我有一个这样的数据结构:

var someObject = {
    'part1' : {
        'name': 'Part 1',
        'size': '20',
        'qty' : '50'
    },
    'part2' : {
        'name': 'Part 2',
        'size': '15',
        'qty' : '60'
    },
    'part3' : [
        {
            'name': 'Part 3A',
            'size': '10',
            'qty' : '20'
        }, {
            'name': 'Part 3B',
            'size': '5',
            'qty' : '20'
        }, {
            'name': 'Part 3C',
            'size': '7.5',
            'qty' : '20'
        }
    ]
};

我想使用这些变量访问数据:

var part1name = "part1.name";
var part2quantity = "part2.qty";
var part3name1 = "part3[0].name";

part1name应该用someObject.part1.name的值填充,即“Part 1”。part2quantity也是一样,它的容量是60。

有没有办法实现这与纯javascript或JQuery?


当前回答

在这里我提供了更多的方法,这些方法在很多方面看起来都更快:

选项1:Split string on。Or [Or] Or ' Or ",颠倒过来,跳过空项。

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var parts = path.split(/\[|\]|\.|'|"/g).reverse(), name; // (why reverse? because it's usually faster to pop off the end of an array)
    while (parts.length) { name=parts.pop(); if (name) origin=origin[name]; }
    return origin;
}

选项2(最快的,除了eval):低级字符扫描(没有regex/split/等等,只是一个快速字符扫描)。 注意:该命令不支持索引引用。

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var c = '', pc, i = 0, n = path.length, name = '';
    if (n) while (i<=n) ((c = path[i++]) == '.' || c == '[' || c == ']' || c == void 0) ? (name?(origin = origin[name], name = ''):(pc=='.'||pc=='['||pc==']'&&c==']'?i=n+2:void 0),pc=c) : name += c;
    if (i==n+2) throw "Invalid path: "+path;
    return origin;
} // (around 1,000,000+/- ops/sec)

选项3:(新:选项2扩展到支持引号-有点慢,但仍然很快)

function getValue(path, origin) {
    if (origin === void 0 || origin === null) origin = self ? self : this;
    if (typeof path !== 'string') path = '' + path;
    var c, pc, i = 0, n = path.length, name = '', q;
    while (i<=n)
        ((c = path[i++]) == '.' || c == '[' || c == ']' || c == "'" || c == '"' || c == void 0) ? (c==q&&path[i]==']'?q='':q?name+=c:name?(origin?origin=origin[name]:i=n+2,name='') : (pc=='['&&(c=='"'||c=="'")?q=c:pc=='.'||pc=='['||pc==']'&&c==']'||pc=='"'||pc=="'"?i=n+2:void 0), pc=c) : name += c;
    if (i==n+2 || name) throw "Invalid path: "+path;
    return origin;
}

JSPerf: http://jsperf.com/ways-to-dereference-a-delimited-property-string/3

"eval(...)" is still king though (performance wise that is). If you have property paths directly under your control, there shouldn't be any issues with using 'eval' (especially if speed is desired). If pulling property paths "over the wire" (on the line!? lol :P), then yes, use something else to be safe. Only an idiot would say to never use "eval" at all, as there ARE good reasons when to use it. Also, "It is used in Doug Crockford's JSON parser." If the input is safe, then no problems at all. Use the right tool for the right job, that's it.

其他回答

AngularJS有$scope.$eval

在AngularJS中,我们可以使用$scope。$eval方法访问嵌套对象:

$scope.someObject = someObject;
console.log( $scope.$eval("someObject.part3[0].name") ); //Part 3A

有关更多信息,请参见

AngularJS $scope API引用- $eval

演示

angular.module("app",[]) .run(function($rootScope) { $rootScope.someObject = { 'part2' : { 'name': 'Part 2', 'size': '15', 'qty' : '60' }, 'part3' : [{ 'name': 'Part 3A', 'size': '10', 'qty' : '20' },{ name: 'Part 3B' }] }; console.log( "part3[0].name =", $rootScope.$eval("someObject.part3[0].name") ); }) <script src="//unpkg.com/angular/angular.js"></script> <body ng-app="app" </body>

