在Android中限制EditText文本长度的最佳方法是什么?
有没有通过xml实现这一点的方法?
在Android中限制EditText文本长度的最佳方法是什么?
有没有通过xml实现这一点的方法?
当前回答
对于其他想知道如何实现这一点的人,这里是我的扩展EditText类EditTextNumeric。
.setMaxLength(int)-设置最大位数
.setMaxValue(int)-限制最大整数值
.setMin(int)-限制最小整数值
.getValue()-获取整数值
import android.content.Context;
import android.text.InputFilter;
import android.text.InputType;
import android.widget.EditText;
public class EditTextNumeric extends EditText {
protected int max_value = Integer.MAX_VALUE;
protected int min_value = Integer.MIN_VALUE;
// constructor
public EditTextNumeric(Context context) {
super(context);
this.setInputType(InputType.TYPE_CLASS_NUMBER);
}
// checks whether the limits are set and corrects them if not within limits
@Override
protected void onTextChanged(CharSequence text, int start, int before, int after) {
if (max_value != Integer.MAX_VALUE) {
try {
if (Integer.parseInt(this.getText().toString()) > max_value) {
// change value and keep cursor position
int selection = this.getSelectionStart();
this.setText(String.valueOf(max_value));
if (selection >= this.getText().toString().length()) {
selection = this.getText().toString().length();
}
this.setSelection(selection);
}
} catch (NumberFormatException exception) {
super.onTextChanged(text, start, before, after);
}
}
if (min_value != Integer.MIN_VALUE) {
try {
if (Integer.parseInt(this.getText().toString()) < min_value) {
// change value and keep cursor position
int selection = this.getSelectionStart();
this.setText(String.valueOf(min_value));
if (selection >= this.getText().toString().length()) {
selection = this.getText().toString().length();
}
this.setSelection(selection);
}
} catch (NumberFormatException exception) {
super.onTextChanged(text, start, before, after);
}
}
super.onTextChanged(text, start, before, after);
}
// set the max number of digits the user can enter
public void setMaxLength(int length) {
InputFilter[] FilterArray = new InputFilter[1];
FilterArray[0] = new InputFilter.LengthFilter(length);
this.setFilters(FilterArray);
}
// set the maximum integer value the user can enter.
// if exeeded, input value will become equal to the set limit
public void setMaxValue(int value) {
max_value = value;
}
// set the minimum integer value the user can enter.
// if entered value is inferior, input value will become equal to the set limit
public void setMinValue(int value) {
min_value = value;
}
// returns integer value or 0 if errorous value
public int getValue() {
try {
return Integer.parseInt(this.getText().toString());
} catch (NumberFormatException exception) {
return 0;
}
}
}
示例用法:
final EditTextNumeric input = new EditTextNumeric(this);
input.setMaxLength(5);
input.setMaxValue(total_pages);
input.setMinValue(1);
当然,适用于EditText的所有其他方法和属性也都有效。
其他回答
TextView tv = new TextView(this);
tv.setFilters(new InputFilter[]{ new InputFilter.LengthFilter(250) });
您可以在EditText中使用android:maxLength=“10”。(此处限制为最多10个字符)
我看到了很多好的解决方案,但我想给出一个我认为更完整、更人性化的解决方案:
1、限制长度。2、如果输入更多,则发出回调以触发吐司。3、光标可以在中间或尾部。4、用户可以通过粘贴字符串进行输入。5、始终丢弃溢出输入并保留原点。
public class LimitTextWatcher implements TextWatcher {
public interface IF_callback{
void callback(int left);
}
public IF_callback if_callback;
EditText editText;
int maxLength;
int cursorPositionLast;
String textLast;
boolean bypass;
public LimitTextWatcher(EditText editText, int maxLength, IF_callback if_callback) {
this.editText = editText;
this.maxLength = maxLength;
this.if_callback = if_callback;
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
if (bypass) {
bypass = false;
} else {
StringBuilder stringBuilder = new StringBuilder();
stringBuilder.append(s);
textLast = stringBuilder.toString();
this.cursorPositionLast = editText.getSelectionStart();
}
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
if (s.toString().length() > maxLength) {
int left = maxLength - s.toString().length();
bypass = true;
s.clear();
bypass = true;
s.append(textLast);
