使用lambda的简单方法是这样的..

Thread t = new Thread(() => DoSomething("param1", "param2"));
t.Start();

或者你甚至可以像这样使用ThreadStart委托…

private void DoSomething(int param1, string param2)
{
    //DO SOMETHING...
    ThreadStart ts = delegate
    {
        if (param1 > 0) DoSomethingElse(param2, "param3");
    };   
    new Thread(ts).Start();
    //DO SOMETHING...
}

或者使用。net 4.5+甚至更干净，像这样..

private void DoSomething(int param1, string param2)
{
    //DO SOMETHING..
    void ts()
    {
        if (param1 > 0) DoSomethingElse(param2, "param3");
    }
    new Thread(ts).Start();
    //DO SOMETHING..
}

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Threading;

namespace ConsoleApp6
{
    class Program
    {
        static void Main(string[] args)
        {

            int x = 10;
            Thread t1 =new Thread(new ParameterizedThreadStart(order1));
            t1.IsBackground = true;//i can stope 
            t1.Start(x);

            Thread t2=new Thread(order2);
            t2.Priority = ThreadPriority.Highest;
            t2.Start();

            Console.ReadKey();
        }//Main

        static void  order1(object args)
        {
            int x = (int)args;


                for (int i = 0; i < x; i++)
            {
                Console.ForegroundColor = ConsoleColor.Green;
                Console.Write(i.ToString() + " ");
            }
        }

        static void order2()
        {
            for (int i = 100; i > 0; i--)
            {
                Console.ForegroundColor = ConsoleColor.Red;
                Console.Write(i.ToString() + " ");
            }
        }`enter code here`
    }
}

class Program
{
    static void Main(string[] args)
    {
        Thread t = new Thread(new ParameterizedThreadStart(ThreadMethod));

        t.Start("My Parameter");
    }

    static void ThreadMethod(object parameter)
    {
        // parameter equals to "My Parameter"
    }
}

你可以使用lambda表达式

private void MyMethod(string param1,int param2)
{
  //do stuff
}
Thread myNewThread = new Thread(() => MyMethod("param1",5));
myNewThread.Start();

这是目前为止我能找到的最好的答案，又快又简单。

我在传递参数时有问题。 我将一个整数从for循环传递给函数并显示它，但它总是给出不同的结果。例如(1,2,2,3)(1,2,3,3)(1,1,2,3)等与paramtrizedthreadstart委托。

这个简单的代码很有魔力

Thread thread = new Thread(Work);
thread.Start(Parameter);

private void Work(object param) 
{
 string Parameter = (string)param; 
}

你可以使用一个paramtrizedthreadstart委托:

string parameter = "Hello world!";
Thread t = new Thread(new ParameterizedThreadStart(MyMethod));
t.Start(parameter);