这里的解决方案仅用于访问深度嵌套的键。我需要一个来访问、添加、修改和删除密钥。这是我想到的:

var deepAccessObject = function(object, path_to_key, type_of_function, value){
    switch(type_of_function){
        //Add key/modify key
        case 0: 
            if(path_to_key.length === 1){
                if(value)
                    object[path_to_key[0]] = value;
                return object[path_to_key[0]];
            }else{
                if(object[path_to_key[0]])
                    return deepAccessObject(object[path_to_key[0]], path_to_key.slice(1), type_of_function, value);
                else
                    object[path_to_key[0]] = {};
            }
            break;
        //delete key
        case 1:
            if(path_to_key.length === 1){
                delete object[path_to_key[0]];
                return true;
            }else{
                if(object[path_to_key[0]])
                    return deepAccessObject(object[path_to_key[0]], path_to_key.slice(1), type_of_function, value);
                else
                    return false;
            }
            break;
        default:
            console.log("Wrong type of function");
    }
};

Path_to_key:数组中的路径。你可以用你的string_path.split(".")替换它。 Type_of_function: 0用于访问(不传递任何值给值),0用于添加和修改。1表示删除。

我已经看了所有其他的答案,决定在更可读的代码中添加改进:

function getObjectValByString(obj, str) {
if (typeof obj === "string") return obj;

const fields = str.split(".");

return getObjectValByString(obj[fields[0]], fields.slice(1).join("."));}

下面是一个代码片段:

let someObject = { 合作伙伴:{ id:“目标”, 人:{ 名称:“蚂蚁”, an:{名称:“ESM”}, }, }, }; 函数getObjectValByString(obj, str) { If (typeof obj === "string")返回obj; Const fields = str.split("."); 返回getObjectValByString(obj[fields[0]], fields.slice(1).join(".")); } const result = getObjectValByString(someObject, "partner.person.an.name"); console.log ({ 结果, });

也适用于对象内的数组/数组。 防御无效值。

/** * Retrieve nested item from object/array * @param {Object|Array} obj * @param {String} path dot separated * @param {*} def default value ( if result undefined ) * @returns {*} */ function path(obj, path, def){ var i, len; for(i = 0,path = path.split('.'), len = path.length; i < len; i++){ if(!obj || typeof obj !== 'object') return def; obj = obj[path[i]]; } if(obj === undefined) return def; return obj; } ////////////////////////// // TEST // ////////////////////////// var arr = [true, {'sp ace': true}, true] var obj = { 'sp ace': true, arr: arr, nested: {'dotted.str.ing': true}, arr3: arr } shouldThrow(`path(obj, "arr.0")`); shouldBeDefined(`path(obj, "arr[0]")`); shouldBeEqualToNumber(`path(obj, "arr.length")`, 3); shouldBeTrue(`path(obj, "sp ace")`); shouldBeEqualToString(`path(obj, "none.existed.prop", "fallback")`, "fallback"); shouldBeTrue(`path(obj, "nested['dotted.str.ing'])`); <script src="https://cdn.rawgit.com/coderek/e7b30bac7634a50ad8fd/raw/174b6634c8f57aa8aac0716c5b7b2a7098e03584/js-test.js"></script>

你必须自己解析字符串:

function getProperty(obj, prop) {
    var parts = prop.split('.');

    if (Array.isArray(parts)) {
        var last = parts.pop(),
        l = parts.length,
        i = 1,
        current = parts[0];

        while((obj = obj[current]) && i < l) {
            current = parts[i];
            i++;
        }

        if(obj) {
            return obj[last];
        }
    } else {
        throw 'parts is not valid array';
    }
}

这要求你也用点表示法定义数组下标:

var part3name1 = "part3.0.name";

它使解析更容易。

DEMO