editText.setSelection(this.cursorPositionLast);
if (if_callback != null) {
if_callback.callback(left);
}
}
}
}
edit_text.addTextChangedListener(new LimitTextWatcher(edit_text, MAX_LENGTH, new LimitTextWatcher.IF_callback() {
@Override
public void callback(int left) {
if(left <= 0) {
Toast.makeText(MainActivity.this, "input is full", Toast.LENGTH_SHORT).show();
}
}
}));
我没能做到的是,如果用户高亮显示当前输入的一部分并试图粘贴一个很长的字符串,我不知道如何恢复高亮显示。
例如,最大长度设置为10,用户输入“12345678”,并将“345”标记为突出显示,然后尝试粘贴一个超过限制的字符串“0000”。
当我尝试使用edit_text.setSelection(start=2,end=4)恢复原点状态时,结果是,它只插入2个空格作为“12 345 678”,而不是原点高亮显示。我希望有人解决这个问题。
在material.io中,可以将TextInputEditText与TextInputLayout结合使用:
<com.google.android.material.textfield.TextInputLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
app:counterEnabled="true"
app:counterMaxLength="1000"
app:passwordToggleEnabled="false">
<com.google.android.material.textfield.TextInputEditText
android:id="@+id/edit_text"
android:hint="@string/description"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:maxLength="1000"
android:gravity="top|start"
android:inputType="textMultiLine|textNoSuggestions"/>
</com.google.android.material.textfield.TextInputLayout>
您可以使用drawbable配置密码EditText:
或者,可以使用/不使用计数器限制文本长度:
附属国:
implementation 'com.google.android.material:material:1.1.0-alpha02'
对于其他想知道如何实现这一点的人,这里是我的扩展EditText类EditTextNumeric。
.setMaxLength(int)-设置最大位数
.setMaxValue(int)-限制最大整数值
.setMin(int)-限制最小整数值
.getValue()-获取整数值
import android.content.Context;
import android.text.InputFilter;
import android.text.InputType;
import android.widget.EditText;
public class EditTextNumeric extends EditText {
protected int max_value = Integer.MAX_VALUE;
protected int min_value = Integer.MIN_VALUE;
// constructor
public EditTextNumeric(Context context) {
super(context);
this.setInputType(InputType.TYPE_CLASS_NUMBER);
}
// checks whether the limits are set and corrects them if not within limits
@Override
protected void onTextChanged(CharSequence text, int start, int before, int after) {
if (max_value != Integer.MAX_VALUE) {
try {
if (Integer.parseInt(this.getText().toString()) > max_value) {
// change value and keep cursor position
int selection = this.getSelectionStart();
this.setText(String.valueOf(max_value));
if (selection >= this.getText().toString().length()) {
selection = this.getText().toString().length();
}
this.setSelection(selection);
}
} catch (NumberFormatException exception) {
super.onTextChanged(text, start, before, after);
}
}
if (min_value != Integer.MIN_VALUE) {
try {
if (Integer.parseInt(this.getText().toString()) < min_value) {
// change value and keep cursor position
int selection = this.getSelectionStart();
this.setText(String.valueOf(min_value));
if (selection >= this.getText().toString().length()) {
selection = this.getText().toString().length();
}
this.setSelection(selection);
}
} catch (NumberFormatException exception) {
super.onTextChanged(text, start, before, after);
}
}
super.onTextChanged(text, start, before, after);
}
// set the max number of digits the user can enter
public void setMaxLength(int length) {
InputFilter[] FilterArray = new InputFilter[1];
FilterArray[0] = new InputFilter.LengthFilter(length);
this.setFilters(FilterArray);
}
// set the maximum integer value the user can enter.
// if exeeded, input value will become equal to the set limit
public void setMaxValue(int value) {
max_value = value;
}
// set the minimum integer value the user can enter.
// if entered value is inferior, input value will become equal to the set limit
public void setMinValue(int value) {
min_value = value;
}
// returns integer value or 0 if errorous value
public int getValue() {
try {
return Integer.parseInt(this.getText().toString());
} catch (NumberFormatException exception) {
return 0;
}
}
}
示例用法:
final EditTextNumeric input = new EditTextNumeric(this);
input.setMaxLength(5);
input.setMaxValue(total_pages);
input.setMinValue(1);
当然,适用于EditText的所有其他方法和属性也都有效。