在Android中限制EditText文本长度的最佳方法是什么?

有没有通过xml实现这一点的方法?


当前回答

对于其他想知道如何实现这一点的人,这里是我的扩展EditText类EditTextNumeric。

.setMaxLength(int)-设置最大位数

.setMaxValue(int)-限制最大整数值

.setMin(int)-限制最小整数值

.getValue()-获取整数值

import android.content.Context;
import android.text.InputFilter;
import android.text.InputType;
import android.widget.EditText;

public class EditTextNumeric extends EditText {
    protected int max_value = Integer.MAX_VALUE;
    protected int min_value = Integer.MIN_VALUE;

    // constructor
    public EditTextNumeric(Context context) {
        super(context);
        this.setInputType(InputType.TYPE_CLASS_NUMBER);
    }

    // checks whether the limits are set and corrects them if not within limits
    @Override
    protected void onTextChanged(CharSequence text, int start, int before, int after) {
        if (max_value != Integer.MAX_VALUE) {
            try {
                if (Integer.parseInt(this.getText().toString()) > max_value) {
                    // change value and keep cursor position
                    int selection = this.getSelectionStart();
                    this.setText(String.valueOf(max_value));
                    if (selection >= this.getText().toString().length()) {
                        selection = this.getText().toString().length();
                    }
                    this.setSelection(selection);
                }
            } catch (NumberFormatException exception) {
                super.onTextChanged(text, start, before, after);
            }
        }
        if (min_value != Integer.MIN_VALUE) {
            try {
                if (Integer.parseInt(this.getText().toString()) < min_value) {
                    // change value and keep cursor position
                    int selection = this.getSelectionStart();
                    this.setText(String.valueOf(min_value));
                    if (selection >= this.getText().toString().length()) {
                        selection = this.getText().toString().length();
                    }
                    this.setSelection(selection);
                }
            } catch (NumberFormatException exception) {
                super.onTextChanged(text, start, before, after);
            }
        }
        super.onTextChanged(text, start, before, after);
    }

    // set the max number of digits the user can enter
    public void setMaxLength(int length) {
        InputFilter[] FilterArray = new InputFilter[1];
        FilterArray[0] = new InputFilter.LengthFilter(length);
        this.setFilters(FilterArray);
    }

    // set the maximum integer value the user can enter.
    // if exeeded, input value will become equal to the set limit
    public void setMaxValue(int value) {
        max_value = value;
    }
    // set the minimum integer value the user can enter.
    // if entered value is inferior, input value will become equal to the set limit
    public void setMinValue(int value) {
        min_value = value;
    }

    // returns integer value or 0 if errorous value
    public int getValue() {
        try {
            return Integer.parseInt(this.getText().toString());
        } catch (NumberFormatException exception) {
            return 0;
        }
    }
}

示例用法:

final EditTextNumeric input = new EditTextNumeric(this);
input.setMaxLength(5);
input.setMaxValue(total_pages);
input.setMinValue(1);

当然,适用于EditText的所有其他方法和属性也都有效。

其他回答

我看到了很多好的解决方案,但我想给出一个我认为更完整、更人性化的解决方案:

1、限制长度。2、如果输入更多,则发出回调以触发吐司。3、光标可以在中间或尾部。4、用户可以通过粘贴字符串进行输入。5、始终丢弃溢出输入并保留原点。

public class LimitTextWatcher implements TextWatcher {

    public interface IF_callback{
        void callback(int left);
    }

    public IF_callback if_callback;

    EditText editText;
    int maxLength;

    int cursorPositionLast;
    String textLast;
    boolean bypass;

    public LimitTextWatcher(EditText editText, int maxLength, IF_callback if_callback) {

        this.editText = editText;
        this.maxLength = maxLength;
        this.if_callback = if_callback;
    }

    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {

        if (bypass) {

            bypass = false;

        } else {

            StringBuilder stringBuilder = new StringBuilder();
            stringBuilder.append(s);
            textLast = stringBuilder.toString();

            this.cursorPositionLast = editText.getSelectionStart();
        }
    }

    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count) {

    }

    @Override
    public void afterTextChanged(Editable s) {
        if (s.toString().length() > maxLength) {

            int left = maxLength - s.toString().length();

            bypass = true;
            s.clear();

            bypass = true;
            s.append(textLast);

            editText.setSelection(this.cursorPositionLast);

            if (if_callback != null) {
                if_callback.callback(left);
            }
        }

    }

}


edit_text.addTextChangedListener(new LimitTextWatcher(edit_text, MAX_LENGTH, new LimitTextWatcher.IF_callback() {
    @Override
    public void callback(int left) {
        if(left <= 0) {
            Toast.makeText(MainActivity.this, "input is full", Toast.LENGTH_SHORT).show();
        }
    }
}));

我没能做到的是,如果用户高亮显示当前输入的一部分并试图粘贴一个很长的字符串,我不知道如何恢复高亮显示。

例如,最大长度设置为10,用户输入“12345678”,并将“345”标记为突出显示,然后尝试粘贴一个超过限制的字符串“0000”。

当我尝试使用edit_text.setSelection(start=2,end=4)恢复原点状态时,结果是,它只插入2个空格作为“12 345 678”,而不是原点高亮显示。我希望有人解决这个问题。

科特林:

edit_text.filters += InputFilter.LengthFilter(10)

中兴刀片A520具有奇怪的效果。当您键入超过10个符号(例如15个)时,EditText将显示前10个符号,但其他5个符号不可见且不可访问。但当您使用Backspace删除符号时,它会先删除右边的5个符号,然后删除剩下的10个符号。要克服这种行为,请使用以下解决方案:

android:inputType="textNoSuggestions|textVisiblePassword"
android:maxLength="10"

或者:

android:inputType="textNoSuggestions"

或者,如果您想获得建议:

private class EditTextWatcher(private val view: EditText) : TextWatcher {
    private var position = 0
    private var oldText = ""

    override fun afterTextChanged(s: Editable?) = Unit

    override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
        oldText = s?.toString() ?: ""
        position = view.selectionStart
    }

    override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
        val newText = s?.toString() ?: ""
        if (newText.length > 10) {
            with(view) {
                setText(oldText)
                position = if (start > 0 && count > 2) {
                    // Text paste in nonempty field.
                    start
                } else {
                    if (position in 1..10 + 1) {
                        // Symbol paste in the beginning or middle of the field.
                        position - 1
                    } else {
                        if (start > 0) {
                            // Adding symbol to the end of the field.
                            start - 1
                        } else {
                            // Text paste in the empty field.
                            0
                        }
                    }
                }
                setSelection(position)
            }
        }
    }
}

// Usage:
editTextWatcher = EditTextWatcher(view.edit_text)
view.edit_text.addTextChangedListener(editTextWatcher)
TextView tv = new TextView(this);
tv.setFilters(new InputFilter[]{ new InputFilter.LengthFilter(250) });
//Set Length filter. Restricting to 10 characters only
editText.setFilters(new InputFilter[]{new InputFilter.LengthFilter(MAX_LENGTH)});

//Allowing only upper case characters
editText.setFilters(new InputFilter[]{new InputFilter.AllCaps()});

//Attaching multiple filters
editText.setFilters(new InputFilter[]{new InputFilter.LengthFilter(MAX_LENGTH), new InputFilter.AllCaps()});

文档

实例

android:maxLength="10"