
控制台的输出:
Name - Foo, Age - 22, Passion - Bar
从一个方法返回元组(有命名属性):
static void Main(string[] args)
{
var empInfo = GetEmpInfo();
Console.WriteLine($"Employee Details: {empInfo.firstName}, {empInfo.lastName}, {empInfo.computerName}, {empInfo.Salary}");
}
static (string firstName, string lastName, string computerName, int Salary) GetEmpInfo()
{
//This is hardcoded just for the demonstration. Ideally this data might be coming from some DB or web service call
return ("Foo", "Bar", "Foo-PC", 1000);
}
控制台的输出:
Employee Details: Foo, Bar, Foo-PC, 1000
创建具有命名属性的元组列表
var tupleList = new List<(int Index, string Name)>
{
(1, "cow"),
(5, "chickens"),
(1, "airplane")
};
foreach (var tuple in tupleList)
Console.WriteLine($"{tuple.Index} - {tuple.Name}");
控制台输出:
1 - cow
5 - chickens
1 - airplane
注意:本文中的代码片段使用了c# v6的字符串插值特性。
