由于goto10的观察，我将以下代码组合在一起，通过设置最大长度来防止丢失其他过滤器：

/**
 * This sets the maximum length in characters of an EditText view. Since the
 * max length must be done with a filter, this method gets the current
 * filters. If there is already a length filter in the view, it will replace
 * it, otherwise, it will add the max length filter preserving the other
 * 
 * @param view
 * @param length
 */
public static void setMaxLength(EditText view, int length) {
    InputFilter curFilters[];
    InputFilter.LengthFilter lengthFilter;
    int idx;

    lengthFilter = new InputFilter.LengthFilter(length);

    curFilters = view.getFilters();
    if (curFilters != null) {
        for (idx = 0; idx < curFilters.length; idx++) {
            if (curFilters[idx] instanceof InputFilter.LengthFilter) {
                curFilters[idx] = lengthFilter;
                return;
            }
        }

        // since the length filter was not part of the list, but
        // there are filters, then add the length filter
        InputFilter newFilters[] = new InputFilter[curFilters.length + 1];
        System.arraycopy(curFilters, 0, newFilters, 0, curFilters.length);
        newFilters[curFilters.length] = lengthFilter;
        view.setFilters(newFilters);
    } else {
        view.setFilters(new InputFilter[] { lengthFilter });
    }
}

xml中的简单方式：

android:maxLength="@{length}"

要以编程方式设置它，可以使用以下函数

public static void setMaxLengthOfEditText(EditText editText, int length) {
    InputFilter[] filters = editText.getFilters();
    List arrayList = new ArrayList();
    int i2 = 0;
    if (filters != null && filters.length > 0) {
        int filtersSize = filters.length;
        int i3 = 0;
        while (i2 < filtersSize) {
            Object obj = filters[i2];
            if (obj instanceof LengthFilter) {
                arrayList.add(new LengthFilter(length));
                i3 = 1;
            } else {
                arrayList.add(obj);
            }
            i2++;
        }
        i2 = i3;
    }
    if (i2 == 0) {
        arrayList.add(new LengthFilter(length));
    }
    if (!arrayList.isEmpty()) {
        editText.setFilters((InputFilter[]) arrayList.toArray(new InputFilter[arrayList.size()]));
    }
}

xml中的简单方式：

android:maxLength="4"

如果您需要在xml编辑文本中设置4个字符，请使用

<EditText
    android:id="@+id/edtUserCode"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:maxLength="4"
    android:hint="Enter user code" />

这是一个自定义的EditText类，允许长度筛选器与其他筛选器一起使用。感谢Tim Gallagher的回答（如下）

import android.content.Context;
import android.text.InputFilter;
import android.util.AttributeSet;
import android.widget.EditText;


public class EditTextMultiFiltering extends EditText{

    public EditTextMultiFiltering(Context context) {
        super(context);
    }

    public EditTextMultiFiltering(Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    public EditTextMultiFiltering(Context context, AttributeSet attrs, int defStyleAttr) {
        super(context, attrs, defStyleAttr);
    }

    public void setMaxLength(int length) {
        InputFilter curFilters[];
        InputFilter.LengthFilter lengthFilter;
        int idx;

        lengthFilter = new InputFilter.LengthFilter(length);

        curFilters = this.getFilters();
        if (curFilters != null) {
            for (idx = 0; idx < curFilters.length; idx++) {
                if (curFilters[idx] instanceof InputFilter.LengthFilter) {
                    curFilters[idx] = lengthFilter;
                    return;
                }
            }

            // since the length filter was not part of the list, but
            // there are filters, then add the length filter
            InputFilter newFilters[] = new InputFilter[curFilters.length + 1];
            System.arraycopy(curFilters, 0, newFilters, 0, curFilters.length);
            newFilters[curFilters.length] = lengthFilter;
            this.setFilters(newFilters);
        } else {
            this.setFilters(new InputFilter[] { lengthFilter });
        }
    }
}

科特林：

edit_text.filters += InputFilter.LengthFilter(10)

中兴刀片A520具有奇怪的效果。当您键入超过10个符号（例如15个）时，EditText将显示前10个符号，但其他5个符号不可见且不可访问。但当您使用Backspace删除符号时，它会先删除右边的5个符号，然后删除剩下的10个符号。要克服这种行为，请使用以下解决方案：

android:inputType="textNoSuggestions|textVisiblePassword"
android:maxLength="10"

或者：

android:inputType="textNoSuggestions"

或者，如果您想获得建议：

private class EditTextWatcher(private val view: EditText) : TextWatcher {
    private var position = 0
    private var oldText = ""

    override fun afterTextChanged(s: Editable?) = Unit

    override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
        oldText = s?.toString() ?: ""
        position = view.selectionStart
    }

    override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
        val newText = s?.toString() ?: ""
        if (newText.length > 10) {
            with(view) {
                setText(oldText)
                position = if (start > 0 && count > 2) {
                    // Text paste in nonempty field.
                    start
                } else {
                    if (position in 1..10 + 1) {
                        // Symbol paste in the beginning or middle of the field.
                        position - 1
                    } else {
                        if (start > 0) {
                            // Adding symbol to the end of the field.
                            start - 1
                        } else {
                            // Text paste in the empty field.
                            0
                        }
                    }
                }
                setSelection(position)
            }
        }
    }
}

// Usage:
editTextWatcher = EditTextWatcher(view.edit_text)
view.edit_text.addTextChangedListener(editTextWatcher)

我看到了很多好的解决方案，但我想给出一个我认为更完整、更人性化的解决方案：

1、限制长度。2、如果输入更多，则发出回调以触发吐司。3、光标可以在中间或尾部。4、用户可以通过粘贴字符串进行输入。5、始终丢弃溢出输入并保留原点。

public class LimitTextWatcher implements TextWatcher {

    public interface IF_callback{
        void callback(int left);
    }

    public IF_callback if_callback;

    EditText editText;
    int maxLength;

    int cursorPositionLast;
    String textLast;
    boolean bypass;

    public LimitTextWatcher(EditText editText, int maxLength, IF_callback if_callback) {

        this.editText = editText;
        this.maxLength = maxLength;
        this.if_callback = if_callback;
    }

    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after) {

        if (bypass) {

            bypass = false;

        } else {

            StringBuilder stringBuilder = new StringBuilder();
            stringBuilder.append(s);
            textLast = stringBuilder.toString();

            this.cursorPositionLast = editText.getSelectionStart();
        }
    }

    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count) {

    }

    @Override
    public void afterTextChanged(Editable s) {
        if (s.toString().length() > maxLength) {

            int left = maxLength - s.toString().length();

            bypass = true;
            s.clear();

            bypass = true;
            s.append(textLast);

            editText.setSelection(this.cursorPositionLast);

            if (if_callback != null) {
                if_callback.callback(left);
            }
        }

    }

}


edit_text.addTextChangedListener(new LimitTextWatcher(edit_text, MAX_LENGTH, new LimitTextWatcher.IF_callback() {
    @Override
    public void callback(int left) {
        if(left <= 0) {
            Toast.makeText(MainActivity.this, "input is full", Toast.LENGTH_SHORT).show();
        }
    }
}));

我没能做到的是，如果用户高亮显示当前输入的一部分并试图粘贴一个很长的字符串，我不知道如何恢复高亮显示。

例如，最大长度设置为10，用户输入“12345678”，并将“345”标记为突出显示，然后尝试粘贴一个超过限制的字符串“0000”。

当我尝试使用edit_text.setSelection（start=2，end=4）恢复原点状态时，结果是，它只插入2个空格作为“12 345 678”，而不是原点高亮显示。我希望有人解决这个问题。