我遇到了一个问题,我的主键序列与我的表行不同步。

也就是说,当我插入一个新行时,我得到一个重复的键错误,因为在串行数据类型中隐含的序列返回一个已经存在的数字。

这似乎是由于导入/恢复没有正确地维护序列造成的。


当前回答

重新启动所有序列到1使用:

-- Create Function
CREATE OR REPLACE FUNCTION "sy_restart_seq_to_1" (
    relname TEXT
)
RETURNS "pg_catalog"."void" AS
$BODY$

DECLARE

BEGIN
    EXECUTE 'ALTER SEQUENCE '||relname||' RESTART WITH 1;';
END;
$BODY$

LANGUAGE 'plpgsql';

-- Use Function
SELECT 
    relname
    ,sy_restart_seq_to_1(relname)
FROM pg_class
WHERE relkind = 'S';

其他回答

在下例中,表名为users,模式名为public(默认模式),请根据需要替换它。

1. 检查最大id:

SELECT MAX(id) FROM public.users;

2. 检查下一个值:

SELECT nextval('public."users_id_seq"');

3.如果下一个值小于最大id,重置它:

SELECT setval('public."users_id_seq"',
  (SELECT MAX(id) FROM public.users)
);

注意:

Nextval()将在返回当前值之前递增序列,而currval()将只返回当前值,如本文所述。

还有另一个plpgsql -仅当max(att) >时重置lastval

do --check seq not in sync
$$
declare
 _r record;
 _i bigint;
 _m bigint;
begin
  for _r in (
    SELECT relname,nspname,d.refobjid::regclass, a.attname, refobjid
    FROM   pg_depend    d
    JOIN   pg_attribute a ON a.attrelid = d.refobjid AND a.attnum = d.refobjsubid
    JOIN pg_class r on r.oid = objid
    JOIN pg_namespace n on n.oid = relnamespace
    WHERE  d.refobjsubid > 0 and  relkind = 'S'
   ) loop
    execute format('select last_value from %I.%I',_r.nspname,_r.relname) into _i;
    execute format('select max(%I) from %s',_r.attname,_r.refobjid) into _m;
    if coalesce(_m,0) > _i then
      raise info '%',concat('changed: ',_r.nspname,'.',_r.relname,' from:',_i,' to:',_m);
      execute format('alter sequence %I.%I restart with %s',_r.nspname,_r.relname,_m+1);
    end if;
  end loop;

end;
$$
;

另外注释行——execute format('alter sequence将给出列表,而不是实际重置值

我找不到Rails的明确答案。

从rails控制台

ActiveRecord::Base.connection.execute("SELECT setval(pg_get_serial_sequence('table_name', 'id'), MAX(id)) FROM table_name;")

例如将table_name替换为users。

ALTER SEQUENCE sequence_name RESTART WITH (SELECT max(id) FROM table_name); 是行不通的。

复制自@tardate答案:

SELECT setval(pg_get_serial_sequence('table_name', 'id'), MAX(id)) FROM table_name;
-- Login to psql and run the following

-- What is the result?
SELECT MAX(id) FROM your_table;

-- Then run...
-- This should be higher than the last result.
SELECT nextval('your_table_id_seq');

-- If it's not higher... run this set the sequence last to your highest id. 
-- (wise to run a quick pg_dump first...)

BEGIN;
-- protect against concurrent inserts while you update the counter
LOCK TABLE your_table IN EXCLUSIVE MODE;
-- Update the sequence
SELECT setval('your_table_id_seq', COALESCE((SELECT MAX(id)+1 FROM your_table), 1), false);
COMMIT;

来源- Ruby论坛