在Android中限制EditText文本长度的最佳方法是什么?
有没有通过xml实现这一点的方法?
在Android中限制EditText文本长度的最佳方法是什么?
有没有通过xml实现这一点的方法?
当前回答
对于其他想知道如何实现这一点的人,这里是我的扩展EditText类EditTextNumeric。
.setMaxLength(int)-设置最大位数
.setMaxValue(int)-限制最大整数值
.setMin(int)-限制最小整数值
.getValue()-获取整数值
import android.content.Context;
import android.text.InputFilter;
import android.text.InputType;
import android.widget.EditText;
public class EditTextNumeric extends EditText {
protected int max_value = Integer.MAX_VALUE;
protected int min_value = Integer.MIN_VALUE;
// constructor
public EditTextNumeric(Context context) {
super(context);
this.setInputType(InputType.TYPE_CLASS_NUMBER);
}
// checks whether the limits are set and corrects them if not within limits
@Override
protected void onTextChanged(CharSequence text, int start, int before, int after) {
if (max_value != Integer.MAX_VALUE) {
try {
if (Integer.parseInt(this.getText().toString()) > max_value) {
// change value and keep cursor position
int selection = this.getSelectionStart();
this.setText(String.valueOf(max_value));
if (selection >= this.getText().toString().length()) {
selection = this.getText().toString().length();
}
this.setSelection(selection);
}
} catch (NumberFormatException exception) {
super.onTextChanged(text, start, before, after);
}
}
if (min_value != Integer.MIN_VALUE) {
try {
if (Integer.parseInt(this.getText().toString()) < min_value) {
// change value and keep cursor position
int selection = this.getSelectionStart();
this.setText(String.valueOf(min_value));
if (selection >= this.getText().toString().length()) {
selection = this.getText().toString().length();
}
this.setSelection(selection);
}
} catch (NumberFormatException exception) {
super.onTextChanged(text, start, before, after);
}
}
super.onTextChanged(text, start, before, after);
}
// set the max number of digits the user can enter
public void setMaxLength(int length) {
InputFilter[] FilterArray = new InputFilter[1];
FilterArray[0] = new InputFilter.LengthFilter(length);
this.setFilters(FilterArray);
}
// set the maximum integer value the user can enter.
// if exeeded, input value will become equal to the set limit
public void setMaxValue(int value) {
max_value = value;
}
// set the minimum integer value the user can enter.
// if entered value is inferior, input value will become equal to the set limit
public void setMinValue(int value) {
min_value = value;
}
// returns integer value or 0 if errorous value
public int getValue() {
try {
return Integer.parseInt(this.getText().toString());
} catch (NumberFormatException exception) {
return 0;
}
}
}
示例用法:
final EditTextNumeric input = new EditTextNumeric(this);
input.setMaxLength(5);
input.setMaxValue(total_pages);
input.setMinValue(1);
当然,适用于EditText的所有其他方法和属性也都有效。
其他回答
科特林:
edit_text.filters += InputFilter.LengthFilter(10)
中兴刀片A520具有奇怪的效果。当您键入超过10个符号(例如15个)时,EditText将显示前10个符号,但其他5个符号不可见且不可访问。但当您使用Backspace删除符号时,它会先删除右边的5个符号,然后删除剩下的10个符号。要克服这种行为,请使用以下解决方案:
android:inputType="textNoSuggestions|textVisiblePassword"
android:maxLength="10"
或者:
android:inputType="textNoSuggestions"
或者,如果您想获得建议:
private class EditTextWatcher(private val view: EditText) : TextWatcher {
private var position = 0
private var oldText = ""
override fun afterTextChanged(s: Editable?) = Unit
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
oldText = s?.toString() ?: ""
position = view.selectionStart
}
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
val newText = s?.toString() ?: ""
if (newText.length > 10) {
with(view) {
setText(oldText)
position = if (start > 0 && count > 2) {
// Text paste in nonempty field.
start
} else {
if (position in 1..10 + 1) {
// Symbol paste in the beginning or middle of the field.
position - 1
} else {
if (start > 0) {
// Adding symbol to the end of the field.
start - 1
} else {
// Text paste in the empty field.
0
}
}
}
setSelection(position)
}
}
}
}
// Usage:
editTextWatcher = EditTextWatcher(view.edit_text)
view.edit_text.addTextChangedListener(editTextWatcher)
对于已经使用自定义输入筛选器并希望限制最大长度的用户,请注意:
当您在代码中分配输入过滤器时,所有先前设置的输入过滤器都将被清除,包括一个使用android:maxLength设置的过滤器。我在尝试使用自定义输入筛选器以防止在密码字段中使用某些不允许的字符时发现了这一点。使用setFilters设置过滤器后,不再观察到maxLength。解决方案是以编程方式将maxLength和自定义过滤器设置在一起。类似于:
myEditText.setFilters(new InputFilter[] {
new PasswordCharFilter(), new InputFilter.LengthFilter(20)
});
这是一个自定义的EditText类,允许长度筛选器与其他筛选器一起使用。感谢Tim Gallagher的回答(如下)
import android.content.Context;
import android.text.InputFilter;
import android.util.AttributeSet;
import android.widget.EditText;
public class EditTextMultiFiltering extends EditText{
public EditTextMultiFiltering(Context context) {
super(context);
}
public EditTextMultiFiltering(Context context, AttributeSet attrs) {
super(context, attrs);
}
public EditTextMultiFiltering(Context context, AttributeSet attrs, int defStyleAttr) {
super(context, attrs, defStyleAttr);
}
public void setMaxLength(int length) {
InputFilter curFilters[];
InputFilter.LengthFilter lengthFilter;
int idx;
lengthFilter = new InputFilter.LengthFilter(length);
curFilters = this.getFilters();
if (curFilters != null) {
for (idx = 0; idx < curFilters.length; idx++) {
if (curFilters[idx] instanceof InputFilter.LengthFilter) {
curFilters[idx] = lengthFilter;
return;
}
}
// since the length filter was not part of the list, but
// there are filters, then add the length filter
InputFilter newFilters[] = new InputFilter[curFilters.length + 1];
System.arraycopy(curFilters, 0, newFilters, 0, curFilters.length);
newFilters[curFilters.length] = lengthFilter;
this.setFilters(newFilters);
} else {
this.setFilters(new InputFilter[] { lengthFilter });
}
}
}
使用输入筛选器限制文本视图的最大长度。
TextView editEntryView = new TextView(...);
InputFilter[] filterArray = new InputFilter[1];
filterArray[0] = new InputFilter.LengthFilter(8);
editEntryView.setFilters(filterArray);
文档
实例
android:maxLength="10"